IBDP Physics- C.4 Standing waves and resonance- IB Style Questions For HL Paper 1A -FA 2025
Question
A string that is fixed at both ends oscillates in the second harmonic with frequency \(100\,\mathrm{Hz}\).
What other harmonic frequencies, in \(\mathrm{Hz}\), can this string oscillate at?
(B) \(25\) and \(75\)
(C) \(50\) and \(150\)
(D) \(75\) and \(150\)
▶️ Answer/Explanation
Correct Answer: \( \boxed{\mathrm{C}} \)
For a string fixed at both ends, the harmonic frequencies are integer multiples of the fundamental frequency:
\(f_n=nf_1\)
The second harmonic has frequency
\(f_2=2f_1=100\,\mathrm{Hz}\)
Therefore, the fundamental frequency is
\(f_1=\dfrac{100}{2}=50\,\mathrm{Hz}\)
The third harmonic is
\(f_3=3f_1=3(50)=150\,\mathrm{Hz}\)
Thus, the other harmonic frequencies listed are \(50\,\mathrm{Hz}\) and \(150\,\mathrm{Hz}\).
Hence, the correct answer is \( \boxed{\mathrm{C}} \).
Question
A standing sound wave is formed in a pipe of length \(L\) that is open at both ends. The standing wave has two nodes. What is the wavelength of the standing wave?
(B) \(\frac{2L}{3}\)
(C) \(L\)
(D) \(2L\)
▶️ Answer/Explanation
Correct Answer: \( \boxed{\mathrm{C}} \)
For a pipe open at both ends, both ends are displacement antinodes.
A standing wave with two nodes corresponds to the second harmonic. For an open pipe, the allowed wavelengths satisfy
\(L=n\frac{\lambda}{2}\)
For two nodes, \(n=2\). Therefore,
\(L=2\frac{\lambda}{2}\)
Hence,
\(\lambda=L\)
Thus, the wavelength of the standing wave is
\( \boxed{\lambda=L} \)
Hence, the correct answer is \( \boxed{\mathrm{C}} \).
Question
What other frequency is possible for a standing wave in this pipe?
(B) \(50\,\mathrm{Hz}\)
(C) \(75\,\mathrm{Hz}\)
(D) \(300\,\mathrm{Hz}\)
▶️ Answer / Explanation
For a pipe that is closed at one end and open at the other, only odd harmonics are present.
The allowed harmonic frequencies are given by:
\( f_n = (2n – 1)f_1 \quad \text{where } n = 1,2,3,\dots \)
The third harmonic corresponds to:
\( f_3 = 3f_1 \)
Given \( f_3 = 150\,\mathrm{Hz} \),
\( f_1 = \dfrac{150}{3} = 50\,\mathrm{Hz} \)
Therefore, another possible standing-wave frequency in this pipe is the fundamental frequency of \(50\,\mathrm{Hz}\).
✅ Answer: (B)
