Score for the test: 0 / 720

You didn't reach the minimum score

Wrong

Important Instructions

 
The clock is setup in upper right , it will display the remaining time for the test.
After the time up , the test will be close by self.
After submitting the test , you will redirected to the result page where you can analysis your performance , also you can go through the solution.

 

Wrong

Score: 0 / 4

 (Given that 1 L bar = 100 J)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

–30 J

radio_off.pngradio_off.png

5 kJ

radio_off.pngradio_off.png

25 J

radio_off.pngradio_off.png

30 J

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

C2A3

radio_off.pngradio_off.png

C3A2

radio_off.pngradio_on.png

C3A4

radio_off.pngradio_off.png

C4A3

Wrong

Score: 0 / 4

Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

0.5 × 10–15

radio_off.pngradio_off.png

0.25 × 10–10

radio_off.pngradio_off.png

0.125 × 10–15

radio_off.pngradio_off.png

0.5 × 10–10

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

10

radio_off.pngradio_off.png

20

radio_off.pngradio_on.png

30

radio_off.pngradio_off.png

40

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`Delta_"mix"`S = 0 at constant T and P

radio_off.pngradio_off.png

`Delta_"mix"``!=` 0 at constant T and P

radio_off.pngradio_on.png

`Delta_"mix"`H = 0 at constant T and P

radio_off.pngradio_off.png

`Delta_"mix"`G = 0 at constant T and P

Wrong

Score: 0 / 4

cell = 0.59 Vat 298 K, the equilibrium constant for the cell reaction is :

`["Given that" (2.303RT)/F=0.059" V at T = 298 K"]`

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

1.0 × 102

radio_off.pngradio_off.png

1.0 × 105

radio_off.pngradio_on.png

1.0 × 1010

radio_off.pngradio_off.png

1.0 × 1030

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Nitrous oxide

radio_off.pngradio_off.png

Methane

radio_off.pngradio_off.png

Ozone

radio_off.pngradio_on.png

Sulphur dioxide

Wrong

Score: 0 / 4

sigma (`sigma`) and pi (`pi`) bonds in pent-2-en-4-yne is

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

10 `sigma` bonds and 3 `pi` bonds

radio_off.pngradio_off.png

`sigma` bonds and 5 `pi` bonds

radio_off.pngradio_off.png

11 `sigma` bonds and 2 `pi` bonds

radio_off.pngradio_off.png

13 `sigma` bonds and no `pi` bonds

Wrong

Score: 0 / 4

`pi` bonds according to Molecular Orbital Theory?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

O2

radio_off.pngradio_off.png

N2

radio_off.pngradio_on.png

C2

radio_off.pngradio_off.png

Be2

Wrong

Score: 0 / 4

2Cu+ Cu2+ + Cu0

`3M"n"O_4^"2-" + 4H^+` `2M"n"O_4^"-" + M"n"O_2 + 2H_2O`

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

(a) and (b) only

radio_off.pngradio_off.png

(a), (b) and (c)

radio_off.pngradio_off.png

(a), (c) and (d)

radio_off.pngradio_off.png

(a) and (d) only

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Penicillin G

radio_off.pngradio_off.png

Ampicillin

radio_off.pngradio_off.png

Amoxycillin

radio_off.pngradio_off.png

Chloramphenicol

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

(CH3)2NH > CH3NH2 > (CH3)3N

radio_off.pngradio_off.png

(CH3)3N > CH3NH2 > (CH3)2NH

radio_off.pngradio_off.png

(CH3)3N > (CH3)2NH > CH3NH2

radio_off.pngradio_off.png

CH3NH2 > (CH3)2NH > (CH3)3N

Wrong

Score: 0 / 4

[Agl]l sol ?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

50 mL of 1 M AgNO3 + 50 mL of 1.5 M KI

radio_off.pngradio_on.png

50 mL of 1 M AgNO3 + 50 mL of 2 M KI

radio_off.pngradio_off.png

50 mL of 2 M AgNO3 + 50 mL of 1.5 M KI

radio_off.pngradio_off.png

50 mL of 0.1 M AgNO3 + 50 mL of 0.1 M KI

Wrong

Score: 0 / 4

 acids H2O and HF are :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

OH and H2F+, respectively

radio_off.pngradio_off.png

H3O+ and F, respectively

radio_off.pngradio_on.png

OH and F, respectively

radio_off.pngradio_off.png

H3O+ and H2F+, respectively

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

50 mL of 0.1 M NaOH + 25 mL of 0.1 MCH3COOH

radio_off.pngradio_off.png

100 mL of 0.1 M CH3COOH + 100 mL of 0.1 MNaOH

radio_off.pngradio_on.png

100 mL of 0.1 M HCl + 200 mL of 0.1 MNH4OH

radio_off.pngradio_off.png

100 mL of 0.1 M HCl + 100 mL of 0.1 MNaOH

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

radio_off.pngradio_on.png

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Na/liquid NH3

radio_off.pngradio_on.png

H2, Pd/C, quinoline

radio_off.pngradio_off.png

Zn/HCl

radio_off.pngradio_off.png

Hg2+/H+, H2O

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

[SiF6]2–

radio_off.pngradio_off.png

[GeCl6]2–

radio_off.pngradio_off.png

[Sn(OH)6]2–

radio_off.pngradio_on.png

[SiCl6]2–

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Sr(OH)2

radio_off.pngradio_off.png

Ca(OH)2

radio_off.pngradio_off.png

Mg(OH)2

radio_off.pngradio_on.png

Be(OH)2

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_on.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

The `pi`-bonding involves overlap of p-orbitals of oxygen with d-orbitals of manganese

radio_off.pngradio_off.png

There is no `pi`-bonding

radio_off.pngradio_off.png

The `pi`-bonding involves overlap of p-orbitals of oxygen with p-orbitals of manganese

radio_off.pngradio_off.png

The `pi`-bonding involves overlap of d-orbitals of oxygen with d-orbitals of manganese

