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AP Chemistry 9.8 Galvanic (Voltaic) Cells Study Notes - New Syllabus Effective fall 2024

AP Chemistry 9.8 Galvanic (Voltaic) Cells Study Notes- New syllabus

AP Chemistry 9.8 Galvanic (Voltaic) Cells Study Notes – AP Chemistry –  per latest AP Chemistry Syllabus.

LEARNING OBJECTIVE

Explain the relationship between the physical components of an electrochemical cell and the overall operational principles of the cell.

Key Concepts: 

  • Components and Functioning of an Electrochemical Cell
  • Galvanic vs. Electrolytic Cells

  • Oxidation and Reduction in Electrochemical Cells

AP Chemistry-Concise Summary Notes- All Topics

Components and Functioning of an Electrochemical Cell

An electrochemical cell is a system that converts chemical energy into electrical energy (or vice versa) through oxidation–reduction (redox) reactions. Each part of the cell plays a specific and essential role in ensuring electron flow, ion balance, and completion of the redox process.

Electrochemical cells operate under two main types:

  • Galvanic (Voltaic) Cells: spontaneous chemical reactions that generate electrical energy.
  • Electrolytic Cells: nonspontaneous reactions driven by an external energy source.

Key Components of an Electrochemical Cell

  

ComponentDescription / FunctionMacroscopic Role
AnodeElectrode where oxidation occurs (loss of electrons).Electrons are released into the external circuit.
CathodeElectrode where reduction occurs (gain of electrons).Electrons are accepted from the circuit.
Half-cellsEach half-cell contains an electrode and an electrolyte solution of its ions.Maintains ionic environment for oxidation or reduction.
Salt bridgeConnects two half-cells, allowing ion flow to balance charge buildup.Completes the circuit electrically while preventing direct mixing.
External circuitWire or conductor that carries electrons between electrodes.Allows current flow from anode → cathode.
Voltmeter / AmmeterMeasures cell potential (voltage) or current.Indicates electrical output or input of the cell.

Macroscopic vs. Particulate Descriptions

  • Macroscopic level: Observes measurable changes such as voltage, current, electrode mass, and gas evolution.
  • Particulate level: Involves electron transfer between ions and electrodes, ion migration through the salt bridge, and redox processes at surfaces.

General Representation of a Galvanic Cell

  • Left side (anode): oxidation → \( \mathrm{Zn(s) \rightarrow Zn^{2+}(aq) + 2e^-} \)
  • Right side (cathode): reduction → \( \mathrm{Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)} \)
  • Electrons flow: from Zn (anode) → Cu (cathode) through external wire.
  • Cations flow from salt bridge to cathode; anions to anode.

Example: 

In a galvanic cell made from Zn(s) and Cu(s) electrodes, identify what happens at each electrode and explain the role of the salt bridge.

▶️ Answer / Explanation

Step 1: Determine the oxidation and reduction half-reactions:

  • Anode: \( \mathrm{Zn(s) \rightarrow Zn^{2+}(aq) + 2e^-} \) (oxidation)
  • Cathode: \( \mathrm{Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)} \) (reduction)

Step 2: Direction of electron flow:

Electrons flow from Zn (anode) → Cu (cathode).

Step 3: Role of the salt bridge:

Allows ions to move between half-cells to maintain electrical neutrality:

  • Anions (e.g., Cl⁻) move toward the anode compartment to balance \( \mathrm{Zn^{2+}} \) formation.
  • Cations (e.g., Na⁺) move toward the cathode compartment to replace \( \mathrm{Cu^{2+}} \) ions reduced at the electrode.

Step 4: Observations:

  • Zn electrode loses mass as it dissolves into solution.
  • Cu electrode gains mass as solid Cu is deposited.

Final Answer: The salt bridge maintains charge balance, while the anode undergoes oxidation and the cathode reduction. The Zn–Cu cell generates a spontaneous voltage of approximately 1.10 V.

 Galvanic vs. Electrolytic Cells

Electrochemical cells are classified into two main types based on whether the overall redox reaction is thermodynamically favored or requires an external source of energy to proceed:

  • Galvanic (Voltaic) Cell: uses a spontaneous redox reaction (\( \mathrm{\Delta G^\circ < 0} \)) to produce electrical energy.
  • Electrolytic Cell: uses electrical energy from an external source to drive a nonspontaneous reaction (\( \mathrm{\Delta G^\circ > 0} \)).

Key Equation for Spontaneity

\( \mathrm{\Delta G^\circ = -nFE^\circ_{cell}} \)

  • \( \mathrm{n} \): moles of electrons transferred
  • \( \mathrm{F = 96,485\ C/mol\ e^-} \): Faraday’s constant
  • \( \mathrm{E^\circ_{cell}} \): standard cell potential (V)

When \( \mathrm{E^\circ_{cell} > 0} \), the reaction is spontaneous (galvanic). When \( \mathrm{E^\circ_{cell} < 0} \), the reaction is nonspontaneous (electrolytic).

Comparison Between Galvanic and Electrolytic Cells

FeatureGalvanic (Voltaic) CellElectrolytic Cell
Nature of ReactionSpontaneous (\( \mathrm{\Delta G^\circ < 0} \))Nonspontaneous (\( \mathrm{\Delta G^\circ > 0} \))
Energy ConversionChemical → ElectricalElectrical → Chemical
Source of EnergyGenerated by reaction itselfSupplied from an external power source
Anode ReactionOxidationOxidation
Cathode ReactionReductionReduction
Electron FlowAnode → Cathode (spontaneous)Forced Anode → Cathode (by power source)
Sign of ElectrodesAnode (−), Cathode (+)Anode (+), Cathode (−)
ExamplesDaniell cell, batteriesElectrolysis of water, electroplating

Visual Representation of Flow and Reactions

  • In a galvanic cell: electrons flow spontaneously from anode → cathode through a wire; ions move through a salt bridge to maintain neutrality.
  • In an electrolytic cell: an external voltage source drives electrons in the reverse direction (nonspontaneous redox).

