Home / iGCSE Mathematics (0580) : C1.3 Calculate with squares, square roots, cubes and cube roots and other powers and roots of numbers. iGCSE Style Questions Paper 1

iGCSE Mathematics (0580) : C1.3 Calculate with squares, square roots, cubes and cube roots and other powers and roots of numbers. iGCSE Style Questions Paper 1

Question

Find the value of the reciprocal of $0.4$ .

▶️Answer/Explanation

2.5 oe

$
\text{Reciprocal of } 0.4 = \frac{1}{0.4}
$

convert 0.4 to a fraction

$
0.4 = \frac{4}{10} = \frac{2}{5}
$

the reciprocal of the fraction

$
\frac{1}{\frac{2}{5}} = \frac{5}{2}
$
$
\frac{5}{2} = 2.5
$

Question 

(a) Work out. 

\(28-16\div 2\)

(b) Find the reciprocal of \(\frac{4}{5}\).

▶️Answer/Explanation

Ans:

(a) 20 

(b) 1.25 or \(1\frac{1}{4}\)

(a)
Follow the order of operations (BIDMAS/BODMAS):
Division comes before subtraction
$16 \div 2 = 8$
$28 – 8 = 20$

(b)

The reciprocal of a fraction means flipping it (swap the numerator and denominator):

$\text{Reciprocal of } \frac{4}{5} = \frac{5}{4}$

Question

Find the value of
(a) \(9^4\),
(b) \(6^0\)

▶️Answer/Explanation

(a) \(9^{4}=4\times 4\times 4\times 4=6561\)
(b) Any non-zero number raised to the power of zero is equal to 1. Therefore, \(6^{0}=1\)

Question

(a) Calculate \(\sqrt{5.7} – 1.03^2\).
Write down all the numbers displayed on your calculator.
(b) Write your answer to part (a) correct to 3 decimal places.

▶️Answer/Explanation

(a) Using a calculator, we get \(\sqrt{5.7} – 1.03^2= 2.387467277 – 1.0609= 1.326567277\)
(b) Rounding the answer to 3 decimal places ,we get \(\sqrt{5.7} – 1.03^2\approx 1.327\)

Question

By writing each number correct to 1 significant figure, estimate the value of \(\frac{\sqrt{3.9}\times 29.3}{8.9-2.7}.\)

Show all your working.

▶️Answer/Explanation

Here,we have to round of each number to 1 significant figure.So,
significant figure for 3.9 is 4
significant figure for 29.3 is 29
significant figure for 8.9 is 9
significant figure for 2.7 is 3
\(\frac{\sqrt{4}\times 29}{9-3}\)=\(9.66\approx 10\)

Question

Calculate.
\(3.2\times \left ( 5.7-1.3 \right )+4.8\)

▶️Answer/Explanation

We can evaluate the expression by using order of operations (PEMDAS) as follows,
First, we evaluate the expression inside the parentheses
5.7−1.3=4.4
Now, we multiply \(3.2\times 4.4=14.08\)
Finally, we add 14.08+4.8=18.88
Therefore,
\(3.2\times \left ( 5.7-1.3 \right )+4.8=18.88\)

(b) \(\sqrt{2.54-0.85}\)

▶️Answer/Explanation

We can start by evaluating the expression inside the square root 2.54-0.85=1.69
So now we have
\(\sqrt{2.54-0.85}=\sqrt{1.69}=1.3\)
Therefore, the answer is 1.3

Question

(a) Find the value of $p$ when $p^3=-27$.
(b) Find the value of $q$ when $q^{-1}=\frac{1}{6}$.
(c) Simplify $8 s^2 \div 2 s^{-1}$.

▶️Answer/Explanation

(a) -3 final answer
(b) 6 final answer
(c) $4 s^3$ or $\frac{4}{s^{-3}}$ final answer

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