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Li < Be < B < C < N < O < F < Ne

radio_off.pngradio_on.png

Li < B < Be < C < O < N < F < Ne

radio_off.pngradio_off.png

Li < B < Be < C < N < O < F < Ne

radio_off.pngradio_off.png

Li < Be < B < C < O < N < F < Ne

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

t = 0.693/k

radio_off.pngradio_off.png

t = 6.909/k

radio_off.pngradio_on.png

t = 4.606/k

radio_off.pngradio_off.png

t = 2.303/k

Wrong

Score: 0 / 4

PCl5 from the following:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Three equatorial P–Cl bonds make an angle of 120° with each other

radio_off.pngradio_off.png

Two axial P–Cl bonds make an angle of 180° with each other

radio_off.pngradio_off.png

Axial P–Cl bonds are longer than equatorial P–Cl bonds

radio_off.pngradio_on.png

PCl5 molecule is non-reactive

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

5f > 6p > 5p > 4d

radio_off.pngradio_off.png

6p > 5f > 5p > 4d

radio_off.pngradio_off.png

6p > 5f > 4d > 5p

radio_off.pngradio_off.png

5f > 6p > 4d > 5p

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Nylon-6,6

radio_off.pngradio_on.png

Nylon-2-Nylon 6

radio_off.pngradio_off.png

Nylon-6

radio_off.pngradio_off.png

Buna-S

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(i) (ii) (iii) (iv)

radio_off.pngradio_on.png

(ii) (iii) (iv) (i)

radio_off.pngradio_off.png

(ii) (iii) (i) (iv)

radio_off.pngradio_off.png

(iii) (iv) (i) (ii)

Wrong

Score: 0 / 4

H2E (E = O, S, Se, Te and Po)?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

H2S < H2O < H2Se < H2Te < H2Po

radio_off.pngradio_off.png

H2O < H2S < H2Se < H2Te < H2Po

radio_off.pngradio_on.png

H2Po < H2Te < H2Se < H2S < H2O

radio_off.pngradio_off.png

H2Se < H2Te < H2Po < H2O < H2S

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

O3 and Zn–H2O gives propanone and ethanal in equimolar ratio. Addition of HCl to alkene "A" gives "B" as the major product. The structure of product "B" is:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_off.png

radio_off.pngradio_on.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Be

radio_off.pngradio_on.png

Mg

radio_off.pngradio_off.png

Ca

radio_off.pngradio_off.png

Sr

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

CuFeS2

radio_off.pngradio_off.png

Cu(OH)2

radio_off.pngradio_off.png

Fe3O4

radio_off.pngradio_on.png

CuCO3.Cu(OH)2

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Lyman series

radio_off.pngradio_on.png

Balmer series

radio_off.pngradio_off.png

Paschen series

radio_off.pngradio_off.png

Brackett series

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Water + Nitric acid

radio_off.pngradio_off.png

Ethanol + Water

radio_off.pngradio_off.png

Acetone + Carbon disulphide

radio_off.pngradio_off.png

Heptane + Octane

Wrong

Score: 0 / 4

`2Fe^"3+" (aq)+2I^"-"(aq)-> 2Fe^"2+" (aq)+I_2 (aq)`

`E_"Cell"^Theta`=0.24 V at 298 K. The standard Gibbs

energy `(Delta_rG^Theta)` of the cell reaction is :

[Given that Faraday constant F = 96500 C mol-1]

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

– 46.32 kJ mol–1

radio_off.pngradio_off.png

– 23.16 kJ mol–1

radio_off.pngradio_off.png

46.32 kJ mol–1

radio_off.pngradio_off.png

23.16 kJ mol–1

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Evaporation of water

radio_off.pngradio_off.png

Expansion of a gas at constant temperature

radio_off.pngradio_off.png

Sublimation of solid to gas

radio_off.pngradio_on.png

2H(g) `->` H2(g)

Wrong

Score: 0 / 4

(a) Pure nitrogen                              (i) Chlorine
(b) Haber process                             (ii) Sulphuric acid
(c) Contact process                          (iii) Ammonia
(d) Deacon’s process                        (iv) Sodium azide or Barium azide

Which of the following is the correct option?
(a)     (b)     (c)      (d)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(i) (ii) (iii) (iv)

radio_off.pngradio_off.png

(ii) (iv) (i) (iii)

radio_off.pngradio_off.png

(iii) (iv) (ii) (i)

radio_off.pngradio_on.png

(iv) (iii) (ii) (i)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

PbF4 is covalent in nature

radio_off.pngradio_off.png

SiCl4 is easily hydrolysed

radio_off.pngradio_off.png

GeX4(X = F, Cl, Br, I) is more stable than GeX2

radio_off.pngradio_off.png

SnF4 is ionic in nature

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Valine

radio_off.pngradio_off.png

Leucine

radio_off.pngradio_on.png

Alanine

radio_off.pngradio_off.png

Lysine

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Z > 1 and attractive forces are dominant

radio_off.pngradio_off.png

Z > 1 and repulsive forces are dominant

radio_off.pngradio_on.png

Z < 1 and attractive forces are dominant

radio_off.pngradio_off.png

Z < 1 and repulsive forces are dominant

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_on.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_on.png

radio_off.pngradio_off.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

`N_2(g)+3H_2(g)``2NH_3(g)`

The correct option is:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`-1/3("d"[H_2])/("dt")=-(1)/(2)("d"[NH_3])/("dt")`

radio_off.pngradio_off.png

`-("d"[N_2])/("dt")=2("d"[NH_3])/("dt")`

radio_off.pngradio_on.png

`-("d"[N_2])/("dt")=(1)/(2)("d"[NH_3])/("dt")`

radio_off.pngradio_off.png

`3("d"[H_2])/("dt")=2("d"[NH_3])/("dt")`

Wrong

Score: 0 / 4

K4 [Fe(CN)6] based on crystal field theory?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`t_"2g"^4e_"g"^2`

