AP Chemistry 6.8 Enthalpies of Formation Study Notes - New Syllabus Effective fall 2024
AP Chemistry 6.8 Enthalpies of Formation Study Notes.- New syllabus
AP Chemistry 6.8 Enthalpies of Formation Study Notes – AP Chemistry – per latest AP Chemistry Syllabus.
LEARNING OBJECTIVE
Calculate the enthalpy change for a chemical or physical process based on the standard enthalpies of formation.
Key Concepts:
- Enthalpy of Reaction
- Enthalpy & Bond Energies
- Enthalpy of Formation
- Hess’s Law
6.8.A.1 Standard Enthalpy of Reaction Calculation:
1. Standard Enthalpy of Formation (ΔHf°):
The Standard Enthalpy of Formation (ΔHf°) is the heat change upon formation when 1 mole of substance is produced from elements in their stable forms at 298 K and 1 atm pressure.
– Standard Conditions: 298 K (25°C), 1 atm pressure.
– Standard State: The standard state of the element under normal conditions.
– ΔHf° of elements in standard state = 0 (e.g., O₂(g), C(s, graphite)).
It is used to calculate enthalpy changes in chemical reactions.
2. Enthalpy Change of a Reaction (ΔH°reaction):
The enthalpy change of a reaction (ΔH°reaction) is the heat released or absorbed during a chemical reaction under constant pressure. It is the difference in enthalpy between the products and reactants.
ΔHreaction=Hproducts−Hreactants
Significance:
– Endothermic Reactions:
When ΔH°reaction is positive, the reaction absorbs heat from the surroundings (e.g., photosynthesis).
– Exothermic Reactions:
If ΔH°reaction is negative, the reaction releases heat into the surroundings (e.g., combustion).
Briefly, ΔH°reaction indicates if a reaction is heat-releasing (exothermic) or heat-gaining (endothermic).
3. Using Enthalpy of Formation Tables:
i. Reading Standard Enthalpy of Formation (ΔHf°) Values:
– Standard enthalpy of formation values (ΔHf°) are given in tables for various compounds at 298 K and 1 atm.
– The values are the heat change when 1 mole of a substance is formed from its elements in their standard state.
– Elements in their standard state have ΔHf° = 0 (e.g., O₂(g), N₂(g), C(s, graphite)).
ii. Using ΔHf° in Reactions:
To calculate the enthalpy change (ΔH°reaction) for a reaction, use the following equation:
ΔHreaction=∑ΔHf(products)−∑ΔHf(reactants)
iii. Stoichiometry Application:
1. Balance the chemical equation for the reaction.
2. Find the ΔHf° values in the table for the reactant and product.
3. Use stoichiometry: Multiply the ΔHf° of each substance by its coefficient in the balanced equation.
4. Calculate the total for products and reactants, then subtract:
ΔHreaction∘=(∑(products))−(∑(reactants))
Example:
For the reaction:
ΔHf° (C(s)) = 0
ΔHf° (O₂(g)) = 0
ΔHf° (CO₂(g)) = -393.5 kJ/mol
ΔHreaction∘=[ΔHf° (CO₂)]−[ΔHf° (C)+ΔHf° (O₂)]
ΔHreaction∘=(−393.5)−(0+0)=−393.5kJ/mol
This reaction releases 393.5 kJ of energy.
OLD Content
Standard State
- Standard enthalpy (ΔH⁰): the enthalpy change at standard conditions
- ⁰ = recorded in standard state
- Standard State conditions:
- For a gas: pressure is 1 atm
- For a pure substance in a condensed state (liquid or solid) = pure liquid or solid
- For a solution, concentration is 1 molar
- Temp is at exactly 25 C
- Remember:
of a pure element is 0
- Standard heats of formation: the amount of heat needed to form 1 mole of a compound from its elements in their standard states (ie. how it exists in nature → oxygen is O2)
- Unit: kJ
- Have to make one mole of product to meet the definition
- SS of an element is the form in which the element exists under 1 atm and 25 C
- Not 0 = not how the element exists in nature
- Ex: Write the equation for the formation of methanol (CH3OH)
- Step 1: write the elements (in standard state)
- Step 1: write the elements (in standard state)
- Note: The elements that exist as diatomic molecules are hydrogen (H2), nitrogen (N2), fluorine (F2), oxygen (O2), iodine (I2), chlorine (Cl2) and bromine (Br2
- Step 2: Balance
- Step 2: Balance
- Formula:
(on RFS)
- Use chart → add up all of heats of formation of products – all the heats of formation of reactants