IB DP Biology- D1.3 Mutations and gene editing- IB Style Questions For HL Paper 1A -New Syllabus
▶️ Answer/Explanation
Before mutation, the mRNA transcribed from the DNA sequence 3′–TAC TCC TGC TTC–5′ would be 5′–AUG AGG ACG AAG–3′, coding for Met–Arg–Thr–Lys.
After mutation, the sequence becomes 3′–TAC TGC TGC TTC–5′, giving mRNA 5′–AUG ACG ACG AAG–3′, coding for Met–Thr–Thr–Lys.
Thus, Thr replaces Arg due to the base substitution changing the codon AGG to ACG.
✅ Answer: (A)
After mutation, the sequence becomes 3′–TAC TGC TGC TTC–5′, giving mRNA 5′–AUG ACG ACG AAG–3′, coding for Met–Thr–Thr–Lys.
Thus, Thr replaces Arg due to the base substitution changing the codon AGG to ACG.
✅ Answer: (A)
▶️ Answer/Explanation
A gene knockout involves intentionally inactivating a gene to observe what changes occur in the organism. This helps reveal the gene’s normal function by seeing what happens when it is absent.
✅ Answer: (B)
✅ Answer: (B)