radio_off.pngradio_on.png

`t_"2g"^6e_"g"^0`

radio_off.pngradio_off.png

`e^3t_"2"^3`

radio_off.pngradio_off.png

`e^4t_"2"^2`

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Calgon's method

radio_off.pngradio_on.png

Clark's method

radio_off.pngradio_off.png

Ion-exchange method

radio_off.pngradio_off.png

Synthetic resins method

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Isothermal

radio_off.pngradio_on.png

Adiabatic

radio_off.pngradio_off.png

Isobaric

radio_off.pngradio_off.png

Isochoric

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Increase in its mass

radio_off.pngradio_on.png

Increase in its kinetic energy

radio_off.pngradio_off.png

Decrease in its pressure

radio_off.pngradio_off.png

Decrease in intermolecular distance

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

–3.4 eV, –3.4 eV

radio_off.pngradio_off.png

–3.4 eV, –6.8 eV

radio_off.pngradio_on.png

3.4 eV, –6.8 eV

radio_off.pngradio_off.png

3.4 eV, 3.4 eV

Wrong

Score: 0 / 4

The correct Boolean operation represented by the circuit diagram drawn is :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

AND

radio_off.pngradio_off.png

OR

radio_off.pngradio_on.png

NAND

radio_off.pngradio_off.png

NOR

Wrong

Score: 0 / 4

(g 10 m/s2)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`sqrt(10) " rad/s"`

radio_off.pngradio_off.png

`10/(2pi)" rad/s"`

radio_off.pngradio_on.png

10 rad/s

radio_off.pngradio_off.png

`10pi " rad/s"`

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`1/9`

radio_off.pngradio_on.png

`8/9`

radio_off.pngradio_off.png

`4/9`

radio_off.pngradio_off.png

`5/9`

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

30° west

radio_off.pngradio_off.png

radio_off.pngradio_off.png

60° west

radio_off.pngradio_off.png

45° west

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

The mass is at the highest point

radio_off.pngradio_off.png

The wire is horizontal

radio_off.pngradio_on.png

The mass is at the lowest point

radio_off.pngradio_off.png

Inclined at an angle of 60° from vertical

Wrong

Score: 0 / 4

y = A0 + Asin`w`t + Bcos`w`t

Then the amplitude of its oscillation is given by :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`A_0+sqrt(A^2+B^2)`

radio_off.pngradio_on.png

`sqrt(A^2+B^2)`

radio_off.pngradio_off.png

`sqrt(A_0^2+(A^2+B^2))`

radio_off.pngradio_off.png

A+B

Wrong

Score: 0 / 4

m2 is kept perpendicular to a magnetic field 5 × 10–5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

2 V

radio_off.pngradio_off.png

0.2 V

radio_off.pngradio_off.png

2 × 10–3 V

radio_off.pngradio_on.png

0.02 V

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`(Aw)/2`

radio_off.pngradio_off.png

`Aw`

radio_off.pngradio_off.png

`(Aw^2)/2`

radio_off.pngradio_on.png

Zero

Wrong

Score: 0 / 4

of 2.5 × 10–2 N/m. The pressure inside the bubble equals at a point Z0 below the free surface of water in a container. Taking g = 10 m/s2, density of water = 103 kg/m3, the value of Z0 is :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

100 cm

radio_off.pngradio_off.png

10 cm

radio_off.pngradio_on.png

1 cm

radio_off.pngradio_off.png

0.5 cm

Wrong

Score: 0 / 4

(`alpha_"cu"``alpha_"cu"` = 1.7 × 10–5 K–1 and `alpha_"AI"``alpha_"AI"` = 2.2 × 10–5 K–1)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

6.8 cm

radio_off.pngradio_off.png

113.9 cm

radio_off.pngradio_off.png

88 cm

radio_off.pngradio_on.png

68 cm

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

J m K–1

radio_off.pngradio_off.png

J m–1 K–1

radio_off.pngradio_off.png

W m K–1

radio_off.pngradio_on.png

W m–1 K–1

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Mgl

radio_off.pngradio_off.png

MgL

radio_off.pngradio_on.png

`1/2Mgl `

radio_off.pngradio_off.png

`1/2MgL`

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

3 J

radio_off.pngradio_off.png

30 kJ

radio_off.pngradio_off.png

2 J

radio_off.pngradio_off.png

1 J

Wrong

Score: 0 / 4

`X=(A^2B^"1/2")/(C^"1/3"D^3)` will be

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`(3/13)%`

radio_off.pngradio_on.png

16%

radio_off.pngradio_off.png

-10%

radio_off.pngradio_off.png

10%

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

150 N

radio_off.pngradio_off.png

200 N

radio_off.pngradio_off.png

250 N

radio_off.pngradio_on.png

100 N

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Red

radio_off.pngradio_off.png

Blue

radio_off.pngradio_off.png

Green

radio_off.pngradio_off.png

Violet

Wrong

Score: 0 / 4

 after 2`pi` revolutions is

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

× 10–6 N m

radio_off.pngradio_off.png

2 × 10–3 N m

radio_off.pngradio_off.png

12 × 10–4 N m

radio_off.pngradio_off.png

2 × 106 N m

Wrong

Score: 0 / 4

y - projection of the radius vector of rotating particle P is :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

y(t) = –3 cos2`pi`t, where y in m

radio_off.pngradio_off.png

y(t) 4sin`((pi"t")/(2)),`where y in m

radio_off.pngradio_off.png

y(t) 3cos`((3pi"t")/(2)),`where y in m

radio_off.pngradio_on.png

y(t) 3cos`((pi"t")/(2)),`where y in m

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Increases as r increases for r < R and for r > R

radio_off.pngradio_on.png

Zero as r increases for r < R, decreases as r increases for r > R

radio_off.pngradio_off.png

Zero as r increases for r < R, increases as r increases for r > R

radio_off.pngradio_off.png

Decreases as r increases for r < R and for r > R

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Induction furnace

radio_off.pngradio_off.png

Magnetic braking in train

radio_off.pngradio_off.png

Electromagnet

radio_off.pngradio_on.png

Electric heater

Wrong

Score: 0 / 4

The ratio of power consumption by the bulbs when (i) all are glowing and (ii) in the situation when two from section A and one from section B are glowing, will be :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

