Home / AS & A Level Chemistry 18.2 Esters Exam Style Practice Questions Paper 1

AS & A Level Chemistry 18.2 Esters Exam Style Practice Questions Paper 1- New Syllabus

Question

The structural formula of compound P is \(\mathrm{CH_3CH_2COOCH_2CH_3}\).

P can be formed by reacting together two organic compounds in the presence of a suitable catalyst.

Which pair of compounds could react together to produce P?

(A) ethanoic acid and propanoic acid
(B) ethanoic acid and propan-1-ol
(C) ethanol and propanoic acid
(D) ethanol and propan-1-ol
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{C}} \)

Compound P is an ester, \(\mathrm{CH_3CH_2COOCH_2CH_3}\), called ethyl propanoate.

It is formed by esterification between:

  • ethanol, \(\mathrm{CH_3CH_2OH}\)
  • propanoic acid, \(\mathrm{CH_3CH_2COOH}\)

The reaction is:

\(\mathrm{CH_3CH_2COOH+CH_3CH_2OH\rightleftharpoons CH_3CH_2COOCH_2CH_3+H_2O}\)

Therefore, the correct answer is (C).

Question

Which compound is a product of the hydrolysis of \(\mathrm{CH_3CO_2CH_2CH_3}\) using aqueous sodium hydroxide?

(A) \(\mathrm{CH_3CO_2^-Na^+}\)
(B) \(\mathrm{CH_3CO_2H}\)
(C) \(\mathrm{C_2H_5CH_2O^-Na^+}\)
(D) \(\mathrm{C_2H_5CH_2CO_2^-Na^+}\)
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{A}} \)

Ethyl ethanoate undergoes alkaline hydrolysis (saponification):

\(\mathrm{CH_3CO_2CH_2CH_3+NaOH\rightarrow CH_3CO_2^-Na^++CH_3CH_2OH}\)

The products are sodium ethanoate and ethanol.

Therefore, the correct answer is (A).

Question

The table shows the reagents and products of three reactions.

 ReactantsProducts
1Ethanoic acid + \(\mathrm{Na_2CO_3}\)\(\mathrm{CH_3CO_2Na+H_2O+CO_2}\)
2Ethanoic acid + Mg\(\mathrm{(CH_3CO_2)_2Mg+H_2O}\)
3Ethanoic acid + \(\mathrm{CH_3OH}\)\(\mathrm{CH_3CO_2CH_3+H_2O}\)

Which rows are correct?

(A) 1, 2 and 3
(B) 1 and 2 only
(C) 1 and 3 only
(D) 2 and 3 only
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{C}} \)

Row 1 is correct because acids react with carbonates to produce a salt, water and carbon dioxide.

Row 2 is incorrect because magnesium reacts with ethanoic acid to produce hydrogen gas, not water:

\(\mathrm{2CH_3CO_2H+Mg\rightarrow (CH_3CO_2)_2Mg+H_2}\)

Row 3 is correct because methanol and ethanoic acid undergo esterification to form methyl ethanoate and water.

Therefore, the correct answer is (C).

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