IBDP Physics 9.2 – Single-slit diffraction: IB Style Question Bank HL Paper 1

IB PHYSICS HL(Higher level) – 2024 – Practice Questions- All Topics

Topic 9.2 Single slit diffraction

Topic 9 Weightage : 5 % 

All Questions for Topic 9.2 – The nature of single-slit diffraction

Question

The diagram shows the diffraction pattern for light passing through a single slit.

What is \(\frac{\text{wavelength of light}}{\text{width of slit}}\)

A  0.01

B. 0.02

C 1

D 2

▶️Answer/Explanation

Ans: A

The graph for the variation of intensity as a function of sinθ is as follows :
  • The width of the central maxima is and angular width of central maxima is.

Hence  \(\frac{\lambda}{b}=\) diffraction angle \(\theta\)

Hence as per given value in graph

 \(\frac{\lambda}{b}= 10^{-2} = 0.001\)

Question

A beam of monochromatic light is incident on a single slit and a diffraction pattern forms on the screen.

What change will increase θs?

A. Increase the width of the slit

B. Decrease the width of the slit

C. Increase the distance between the slit and the screen

D. Decrease the distance between the slit and the screen

▶️Answer/Explanation

Markscheme

B

FRAUNHOFER DIFFRACTION BY SINGLE SLIT

In Fraunhofer diffraction experiment, the source and the screen are effectively at infinite distance from the diffracting element.
In single slit diffraction, imagine aperture to be divided into two equal halves. Secondary sources in these two halves give first minima at b sin θ = λ
In general, b sin θ = nλ for minima
Hence \(sin\theta=\frac{n\lambda}{b}\)
\(\therefore b \downarrow \Rightarrow sin\theta \uparrow\)

Question

A single-slit diffraction experiment is performed using light of different colours. The width of the central peak in the diffraction pattern is measured for each colour. What is the order of the colours that corresponds to increasing widths of the central peak?

A. red, green, blue

B. red, blue, green

C. blue, green, red

D. green, blue, red

▶️Answer/Explanation

Markscheme

C

The graph for the variation of intensity as a function of sinθ is as follows :
  • The width of the central maxima is and angular width of central maxima is.

Hence width of the central maxima increases with increase in wavelength.

We can see lowest wavelength is blue and highest for red for blue, green, red

Question

A parallel beam of coherent light of wavelength λ is incident on a rectangular slit of width d. After passing through the slit the light is incident on a screen a distance D from the slit where D is much greater than d. What is the width of the central maximum of the diffraction pattern as measured on the screen?

A. \(\frac{{2D\lambda }}{d}\)

B. \(\frac{{2d}}{{D\lambda }}\)

C. \(\frac{{D\lambda }}{d}\)

D. \(\frac{d}{{D\lambda }}\)

▶️Answer/Explanation

Markscheme

A

The graph for the variation of intensity as a function of sinθ is as follows :
  • The width of the central maxima is and angular width of central maxima is.

Question

The intensity distribution of monochromatic light passing through a narrow slit and then incident on a screen is shown below.

When the slit width is reduced which diagram shows the new intensity distribution? Diagrams are drawn to the same scale as the original.

▶️Answer/Explanation

Markscheme

B

The width of the central maxima is

When b is reduced width of the central maxima is is increased . 

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