4 : 9

radio_off.pngradio_on.png

9 : 4

radio_off.pngradio_off.png

1 : 2

radio_off.pngradio_off.png

2 : 1

Wrong

Score: 0 / 4

`delta` = +25°. At a point B on the earth’s surface the angle of dip, `delta` = –25°. We can interpret that:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

A and B are both located in the northern hemisphere.

radio_off.pngradio_off.png

A is located in the southern hemisphere and B is located in the northern hemisphere.

radio_off.pngradio_on.png

A is located in the northern hemisphere and B is located in the southern hemisphere.

radio_off.pngradio_off.png

A and B are both located in the southern hemisphere.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

30 J

radio_off.pngradio_off.png

5 J

radio_off.pngradio_on.png

25 J

radio_off.pngradio_off.png

20 J

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

When the light rays undergo two internal reflections in a water drop, a secondary rainbow is formed

radio_off.pngradio_off.png

The order of colours is reversed in the secondary rainbow

radio_off.pngradio_on.png

An observer can see a rainbow when his front is towards the sun

radio_off.pngradio_off.png

Rainbow is a combined effect of dispersion refraction and reflection of sunlight

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

radio_off.pngradio_off.png

radio_off.pngradio_on.png

radio_off.pngradio_off.png

Wrong

Score: 0 / 4

radii rA and rB with speed vA and vB respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

rA : rB

radio_off.pngradio_off.png

vA : vB

radio_off.pngradio_off.png

rB : rA

radio_off.pngradio_on.png

1 : 1

Wrong

Score: 0 / 4

F1. When the space between the two lenses is filled with glycerine (which has the same refractive index (`mu` = 1.5) as that of glass) then the equivalent focal length is F2. The ratio F1 : F2 will be :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

2 : 1

radio_off.pngradio_on.png

1 : 2

radio_off.pngradio_off.png

2 : 3

radio_off.pngradio_off.png

3 : 4

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

180°

radio_off.pngradio_off.png

radio_off.pngradio_off.png

Equal to angle of incidence

radio_off.pngradio_on.png

90°

Wrong

Score: 0 / 4

+`lambda`C/m and –`lambda` C/m are placed at a distance of 2R in free space. What is the electric field mid-way between the two line charges?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Zero

radio_off.pngradio_off.png

`(2lambda)/(piepsi_0R`N/C

radio_off.pngradio_on.png

`(lambda)/(piepsi_0R`N/C

radio_off.pngradio_off.png

`(lambda)/(2piepsi_0R` N/C

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Electrons are the majority carriers and trivalent atoms are the dopants.

radio_off.pngradio_on.png

Holes are the majority carriers and trivalent atoms are the dopants.

radio_off.pngradio_off.png

Holes are the majority carriers and pentavalent atoms are the dopants.

radio_off.pngradio_off.png

Electrons are the majority carriers and pentavalent atoms are the dopants.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Conductor

radio_off.pngradio_off.png

Inductor

radio_off.pngradio_off.png

Switch

radio_off.pngradio_on.png

Fuse

Wrong

Score: 0 / 4

`mu`F is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Zero, 60 `mu`A

radio_off.pngradio_on.png

60 `mu`A, 60 `mu`A

radio_off.pngradio_off.png

60 `mu`A, zero

radio_off.pngradio_off.png

Zero, zero

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

V2 > V1 and i1 = i2

radio_off.pngradio_off.png

V1 = V2 and i1 > i2

radio_off.pngradio_on.png

V1 = V2 and i1 = i2

radio_off.pngradio_off.png

V2 > Vv and i1 > i2

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

2 protons and 2 neutrons only

radio_off.pngradio_off.png

2 electrons, 2 protons and 2 neutrons

radio_off.pngradio_off.png

2 electrons and 4 protons only

radio_off.pngradio_off.png

2 protons only

Wrong

Score: 0 / 4

(me = 9 × 10–31 kg)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

12.2 × 10–13 m

radio_off.pngradio_on.png

12.2 × 10–12 m

radio_off.pngradio_off.png

12.2 × 10–14 m

radio_off.pngradio_off.png

12.2 nm

Wrong

Score: 0 / 4

it can travel x2 distance. Then x1 : x2 will be:

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

`1:sqrt2`

radio_off.pngradio_off.png

`sqrt2:1`

radio_off.pngradio_on.png

`1:sqrt3`

radio_off.pngradio_off.png

`1:2sqrt3`

Wrong

Score: 0 / 4

2 mm2 is present near the bottom of a fully filled open tank of height 2 m. Taking g = 10 m/s2, the rate of flow of water through the open hole would be nearly

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

12.6 × 10–6 m3/s

radio_off.pngradio_off.png

8.9 × 10–6 m3/s

radio_off.pngradio_off.png

2.23 × 10–6 m3/s

radio_off.pngradio_off.png

6.4 × 10–6 m3/s

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

F

radio_off.pngradio_on.png

`(9F)/16`

radio_off.pngradio_off.png

`(16F)/9`

radio_off.pngradio_off.png

`(4F)/3`

Wrong

Score: 0 / 4

 rH : r`alpha` will be :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

2 : 1

radio_off.pngradio_off.png

1 : 2

radio_off.pngradio_off.png

4 : 1

radio_off.pngradio_off.png

1 : 4

Wrong

Score: 0 / 4

`vecV` is acted by three forces shown by the vector triangle PQR. The velocity of the particle will :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Increase

radio_off.pngradio_off.png

Decrease

radio_off.pngradio_on.png

Remain constant

radio_off.pngradio_off.png

Change according to the smallest force `vec"QR"`

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

mgR

radio_off.pngradio_off.png

2mgR

radio_off.pngradio_on.png

`1/2"mgR"`

radio_off.pngradio_off.png

`3/2"mgR"`

Wrong

Score: 0 / 4

(`mu_"water"` = 4/3)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

0.266°

radio_off.pngradio_on.png

0.15°

radio_off.pngradio_off.png

0.05°

radio_off.pngradio_off.png

0.1°

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Viroids lack a protein coat.

