IB DP Maths Topic 2.5 :The fundamental theorem of algebra HL Paper 2

 

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Question

One root of the equation \({x^2} + ax + b = 0\) is \(2 + 3{\text{i}}\) where \(a,{\text{ }}b \in \mathbb{R}\). Find the value of \(a\) and the value of \(b\).

▶️Answer/Explanation

Markscheme

METHOD 1

substituting

\( – 5 + 12{\text{i}} + a(2 + 3{\text{i}}) + b = 0\)     (A1)

equating real or imaginary parts     (M1)

\(12 + 3a = 0 \Rightarrow a =  – 4\)     A1

\( – 5 + 2a + b = 0 \Rightarrow b = 13\)     A1

METHOD 2

other root is \(2 – 3{\text{i}}\)     (A1)

considering either the sum or product of roots or multiplying factors     (M1)

\(4 =  – a\) (sum of roots) so \(a =  – 4\)     A1

\(13 = b\) (product of roots)     A1

[4 marks]

Examiners report

[N/A]
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