Images Formed by Mirrors AP Physics 2 FRQ – Exam Style Questions etc.
Images Formed by Mirrors AP Physics 2 FRQ
Unit 13: Geometric and Physical Optics
Weightage : 15–18%
Exam Style Practice Questions ,Images Formed by Mirrors AP Physics 2 MCQ
Question
The figure above shows a convex mirror, its focal point \(F\), and its center of curvature \(C\).
Which of the rays shown above is correct for this mirror?
(A) 1
(B) 2
(C) 3
(D) 4
▶️Answer/Explanation
Ans:B
Question
The figure above shows a convex mirror, its focal point \(F\), and its center of curvature \(C\).
An object is located \(2 \mathrm{~m}\) to the left of the mirror. If point \(C\) is \(30 \mathrm{~cm}\) from the mirror, what is the approximate location of the object’s image?
(A) \(26 \mathrm{~cm}\) to the right of the mirror
(B) \(14 \mathrm{~cm}\) to the right of the mirror
(C) \(16 \mathrm{~cm}\) to the left of the mirror
(D) \(35 \mathrm{~cm}\) to the left of the mirror
▶️Answer/Explanation
Ans:B
Question
A bug crawls directly away from a mirror of focal length 10 cm as shown in the figure. The bug begins at 13 cm from the mirror and ends at 20 cm. What is happening to the image of the bug?
(A) The image inverts.
(B) The image gets larger in size.
( C) The image is becoming the same size as the bug.
(D) The image is moving away from the lens to the right.
Answer/Explanation
Ans:
C-The bug is walking from a position where the image is real, larger, and inverted toward 2f, where the image will be real, inverted, and the same size as the bug.
Question
Multi Correct. Which of the following are possible for the images formed by the lens in the accompanying figure? Select two answers.
(A) real and inverted
(B) real and smaller in size
(C) real and upright
(E) virtual and smaller in size
Answer/Explanation
Ans: A,B
Solution: The lens shown has thick in the center and thin on the outside which makes a converging lens. In converging lenses, all of the real images are inverted and can be any size, but the virtual images are formed in a magnifying lens scenario and are always larger and upright.
Question
An object is located 0.20 meters from a converging lens which has a focal length of 0.15 meters. Relative to the object, the image formed by the lens will be:
(A) virtual, inverted, smaller (B) real, inverted, smaller. (C) real, inverted, larger
(D) virtual, upright, larger
Answer/Explanation
Ans:C
Solution: Using the math, 1/f = 1/do + 1/di, and M = – di / do … di +0.6 M = – 3 …