radio_off.pngradio_off.png

Viruses are obligate parasites.

radio_off.pngradio_on.png

Infective constituent in viruses is the protein coat.

radio_off.pngradio_off.png

Prions consist of abnormally folded proteins.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Adenine and thymine

radio_off.pngradio_on.png

Adenine and guanine

radio_off.pngradio_off.png

Guanine and cytosine

radio_off.pngradio_off.png

Cytosine and thymine

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

GLUT I

radio_off.pngradio_off.png

GLUT II

radio_off.pngradio_off.png

GLUT III

radio_off.pngradio_on.png

GLUT IV

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Chief Cells

radio_off.pngradio_on.png

Goblet Cells

radio_off.pngradio_off.png

Oxyntic Cells

radio_off.pngradio_off.png

Duodenal Cells

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

BOD incubator

radio_off.pngradio_off.png

Sludge digester

radio_off.pngradio_off.png

Industrial oven

radio_off.pngradio_on.png

Bioreactor

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

It is Vitamin A enriched, with a gene from daffodil

radio_off.pngradio_off.png

It is pest resistant, with a gene from Bacillus thuringiensis

radio_off.pngradio_off.png

It is drought tolerant, developed using Agrobacterium vector

radio_off.pngradio_off.png

It has yellow grains, because of a gene introduced from a primitive variety of rice

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Biosphere Reserve

radio_off.pngradio_off.png

Wildlife Sanctuary

radio_off.pngradio_on.png

Botanical Garden

radio_off.pngradio_off.png

Sacred Grove

Wrong

Score: 0 / 4

5'AACAGCGGUGCUAUU3'

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Insertion of G at 5th position

radio_off.pngradio_off.png

Deletion of G from 5th position

radio_off.pngradio_off.png

Insertion of A and G at 4th and 5th positions respectively

radio_off.pngradio_on.png

Deletion of GGU from 7th, 8th and 9th positions

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Shoot the waste into space

radio_off.pngradio_off.png

Bury the waste under Antarctic ice-cover

radio_off.pngradio_off.png

Dump the waste within rocks under deep ocean

radio_off.pngradio_on.png

Bury the waste within rocks deep below the Earth's surface

Wrong

Score: 0 / 4

(a) Lactobacillus                          (i) Cheese
(b) Saccharomyces                     (ii) Curd cerevisiae
(c) Aspergillus niger                    (iii) Citric Acid
(d) Acetobacter aceti                   (iv) Bread
                                                    (v) Acetic Acid
Select the correct option.
(a)             (b)              (c)              (d)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(ii) (iv) (v) (iii)

radio_off.pngradio_on.png

(ii) (iv) (iii) (v)

radio_off.pngradio_off.png

(iii) (iv) (v) (i)

radio_off.pngradio_off.png

(ii) (i) (iii) (v)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

A unit of distance between two expressed genes representing 10% cross over.

radio_off.pngradio_off.png

A unit of distance between two expressed genes representing 100% cross over.

radio_off.pngradio_on.png

A unit of distance between genes on chromosomes, representing 1% cross over.

radio_off.pngradio_off.png

A unit of distance between genes on chromosomes, representing 50% cross over.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Vaults, LNG-20

radio_off.pngradio_off.png

Multiload 375, Progestasert

radio_off.pngradio_on.png

Progestasert, LNG-20

radio_off.pngradio_off.png

Lippes Loop, Multiload 375

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Trichoderma

radio_off.pngradio_off.png

Chlorella

radio_off.pngradio_off.png

Anabaena

radio_off.pngradio_off.png

Lactobacillus

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Genes expressed as RNA

radio_off.pngradio_off.png

Polypeptide expression

radio_off.pngradio_off.png

DNA polymorphism

radio_off.pngradio_off.png

Novel DNA sequences

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Natural killer cells

radio_off.pngradio_off.png

Monocytes

radio_off.pngradio_off.png

Macrophages

radio_off.pngradio_on.png

Immunoglobulin A

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Inbreeding increases homozygosity

radio_off.pngradio_off.png

Inbreeding is essential to evolve purelines in any animal.

radio_off.pngradio_on.png

Inbreeding selects harmful recessive genes that reduce fertility and productivity

radio_off.pngradio_off.png

Inbreeding helps in accumulation of superior genes and elimination of undesirable genes

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Testis `->` Epididymis `->` Vasa efferentia `->` Rete testis `->` Inguinal canal `->` Urethra

radio_off.pngradio_on.png

Seminiferous tubules `->` Rete testis `->` Vasa efferentia `->` Epididymis `->` Vas deferens v Ejaculatory duct `->` Urethra `->` Urethral meatus

radio_off.pngradio_off.png

Seminiferous tubules `->` Vasa efferentia `->` Epididymis `->` Inguinal canal `->` Urethra

radio_off.pngradio_off.png

Testis `->` Epididymis `->` Vasa efferentia `->` Vas deferens `->` Ejaculatory duct `->` Inguinal canal `->` Urethra `->` Urethral meatus

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

0.36(AA); 0.48(Aa); 0.16(aa)

radio_off.pngradio_off.png

0.16(AA); 0.24(Aa); 0.36(aa)

radio_off.pngradio_on.png

0.16(AA); 0.48(Aa); 0.36(aa)

radio_off.pngradio_off.png

0.16(AA); 0.36(Aa); 0.48(aa)

