iGCSE Chemistry 0620 Extended - 10.2 Fertilisers- Exam Style Questions Paper 4- New Syllabus
Question

Most-appropriate topic codes (Cambridge IGCSE Chemistry 0620):
• Topic 8.2 — Periodicity / Topic 9.5 — Extraction of Metals (Part (a)(i), (a)(ii) & (a)(iv))
• Topic 10.2 — Water supply and water treatment (Part (a)(iii))
• Topic 10.3 — Air quality and climate (Part (a)(v))
• Topic 6.4 — Redox reactions (Part (a)(vi))
• Topic 2.2 — Isotopes and relative atomic mass (Part (b)(i) & (b)(ii))
• Topic 2.1 — Atomic structure (Part (c)(i) & (c)(ii))
▶️ Answer/Explanation
(a)(i) Al
Bauxite serves as the primary metal mineral source for extracting pure aluminium. It goes through intermediate chemical upgrades to clean out solid iron impurities prior to down-stream electrolysis.
(a)(ii) Ar
Argon is an unreactive noble gas situated at the far right edge of Period 3. Because its valence ring contains a completed octet layout, it remains extremely inert and chemically detached.
(a)(iii) Cl
Chlorine acts as a highly effective antimicrobial treatment chemical. Municipal utilities disperse tiny trace doses throughout raw water to sterilize bacterial cells and secure clean tap delivery.
(a)(iv) Al
Aluminium oxide ($\text{Al}_2\text{O}_3$) behaves as an amphoteric chemical species. This lets it neutralize acidic compounds as well as highly alkaline bases during chemical processing.
(a)(v) S
Sulfur burns to generate sulfur dioxide gas. Once launched into cloud moisture layers, this compound oxidizes into acid rain mixtures that can impact environmental ecosystems.
(a)(vi) Cl
Chlorine holds a strong electron affinity compared to hydrogen. Within hydrogen chloride gas, the chlorine atom pulls shared electron density close to itself, claiming a $-1$ oxidation state.
(b)(i) Carbon-12 (${}^{12}\text{C}$)
The common reference baseline globally for all relative atomic weights is standard Carbon-12. This particular atomic isotope acts as the perfect benchmark for comparing mass quantities safely.
(b)(ii) 24.3
We calculate the weighted average based on isotopic masses and how often they appear in nature: $$\text{A}_r = \frac{(24 \times 85) + (26 \times 15)}{100} = \frac{2040 + 390}{100} = 24.3$$
(c)(i) 27
The nucleon count is found by adding together the total number of protons and neutrons located inside the atomic nucleus. Adding them together gives $13 \text{ protons} + 14 \text{ neutrons} = 27$.
(c)(ii) Aluminium / Al
The definitive identification for any element is governed by its proton count. Finding exactly 13 protons in the nucleus matches exclusively with the atomic properties of aluminium.
