SAT MAth Practice questions – all topics
- Advanced Math Weightage: 35% Questions: 13-15
- Equivalent expressions
- Nonlinear equations in one variable and systems of equations in two variables
- Nonlinear functions
SAT MAth and English – full syllabus practice tests
Questions Easy
What is the y-coordinate of the y-intercept of the graph of \(y=3^{x}+9\) ?
▶️Answer/Explanation
Ans: 10
To find the \(y\)-coordinate of the \(y\)-intercept of the graph of \(y = 3^x + 9\), we set \(x = 0\) and solve for \(y\):
\[y = 3^0 + 9 = 1 + 9 = 10\]
So, the \(y\)-coordinate of the \(y\)-intercept is \(10\).
Question
\(E = 18,000 – 2,000t\)
\(V = 18,000(0.85^{t})\)
The given equations are two different models that can be used to find the value, in dollars, of a particular car \(t\) years after it was purchased. Which of the following statements correctly compares the values of \(E\) and \(V\) for \(O < t < 9\) ?
- \(E\) is always less than \(V\).
- \(E\) is always greater than \(V\).
- \(E\) is initially greater than \(V\) but eventually becomes less than \(V\).
- \(E\) is initially less than \(V\) but eventually becomes greater than \(V\).
▶️Answer/Explanation
C
Question
Kao measured the temperature of a cup of hot chocolate placed in a room with a constant temperature of70 degrees Fahrenheit ( $\left.{ }^{\circ} \mathrm{F}\right)$. The temperature of the hot chocolate was $185^{\circ} \mathrm{F}$ at 6:00 p.m. when it started cooling. The temperature of the hot chocolate was 156 $6^{\circ} \mathrm{F}$ at 6:05 p.m. and $135^{\circ} \mathrm{F}$ at 6:10 p.m. The temperature of the hot chocolate continued to decrease. Of the following functions, which best models the temperature $T(m)$, in degrees Fahrenheit, of Kao’s hot chocolate $m$ minutes after it started cooling?
A. $T(m)=185(1.25)^m$
B. $T(m)=185(0.85)^m$
C. $T(m)=(185-70)(0.75)^{\frac{m}{5}}$
D. $T(m)=70+115(0.75)^{\frac{m}{5}}$
▶️Answer/Explanation
Ans: D