Wrong

Score: 0 / 4

(a) Pila                                          (i) Flame cells
(b) Bombyx                                    (ii) Comb plates
(c) Pleurobrachia                          (iii) Radula
(d) Taenia                                     (iv) Malpighian tubules
Select the correct option from the following :
(a)        (b)         (c)        (d)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(iii) (ii) (i) (iv)

radio_off.pngradio_on.png

(iii) (iv) (ii) (i)

radio_off.pngradio_off.png

(ii) (iv) (iii) (i)

radio_off.pngradio_off.png

(iii) (ii) (iv) (i)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

s-arm and l-arm respectively

radio_off.pngradio_on.png

p-arm and q-arm respectively

radio_off.pngradio_off.png

q-arm and p-arm respectively

radio_off.pngradio_off.png

m-arm and n-arm respectively

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Lateral buds

radio_off.pngradio_off.png

Pulvinus

radio_off.pngradio_off.png

Shoot apex

radio_off.pngradio_on.png

Leaves

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Cerebrum

radio_off.pngradio_on.png

Hypothalamus

radio_off.pngradio_off.png

Corpus callosum

radio_off.pngradio_off.png

Medulla oblongata

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Mitochondria and Lysosomes

radio_off.pngradio_off.png

Chloroplast and Vacuoles

radio_off.pngradio_on.png

Lysosomes and Vacuoles

radio_off.pngradio_off.png

Nuclear envelope and Mitochondria

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Turner's syndrome

radio_off.pngradio_on.png

Klinefelter's syndrome

radio_off.pngradio_off.png

Edward syndrome

radio_off.pngradio_off.png

Down's syndrome

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Water only

radio_off.pngradio_off.png

Water and mineral salts only

radio_off.pngradio_off.png

Water, mineral salts and some organic nitrogen only

radio_off.pngradio_on.png

Water, mineral salts, some organic nitrogen and hormones

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Ozone and Ammonia

radio_off.pngradio_off.png

Oxygen and Nitrogen

radio_off.pngradio_off.png

Nitrogen and Sulphur dioxide

radio_off.pngradio_on.png

Carbon dioxide and Methane

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Montreal Protocol

radio_off.pngradio_off.png

Kyoto Protocol

radio_off.pngradio_off.png

Gothenburg Protocol

radio_off.pngradio_off.png

Geneva Protocol

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Autogamy

radio_off.pngradio_off.png

Parthenocarpy

radio_off.pngradio_off.png

Syngamy

radio_off.pngradio_on.png

Parthenogenesis

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Gonorrhoea

radio_off.pngradio_off.png

Genital warts

radio_off.pngradio_on.png

Genital herpes

radio_off.pngradio_off.png

Chlamydiasis

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Auto-immune response

radio_off.pngradio_off.png

Humoral immune response

radio_off.pngradio_off.png

Inflammatory immune response

radio_off.pngradio_on.png

Cell-mediated immune response

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Low levels of antidiuretic hormone

radio_off.pngradio_on.png

Maintaining hyperosmolarity towards inner medullary interstitium in the kidneys.

radio_off.pngradio_off.png

Secretion of erythropoietin by Juxtaglomerular complex

radio_off.pngradio_off.png

Hydrostatic pressure during glomerular filtration

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Genetic code is not ambiguous

radio_off.pngradio_off.png

Genetic code is redundant

radio_off.pngradio_on.png

Genetic code is nearly universal

radio_off.pngradio_off.png

Genetic code is specific

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Lysosomes have numerous hydrolytic enzymes

radio_off.pngradio_off.png

The hydrolytic enzymes of lysosomes are active under acidic pH

radio_off.pngradio_off.png

Lysosomes are membrane bound structures

radio_off.pngradio_on.png

Lysosomes are formed by the process of packaging in the endoplasmic reticulum

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Rudolf Virchow

radio_off.pngradio_off.png

Theodor Schwann

radio_off.pngradio_off.png

Schleiden

radio_off.pngradio_off.png

Aristotle

Wrong

Score: 0 / 4

(a) Nitrogenous waste build-up in the body
(b) Non-elimination of excess potassium ions
(c) Reduced absorption of calcium ions from gastro-intestinal tract
(d) Reduced RBC production

Which of the following options is the most appropriate?

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(a) and (b) are correct

radio_off.pngradio_off.png

(b) and (c) are correct

radio_off.pngradio_on.png

(c) and (d) are correct

radio_off.pngradio_off.png

a) and (d) are correct

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Non-multidirectional

radio_off.pngradio_off.png

Upward

radio_off.pngradio_off.png

Downward

radio_off.pngradio_on.png

Bi-directional

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Tetany

radio_off.pngradio_on.png

Muscular dystrophy

radio_off.pngradio_off.png

Myasthenia gravis

radio_off.pngradio_off.png

Botulism

Wrong

Score: 0 / 4

(a) Organ system level of organisation
(b) Bilateral symmetry
(c) True coelomates with segmentation of body


Select the correct option of animal groups which possess all the above characteristics

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Annelida, Arthropoda and Chordata

radio_off.pngradio_off.png

Annelida, Arthropoda and Mollusca

radio_off.pngradio_off.png

Arthropoda, Mollusca and Chordata

radio_off.pngradio_off.png

Annelida, Mollusca and Chordata

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

T.H. Morgan

radio_off.pngradio_off.png

Gregor J. Mendel

radio_off.pngradio_on.png

Alfred Sturtevant

radio_off.pngradio_off.png

Sutton Boveri

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

The enzyme cuts DNA molecule at identified position within the DNA.

radio_off.pngradio_on.png

The enzyme binds DNA at specific sites and cuts only one of the two strands.

radio_off.pngradio_off.png

The enzyme cuts the sugar-phosphate backbone at specific sites on each strand.

