Home / iGCSE Chemistry (0620) Core:11.2 Naming organic compounds: Exam Style Questions Paper 1

iGCSE Chemistry (0620) Core:11.2 Naming organic compounds: Exam Style Questions Paper 1- New Syllabus

Question

The structures of four organic compounds, W, X, Y and Z, are shown.

Which compounds are members of the same homologous series?
A W and X
B W and Z
C X and Y
D Y and Z

▶️ Answer/Explanation
W contains a carboxyl group (-COOH) which makes it a carboxylic acid. X contains a carbon-carbon double bond (C=C) which makes it an alkene. Y contains a hydroxyl group (-OH) attached to a saturated carbon chain, making it an alcohol. Z also contains a carboxyl group (-COOH), making it a carboxylic acid. Since W and Z share the same functional group (-COOH), they belong to the same homologous series (carboxylic acids).
Answer: (B) W and Z

Question

Which bar chart shows the percentage composition of natural gas?
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Natural gas is primarily composed of methane ($\text{CH}_4$), typically making up around 80-95% of its composition. The remaining percentage consists of smaller amounts of other hydrocarbons such as ethane, propane, and butane. Looking at the bar charts, option D shows methane as the largest component by far, taking up the majority of the bar, with only a small portion dedicated to other hydrocarbons. This accurately represents the composition of natural gas, where methane is the main constituent. The other options show different distributions that do not match the true composition of natural gas.

Question

What is the structure of ethanol?
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Ethanol is an alcohol with the molecular formula $\mathrm{C_2H_5OH}$ or $\mathrm{CH_3CH_2OH}$. Its displayed formula shows two carbon atoms connected by a single covalent bond. The first carbon is bonded to three hydrogen atoms ($\mathrm{CH_3}$–), and the second carbon is bonded to two hydrogen atoms and an –OH (hydroxyl) group (–$\mathrm{CH_2OH}$). Looking at the four diagrams, the one with two carbons, five hydrogens, and one –OH group in this exact arrangement is ethanol. Methanol has only one carbon, methanoic acid and ethanoic acid contain a –COOH carboxyl group rather than the –OH alcohol group. The structure matching the $\mathrm{C_2H_5OH}$ formula is option D.

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