Example : 

Write the half-reactions, direction of electron flow, and electrode signs for a Daniell cell composed of Zn and Cu electrodes.

▶️ Answer / Explanation

Step 1: Half-reactions:

  • Anode (oxidation): \( \mathrm{Zn(s) \rightarrow Zn^{2+}(aq) + 2e^-} \)
  • Cathode (reduction): \( \mathrm{Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)} \)

Step 2: Electron flow:

Electrons flow from Zn (anode) → Cu (cathode).

Step 3: Electrode signs:

  • Anode = negative (source of electrons)
  • Cathode = positive (receives electrons)

Step 4: Cell representation:

\( \mathrm{Zn(s) | Zn^{2+}(aq) || Cu^{2+}(aq) | Cu(s)} \)

Final Answer: The Daniell cell operates spontaneously with \( \mathrm{E^\circ_{cell} = +1.10\ V} \); oxidation at the anode and reduction at the cathode generate electrical current.

Example : 

 Describe what happens at each electrode during the electrolysis of molten \( \mathrm{NaCl(l)} \), including electron flow and products formed.

▶️ Answer / Explanation

Step 1: External DC power source forces nonspontaneous redox:

  • Cathode (reduction): \( \mathrm{Na^+ + e^- \rightarrow Na(l)} \)
  • Anode (oxidation): \( \mathrm{2Cl^- \rightarrow Cl_2(g) + 2e^-} \)

Step 2: Direction of flow:

Electrons move from the anode (+) to the cathode (−) through the external circuit (opposite of galvanic flow).

Step 3: Observation:

  • Liquid sodium forms at the cathode.
  • Chlorine gas evolves at the anode.

Final Answer: Electrolysis of molten NaCl is an electrolytic process driven by external electrical energy, resulting in the decomposition of NaCl into \( \mathrm{Na(l)} \) and \( \mathrm{Cl_2(g)} \).

Oxidation and Reduction in Electrochemical Cells

In all electrochemical cells — whether galvanic (voltaic) or electrolytic — the fundamental rule remains the same:

Oxidation occurs at the anode, and reduction occurs at the cathode.

This principle applies universally, even though the signs of the electrodes differ between galvanic and electrolytic cells.

Key Terms and Equations

  • Oxidation: loss of electrons → occurs at the anode
  • Reduction: gain of electrons → occurs at the cathode
  • Mnemonic: “OIL RIG” — Oxidation Is Loss, Reduction Is Gain (of electrons)

General representation for a redox reaction:

\( \mathrm{Ox + e^- \leftrightharpoons Red} \)

Electrode Behavior in Different Cell Types

PropertyGalvanic (Voltaic) CellElectrolytic Cell
Reaction TypeSpontaneous (\( \mathrm{\Delta G^\circ < 0} \))Nonspontaneous (\( \mathrm{\Delta G^\circ > 0} \))
Anode processOxidationOxidation
Cathode processReductionReduction
Electron flowFrom anode → cathode (spontaneous)From anode → cathode (forced by external source)
Anode signNegative (source of electrons)Positive (connected to positive terminal of power supply)
Cathode signPositive (electron sink)Negative (connected to negative terminal)

Mnemonic Summary

  • Oxidation → Anode (Always!)
  • Reduction → Cathode (Always!)
  • In Galvanic Cell: Anode (−), Cathode (+)
  • In Electrolytic Cell: Anode (+), Cathode (−)

Example : 

In the galvanic cell \( \mathrm{Zn(s) | Zn^{2+}(aq) || Cu^{2+}(aq) | Cu(s)} \), determine where oxidation and reduction occur, and identify the anode and cathode.

▶️ Answer / Explanation

Step 1: Write half-reactions:

  • \( \mathrm{Zn(s) \rightarrow Zn^{2+}(aq) + 2e^-} \) — oxidation
  • \( \mathrm{Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)} \) — reduction

Step 2: Identify electrodes:

  • Anode → Zn(s) electrode (oxidation site)
  • Cathode → Cu(s) electrode (reduction site)

Step 3: Determine flow:

Electrons flow from Zn (anode, −) → Cu (cathode, +)

Final Answer: Oxidation occurs at the Zn anode; reduction occurs at the Cu cathode. This is a galvanic cell that generates electricity spontaneously (\( \mathrm{E^\circ_{cell} = +1.10\ V} \)).

Example : 

During the electrolysis of molten \( \mathrm{NaCl(l)} \), identify the anode, cathode, and reactions at each electrode.

▶️ Answer / Explanation

Step 1: Write half-reactions:

  • Anode (oxidation): \( \mathrm{2Cl^-(l) \rightarrow Cl_2(g) + 2e^-} \)
  • Cathode (reduction): \( \mathrm{Na^+(l) + e^- \rightarrow Na(l)} \)

Step 2: Assign electrodes:

  • Anode = positive (connected to external power supply’s + terminal)
  • Cathode = negative (connected to − terminal)

Step 3: Direction of flow:

Electrons move from anode → cathode through the external circuit (forced by power source).

Final Answer: In the electrolysis of molten NaCl, oxidation occurs at the anode (+) and reduction at the cathode (−). The universal rule — oxidation at anode, reduction at cathode — holds true.

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