radio_off.pngradio_off.png

The enzyme recognizes a specific palindromic nucleotide sequence in the DNA.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Morels and truffles are edible delicacies.

radio_off.pngradio_off.png

Claviceps is a source of many alkaloids and LSD.

radio_off.pngradio_off.png

Conidia are produced exogenously and ascospores endogenously.

radio_off.pngradio_on.png

Yeasts have filamentous bodies with long thread-like hyphae.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Basal

radio_off.pngradio_off.png

Axile

radio_off.pngradio_on.png

Parietal

radio_off.pngradio_off.png

Free central

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_on.png

Habitat loss and fragmentation

radio_off.pngradio_off.png

Drought and floods

radio_off.pngradio_off.png

Economic exploitation

radio_off.pngradio_off.png

Alien species invasion

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

random and directional

radio_off.pngradio_on.png

random and directionless

radio_off.pngradio_off.png

small and directional

radio_off.pngradio_off.png

small and directionless

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

0.9

radio_off.pngradio_on.png

0.7

radio_off.pngradio_off.png

0.07

radio_off.pngradio_off.png

0.09

Wrong

Score: 0 / 4

F1 generation pink flowers were obtained. When pink flowers were selfed, the F2 generation showed white, red and pink flowers. Choose the incorrect statement from the following :

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

This experiment does not follow the Principle of Dominance.

radio_off.pngradio_off.png

Pink colour in F1 is due to incomplete dominance.

radio_off.pngradio_off.png

Ratio of F2 is `1/2` (Red) : `2/4` (Pink) : `1/4` (White)

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Law of Segregation does not apply in this experiment

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Male fruit fly is heterogametic

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In male grasshoppers 50% of sperms have no sex-chromosome

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In domesticated fowls, sex of progeny depends on the type of sperm rather than egg

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Human males have one of their sexchromosome much shorter than the other

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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M `->` G1 `->` G2 `->` S

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G1 `->` G2 `->` S `->` M

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S `->` G1 `->` G2 `->` M

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G1 `->` S `->` G2 `->` M

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Nitrogen fixation

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Chemoautotrophic fixation

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Nitrification

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Denitrification

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Making plastic sacks

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Use as a fertilizer

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Construction of roads

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Making tubes and pipes

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Liverworts

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Mosses

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Pteridophytes

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Gymnosperms

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Lactational amenorrhea, Pills Emergency contraceptives.

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Barrier method, Lactational amenorrhea, Pills.

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CuT, Pills, Emergency contraceptives.

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Pills, Emergency contraceptives, Barrier methods.

Wrong

Score: 0 / 4

(a) Insulin                                 (i) Addison's disease
(b) Thyroxin                             (ii) Diabetes insipidus
(c) Corticoids                           (iii) Acromegaly
(d) Growth Hormone                (iv) Goitre
                                                (v) Diabetes mellitus
Select the correct option.
(a)          (b)            (c)             (d)

Your choiceExpected choiceAnswerComment
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(v) (i) (ii) (iii)

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(ii) (iv) (iii) (i)

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(v) (iv) (i) (iii)

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(ii) (iv) (i) (iii)

Wrong

Score: 0 / 4

(a) Crypts of Lieberkuhn                    (i) Pancreas
(b) Glisson's Capsule                        (ii) Duodenum
(c) Islets of Langerhans                    (iii) Small intestine
(d) Brunner's Glands                        (iv) Liver
Select the correct option from the following
(a)       (b)       (c)         (d)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(iii) (i) (ii) (iv)

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(ii) (iv) (i) (iii)

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(iii) (iv) (i) (ii)

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(iii) (ii) (i) (iv)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Closure of stomata

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Flaccidity of bulliform cells

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Shrinkage of air spaces in spongy mesophy ll

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Tyloses in vessels

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Isopropanol

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Chilled ethanol

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Methanol at room temperature

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Chilled chloroform

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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to reduce CO2 emissions and global warming

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for conservation of biodiversity and sustainable utilization of its benefits

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to assess threat posed to native species by invasive weed species

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for immediate steps to discontinue use of CFCs that were damaging the ozone layer

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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its embryo is immature.

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it has obligate association with mycorrhizae.

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it has very hard seed coat.

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its seeds contain inhibitors that present germination.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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after entry of sperm but before fertilization

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after fertilization

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before entry of sperm into ovum

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simultaneously with first cleavage

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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an alkaloid

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an essential oil

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a lectin

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a pigment

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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8th, 9th and 10th pairs of ribs articulate directly with the sternum.

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11th and 12th pairs of ribs are connected to the sternum with the help of hyaline cartilage.

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Each rib is a flat thin bone and all the ribs are connected dorsally to the thoracic vertebrae and ventrally to the sternum.

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There are seven pairs of vertebrosternal, three pairs of vertebrochondral and two pairs of vertebral ribs.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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methylation of morphine

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acetylation of morphine

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glycosylation of morphine

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nitration of morphine

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Directional Selection

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Stabilizing Selection

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Disruptive Selection

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Cyclical Selection

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Aldolase

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Hexokinase

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Enolase

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Phosphofructokinase

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Cornea is an external, transparent and protective proteinacious covering of the eye-ball.

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Cornea consists of dense connective tissue of elastin and can repair itself.

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Cornea is convex, transparent layer which is highly vascularised.

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Cornea consists of dense matrix of collagen and is the most sensitive portion the eye.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Pyramid of numbers in grassland

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Pyramid of energy

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Pyramid of biomass in a forest

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Pyramid of biomass in a sea

Wrong

Score: 0 / 4

(A) Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group.
(B) A complete catalytic active enzyme with its bound prosthetic group is called apoenzyme.
Select the correct option.

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Both (A) and (B) are true.

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(A) is true but (B) is false.

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Both (A) and (B) are false.

