Home / AS & A Level Chemistry 4.1 The gaseous state , ideal and real gases and $p V=n R T$ Exam Style Practice Questions Paper 1

AS & A Level Chemistry 4.1 The gaseous state , ideal and real gases and $p V=n R T$ Exam Style Practice Questions Paper 1- New Syllabus

Question

A pure sample of a gas has a density of \(2.62\,\mathrm{g\,dm^{-3}}\) at \(101000\,\mathrm{Pa}\) and \(25^\circ\mathrm{C}\). The gas behaves ideally under these conditions.

Which expression gives the \(M_r\) of the gas?

(A) \(\dfrac{101000\times0.001}{2.62\times8.31\times25}\)
(B) \(\dfrac{101000\times0.001}{2.62\times8.31\times298}\)
(C) \(\dfrac{2.62\times8.31\times25}{101000\times0.001}\)
(D) \(\dfrac{2.62\times8.31\times298}{101000\times0.001}\)
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{D}} \)

For an ideal gas:

\(PV=nRT\)

Using \(n=\dfrac{m}{M_r}\) and density \(=\dfrac{m}{V}\):

\(M_r=\dfrac{\mathrm{density}\times RT}{P}\)

Temperature must be converted to kelvin: \(25^\circ\mathrm{C}=298\,\mathrm{K}\), and \(1\,\mathrm{dm^3}=0.001\,\mathrm{m^3}\).

Therefore, the correct expression is (D).

Question

\(1.00\,\mathrm{g}\) of nitrogen gas is stored in a \(2.00\,\mathrm{dm^3}\) vessel at \(40.0^\circ\mathrm{C}\).

What is the pressure in the vessel?

(A) \(5940\,\mathrm{Pa}\)
(B) \(11\,900\,\mathrm{Pa}\)
(C) \(46\,400\,\mathrm{Pa}\)
(D) \(92\,900\,\mathrm{Pa}\)
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{C}} \)

Moles of nitrogen:

\(n=\dfrac{1.00}{28.0}=0.0357\,\mathrm{mol}\)

Convert the volume and temperature:

\(V=2.00\,\mathrm{dm^3}=2.00\times10^{-3}\,\mathrm{m^3}\)

\(T=40.0+273=313\,\mathrm{K}\)

Using the ideal gas equation, \(PV=nRT\).

\(P=\dfrac{nRT}{V}=\dfrac{0.0357\times8.31\times313}{2.00\times10^{-3}}\approx4.64\times10^4\,\mathrm{Pa}\)

Therefore, the correct answer is (C).

Question 

Two glass vessels, M and N, are connected by a closed valve.

M contains helium at \(20^\circ\mathrm{C}\) at a pressure of \(1.0\times10^5\,\mathrm{Pa}\). N has been evacuated and has three times the volume of M.

The valve is opened and the temperature of the whole apparatus is raised to \(100^\circ\mathrm{C}\).

What is the final pressure in the system?

(A) \(3.18\times10^4\,\mathrm{Pa}\)
(B) \(4.24\times10^4\,\mathrm{Pa}\)
(C) \(1.25\times10^5\,\mathrm{Pa}\)
(D) \(5.09\times10^5\,\mathrm{Pa}\)
▶️ Answer/Explanation

Correct Answer: \( \boxed{\mathrm{A}} \)

Initially:

\(P_1=1.0\times10^5\,\mathrm{Pa}\), \(T_1=293\,\mathrm{K}\).

The total volume after opening the valve is:

\(V_2=V+3V=4V\)

The final temperature is:

\(T_2=373\,\mathrm{K}\)

Using \( \dfrac{PV}{T}=\text{constant} \):

\(P_2=P_1\times\dfrac{V_1}{V_2}\times\dfrac{T_2}{T_1}\)

\(=1.0\times10^5\times\dfrac{1}{4}\times\dfrac{373}{293}\)

\(=3.18\times10^4\,\mathrm{Pa}\)

Therefore, the correct answer is (A).

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