AP Chemistry 7.12 Common-Ion Effect Study Notes - New Syllabus Effective fall 2024
AP Chemistry 7.12 Common-Ion Effect Study Notes- New syllabus
AP Chemistry 7.12 Common-Ion Effect Study Notes – AP Chemistry – per latest AP Chemistry Syllabus.
LEARNING OBJECTIVE
Identify the solubility of a salt, and/or the value of Ksp for the salt, based on the concentration of a common ion already present in solution.
Key Concepts:
- Common-Ion Effect
7.12.A.1 Common-Ion Effect on Solubility
1. Solubility and Ksp
- Solubility: The amount of a salt that dissolves in a solvent to form a saturated solution.
- Ksp (Solubility Product Constant): The equilibrium constant for the dissolution of a salt. It is the product of ion concentrations:
- AB(s) ⇌ A⁺(aq) + B⁻(aq)
- Ksp = [A⁺][B⁻]
- Higher Ksp → More soluble
- Lower Ksp → Less soluble
2. Le Châtelier’s Principle
When a system at equilibrium is disturbed (e.g., change in concentration, temperature, or pressure), it shifts to minimize the disturbance and restore equilibrium.
Example: Adding more ions pushes the reaction to form more solid, counteracting the disturbance.
3. Common-Ion Effect
- Definition: Adding a common ion to a solution reduces the solubility of a salt.
- Why? The equilibrium shifts to the left (towards undissolved salt), decreasing dissolved salt.
4. Calculating Solubility with Common Ion
- Dissociation Equation:
AB(s) ⇌ A⁺(aq) + B⁻(aq) - Write the Ksp Expression:
Ksp = [A⁺][B⁻] - Adjust for Common Ion:
If [A⁺] from another source = x, and s = solubility of AB:
[A⁺] = x + s, [B⁻] = s - Solve for Solubility (s):
Plug into the Ksp formula and solve. The new solubility (s) will be lower due to the common ion.
5. Applications
- Precipitation Control:
Use common ions to lower solubility and force precipitation of specific salts. - Buffer Solutions:
Common ions help buffers resist pH changes by shifting equilibrium reactions.
Summary: The common-ion effect is key to understanding solubility, precipitation, and equilibrium in chemistry.
OLD Content
Common-Ion Effect
- Common-Ion Effect: when you try to dissolve the solid in a solution with either the cation or anion already present less solid will dissolve/more solid will be produced → the solubility of that salt is going to be less that it was in pure water
- Q > Ksp → reaction will shift to consuming more ions and producing more reactant (shift left) (more solid forming)
Calculations
- Asked to calculate the solubility of solid (s) in a solution of another compound
- Write balanced equation [dissolution/ions on product side] and ICE table
- Nothing in the Solid column, difference is that will have initial value for the ion that is present in solution
- Write balanced equation [dissolution/ions on product side] and ICE table