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(A) is false but (B) is true.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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benign growth on mucous lining of nasal cavity

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inflammation of bronchi and bronchioles

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proliferation of fibrous tissues and damage of the alveolar walls

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reduction in the secretion of surfactants by pneumocytes.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Ovary develops into fruit

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Zygote develops into embryo

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Central cell develops into endosperm

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Ovules develop into embryo sac

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Albuminous cells and sieve cells

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Sieve tubes only

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Companion cells only

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Both sieve tubes and companion cells

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Auxin and Ethylene

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Gibberellin and Cytokinin

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Gibberellin and Abscisic acid

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Cytokinin and Abscisic acid

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Chalaza

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Perisperm

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Hilum

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Tegmen

Wrong

Score: 0 / 4

G0 phase :

Your choiceExpected choiceAnswerComment
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exit the cell cycle

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enter the cell cycle

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suspend the cell cycle

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terminate the cell cycle

Wrong

Score: 0 / 4

Column - I                                      Column - II
(a) Saprophyte                     (i) Symbiotic association of fungi with plant roots
(b) Parasite                          (ii) Decomposition of dead organic materials
(c) Lichens                           (iii)Living on living plants or animals
(d) Mycorrhiza                      (iv) Symbiotic association of algae and fungi
Choose the correct answer from the option given below
(a)            (b)           (c)           (d)

Your choiceExpected choiceAnswerComment
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(i) (ii) (iii) (iv)

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(iii) (ii) (i) (iv)

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(ii) (i) (iii) (iv)

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(ii) (iii) (iv) (i)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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50 beats per minute

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75 beats per minute

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100 beats per minute

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125 beats per minute

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Body temperature

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Moist surface of midgut

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Alkaline pH of gut

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Acidic pH of stomach

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Bile duct and Bronchioles

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Fallopian tubes and Pancreatic duct

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Eustachian tube and Salivary duct

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Bronchioles and Fallopian tubes

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

Annual ring is a combination of spring wood and autumn wood produced in a year

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Differential activity of cambium causes light and dark bands of tissue early and late wood respectively.

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Activity of cambium depends upon variation in climate.

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Annual rings are not prominent in trees of temperate region.

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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One fuses with egg other(s) degenerate(s) in the synergid.

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All fuse with the egg.

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One fuses with the egg, other(s) fuse(s) with synergid nucleus.

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One fuses with the egg and other fuses with central cell nuclei.

Wrong

Score: 0 / 4

(a) i gene                              (i) `beta`-galactosidase
(b) z gene                             (ii) Permease
(c) a gene                             (iii) Repressor
(d) y gene                             (iv) Transacetylase
Select the correct option.
(a)      (b)       (c)      (d)

Your choiceExpected choiceAnswerComment
radio_off.pngradio_off.png

(i) (iii) (ii) (iv)

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(iii) (i) (ii) (iv)

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(iii) (i) (iv) (ii)

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(iii) (iv) (i) (ii)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Pharynx `->` Oesophagus `->` Crop `->` Gizzard`->` Ileum `->` Colon `->` Rectum

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Pharynx `->` Oesophagus `->` Gizzard `->` Crop`->` Ileum `->` Colon `->` Rectum

radio_off.pngradio_off.png

Pharynx `->` Oesophagus `->` Gizzard `->`Ileum `->` Crop  Colon `->` Rectum

radio_off.pngradio_off.png

Pharynx `->` Oesophagus `->` Ileum `->` Crop`->` Gizzard `->` Colon `->` Rectum

Wrong

Score: 0 / 4

(a) Homo habilis                           (i) 900 cc
(b) Homo neanderthalensis          (ii) 1350 cc
(c) Homo erectus                         (iii) 650-800 cc
(d) Homo sapiens                         (iv) 1400 cc
Select the correct option.
(a)     (b)       (c)        (d)

Your choiceExpected choiceAnswerComment
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(iii) (i) (iv) (ii)

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(iii) (ii) (i) (iv)

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(iii) (iv) (i) (ii)

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(iv) (iii) (i) (ii)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Plasmodium vivax / UTI test

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Streptococcus pneumoniae / Widal test

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Salmonella typhi / Anthrone test

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Salmonella typhi / Widal test

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Changing the permeability of the cell membrane

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Binding to DNA and forming a genehormone complex

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Activating cyclic AMP located on the cell membrane

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Using aquaporin channels as second messenger

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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1500 mL

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1700 mL

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2200 mL

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2700 mL

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Cyclosporin A

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Statin

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Streptokinase

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Lipases

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Outer membrane is permeable to monomers of carbohydrates, fats and proteins.

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Enzymes of electron transport are embedded in outer membrane.

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Inner membrane is convoluted with infoldings.

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Mitochondrial matrix contains single circular DNA molecule and ribosomes.

Wrong

Score: 0 / 4

      Column-I                                    Column-II
(a) P - wave                   (i) Depolarisation of ventricles
(b) QRS complex           (ii) Repolarisation of ventricles
(c) T - wave                   (iii)Coronary ischemia
(d) Reduction in the       (iv) Depolarisation of size of T-wave atria
                                      (v) Repolarisation of atria

Select the correct option.
(a)      (b)      (c)       (d)

Your choiceExpected choiceAnswerComment
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(iv) (i) (ii) (iii)

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(iv) (i) (ii) (v)

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(ii) (i) (v) (iii)

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(ii) (iii) (v) (iv)

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Bacillus thuringiensis, Tobacco mosaic virus, Aphids

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Trichoderma, Baculovirus, Bacillus thuringiensis

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Oscillatoria, Rhizobium, Trichoderma

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Nostoc, Azospirillium, Nucleopolyhedrovirus

Wrong

Score: 0 / 4

Your choiceExpected choiceAnswerComment
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Mangifera indica Car. Linn.

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Mangifera indica Linn.

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Mangifera indica

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Mangifera Indica

Score for the test: 0 / 720

You didn't reach the minimum score

Wrong