IBDP Maths AI: Topic : SL 1.5: Laws of exponents: IB style Questions SL Paper 1

Question

 The strength of earthquakes is measured on the Richter magnitude scale, with values
typically between 0 and 8 where 8 is the most severe.
The Gutenberg–Richter equation gives the average number of earthquakes per year, N,
which have a magnitude of at least M. For a particular region the equation is
\(log_{10}N=a-M\), for some \(a\epsilon \mathbb{R}\).
This region has an average of 100 earthquakes per year with a magnitude of at least 3.
(a) Find the value of a.
The equation for this region can also be written as \(N=\frac{b}{M^M}\).
(b) Find the value of b.
(c) Given 0<M<8, find the range for N.
The expected length of time, in years, between earthquakes with a magnitude of at least M is \(\frac{1}{N}\).
Within this region the most severe earthquake recorded had a magnitude of 7.2.
(d) Find the expected length of time between this earthquake and the next earthquake of at least this magnitude. Give your answer to the nearest year.

Answer/Explanation

Ans:

(a) \(log_{10} 100 = a – 3\)
a = 5
(b) EITHER
\(N = 10^{5-M}\)
OR
\(100=\frac{b}{10^3}\)
THEN
b = 100000\((=10^5)\)
(c) 0.001<N<100000 \((10^{-3}<N<10^5)\)
(d) \(N=\frac{10^5}{10^{7.2}}(=0.0063095…)\)
length of time = \(\frac{1}{0.0063095…}=10^{2.2}\)
= 158 years

Question

Five pipes labelled, “6 metres in length”, were delivered to a building site. The contractor measured each pipe to check its length (in metres) and recorded the following;

5.96, 5.95, 6.02, 5.95, 5.99.

(i) Find the mean of the contractor’s measurements.

(ii) Calculate the percentage error between the mean and the stated, approximate length of 6 metres.

[3]
a.

Calculate \(\sqrt {{{3.87}^5} – {{8.73}^{ – 0.5}}} \), giving your answer

(i) correct to the nearest integer,

(ii) in the form \(a \times 10^k\), where 1 ≤ a < 10, \(k \in {\mathbb{Z}}\) .

[3]
b.
Answer/Explanation

Markscheme

(i) Mean = (5.96 + 5.95 + 6.02 + 5.95 + 5.99) / 5 = 5.974 (5.97)     (A1)

(ii) \({\text{%  error}} = \frac{{error}}{{actualvalue}} \times 100\% \)

\( = \frac{{6 – 5.974}}{{5.974}} \times 100\%  = 0.435\% \)     (M1)(A1)(ft)

(M1) for correctly substituted formula.

Allow 0.503% as follow through from 5.97

Note: An answer of 0.433% is incorrect.     (C3)

[3 marks]

a.

number is 29.45728613

(i) Nearest integer = 29     (A1)

(ii) Standard form = 2.95 × 101 (accept 2.9 × 101)     (A1)(ft)(A1)

Award (A1) for each correct term

Award (A1)(A0) for 2.95 × 10     (C3)

[3 marks]

b.

Question

Write down the following numbers in increasing order.

\(3.5\), \(1.6 \times 10^{−19}\), \(60730\), \(6.073 \times 10^{5}\), \(0.006073 \times 10^6\), \(\pi\), \(9.8 \times 10^{−18}\).

[3]
a.

Write down the median of the numbers in part (a).

[1]
b.

State which of the numbers in part (a) is irrational.

[1]
c.
Answer/Explanation

Markscheme

\(1.6 \times 10^{−19}\), \(9.8 \times 10^{−18}\), \(\pi\), \(3.5\), \(0.006073 \times 10^6\), \(60730\), \(6.073 \times 10^{5}\)     (A4)

Award (A1) for \(\pi\) before 3.5

Award (A1) for \(1.6 \times 10^{−19}\) before \(9.8 \times 10^{−18}\)

Award (A1) for the three numbers containing 6073 in the correct order.

Award (A1) for the pair with negative indices placed before 3.5 and \(\pi\) and the remaining three numbers placed after (independently of the other three marks).

Award (A3) for numbers given in correct decreasing order.

Award (A2) for decreasing order with at most 1 error     (C4)

[3 marks]

a.

The median is 3.5.     (A1)(ft)

Follow through from candidate’s list.     (C1)

[1 mark]

b.

\(\pi\) is irrational.     (A1)     (C1)

[1 mark]

c.

Question

Consider the numbers \(2\), \(\sqrt 3 \), \( – \frac{2}{3}\) and the sets \(\mathbb{N}\), \(\mathbb{Z}\), \(\mathbb{Q}\) and \(\mathbb{R}\).

Complete the table below by placing a tick in the appropriate box if the number is an element of the set, and a cross if it is not.

[3]
a.

A function \(f\) is given by \(f(x) = 2{x^2} – 3x{\text{, }}x \in \{ – 2{\text{, }}2{\text{, }}3\} \).

Write down the range of function \(f\).

[1]
b.
Answer/Explanation

Markscheme

     (A1)(A1)(A1)     (C3)

Note: Accept any symbol for ticks. Do not penalise if the other boxes are left blank.

[3 marks]

a.

\({\text{Range}} = \{ 2{\text{, }}9{\text{, }}14\} \)     (A1)(ft)     (C1)

Note: Brackets not required.

[1 mark]

b.

Question

Consider the numbers \(\sqrt 3 \), \(6\), \(2\frac{1}{2}\), \(\pi \), \( – 5\), and the sets \(\mathbb{N}\), \(\mathbb{Z}\), and \(\mathbb{Q}\). Complete the following table by placing a tick in the appropriate box if the number is an element of the set.

Answer/Explanation

Markscheme

Note: Accept any symbol for ticks. Do not penalize if candidate had also indicated, by a different symbol, that the number is not an element of the set.

Row \(\mathbb{N}\) correct, no extra entries.     (A1)     (C1)

Row \(\mathbb{Z}\)     (A1)(A1)    (C2)

Note: Award (A1) for each correct tick and no extra entries. Award (A1) only for both ticks correct and 1 extra entry, (A0) otherwise.

Row \(\mathbb{Q}\)     (A1)(A1)(A1)     (C3)

Note: Award (A1) for each correct tick and no extra entries. Award (A2) only for all 3 correct and one extra entry. Award (A1) only for 2 correct and one extra entry. (A0) otherwise.

[6 marks]

Scroll to Top