Home / AS & A Level Chemistry 16.1 Alcohols Exam Style Practice Questions Paper 1

AS & A Level Chemistry 16.1 Alcohols Exam Style Practice Questions Paper 1- New Syllabus

Question

Cyclohexanol is converted to cyclohexane-1,2-diol via a two-step synthesis that proceeds via intermediate Q.

Which row identifies the type of reaction in step 1 and in step 2?

 Step 1Step 2
Adehydrationoxidation
Bdehydrationnucleophilic substitution
Creductionoxidation
Dreductionnucleophilic substitution
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{A}} \)

In step 1, cyclohexanol is converted into cyclohexene by eliminating a molecule of water. This is a dehydration reaction.

In step 2, the alkene is converted into cyclohexane-1,2-diol by oxidation with an oxidising agent such as cold, dilute acidified \(\mathrm{KMnO_4}\).

Two hydroxyl groups are added across the carbon-carbon double bond to form the vicinal diol.

Therefore, the correct answer is (A).

Question

The diagram shows the structure of compound X.

X undergoes hydrolysis to form product Y in which all of the bromine atoms are replaced by hydroxyl groups.

Product Z is formed by oxidation of Y.

Two suggestions are listed.

1   Y is a secondary alcohol.

2   Z is a ketone.

Which suggestions are correct?

(A) both 1 and 2
(B) 1 only
(C) 2 only
(D) neither 1 nor 2
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{A}} \)

Hydrolysis replaces each bromine atom with a hydroxyl group. In the cyclohexane ring, each carbon bearing a hydroxyl group is bonded to two other carbon atoms, so every \(\mathrm{-OH}\) group is on a secondary carbon.

On oxidation, secondary alcohols are oxidised to ketones.

Therefore, product Y is a secondary alcohol and product Z contains ketone groups.

Hence, both suggestions are correct and the correct answer is (A).

Question

Which reaction mixture produces a primary alcohol as the major product?

(A) propanone with \(\mathrm{NaBH_4}\)
(B) propene with steam in the presence of \(\mathrm{H_3PO_4}\)
(C) butanoic acid with \(\mathrm{LiAlH_4}\)
(D) ethene with hot concentrated acidified \(\mathrm{KMnO_4}\)
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{C}} \)

Lithium aluminium hydride reduces carboxylic acids to primary alcohols.

The reaction is:

\(\mathrm{CH_3CH_2CH_2COOH \xrightarrow{LiAlH_4} CH_3CH_2CH_2CH_2OH}\)

Option (A) produces a secondary alcohol, option (B) produces a secondary alcohol by Markovnikov addition, and option (D) oxidises ethene rather than producing an alcohol.

Therefore, the correct answer is (C).

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