Home / iGCSE Mathematics (0580) : C2.4 Use and interpret positive, negative and zero indices. iGCSE Style Questions Paper 3

iGCSE Mathematics (0580) : C2.4 Use and interpret positive, negative and zero indices. iGCSE Style Questions Paper 3

Question

(a) Work out \(48\div 3-5\times 2\).

(b) Insert one pair of brackets to make this statement correct.

3 + 2 × 12 – 4 = 19

(c) Write the following in order, starting with the smallest.

\(\frac{3}{4}\)  0.749  76%

(d) Find the value of [1 each]

(i) \(\sqrt{265.69}\)

(ii) 83

(e) Write down the smallest prime number.

(f) Write down all the factors of 18.

(g) Write down a common factor of 16 and 72 that is greater than 2.

(h) Write \(\frac{28}{140}\) as a fraction in its simplest form. 

(i) Jeff and his friends win a prize.
Jeff’s share is $160 which is \(\frac{5}{11}\) of the prize.
Work out the value of the prize.

▶️ Answer/Explanation
Solution

(a) Ans: 6

Using BIDMAS/BODMAS rules:
48 ÷ 3 = 16
5 × 2 = 10
16 – 10 = 6

(b) Ans: 3 + 2 × (12 – 4) = 19

Calculation:
12 – 4 = 8
2 × 8 = 16
3 + 16 = 19

(c) Ans: 0.749, \(\frac{3}{4}\), 76%

Convert all to decimals:
\(\frac{3}{4}\) = 0.75
76% = 0.76
Order: 0.749, 0.75, 0.76

(d)

(i) Ans: 16.3 (since 16.3 × 16.3 = 265.69)

(ii) Ans: 512 (8 × 8 × 8)

(e) Ans: 2

2 is the smallest and only even prime number

(f) Ans: 1, 2, 3, 6, 9, 18

Numbers that divide exactly into 18

(g) Ans: 4 or 8

Common factors of 16 (1,2,4,8,16) and 72 (1,2,3,4,6,8,9,12,18,24,36,72) >2

(h) Ans: \(\frac{1}{5}\)

Simplify by dividing numerator and denominator by 28

(i) Ans: $352

Let P = prize value
\(\frac{5}{11}\)P = 160 → P = 160 × \(\frac{11}{5}\) = 352

Question

(a) Write one hundred and twenty thousand and twenty in figures.

(b) Find the value of \( \sqrt{3481} \).

(c)

(i) Write down the fraction of the rectangle that is shaded.

(ii) Find the percentage of the rectangle that is not shaded.

(d) Write these numbers in order, starting with the smallest:
27%, \( \frac{5}{17} \), 0.268, \( \frac{7}{29} \)

(e) Write 0.3728 correct to 1 decimal place.

(f) Write down the value of \(19^\circ\).

(g) The height, h metres, of a tower is 128m, correct to the nearest metre.
Complete the statement about the value of h.

(h) Find the highest common factor (HCF) of 126 and 180.

(i) Write down an irrational number with a value between 6 and 7.

▶️ Answer/Explanation
Solution

(a) Ans: 120,020

One hundred twenty thousand = 120,000
And twenty = 20
Combined: 120,000 + 20 = 120,020

(b) Ans: 59

59 × 59 = 3,481
Therefore, \( \sqrt{3481} = 59 \)

(c)(i) Ans: \( \frac{5}{8} \)

Total parts = 8
Shaded parts = 5
Fraction shaded = \( \frac{5}{8} \)

(c)(ii) Ans: 37.5%

Unshaded fraction = \( \frac{3}{8} \)
Percentage unshaded = \( \frac{3}{8} \times 100 = 37.5\% \)

(d) Ans: \( \frac{7}{29} \) < 0.268 < 27% < \( \frac{5}{17} \)

Convert all to decimals:
\( \frac{7}{29} \approx 0.241 \)
0.268
27% = 0.27
\( \frac{5}{17} \approx 0.294 \)

(e) Ans: 0.4

0.3728 rounded to 1 decimal place:
Look at second decimal (7) which ≥5, so round up:
0.4

(f) Ans: 1

Any non-zero number to the power of 0 equals 1:
\(19^\circ = 1\)

(g) Ans: 127.5 ≤ h < 128.5

When rounded to nearest meter (128m), the actual height h satisfies:
127.5m ≤ h < 128.5m

(h) Ans: 18

Prime factors:
126 = 2 × 3² × 7
180 = 2² × 3² × 5
Common factors: 2 × 3² = 18

(i) Ans: \( \sqrt{37} \) (or any other irrational between 6 and 7)

Since \( \sqrt{36} = 6 \) and \( \sqrt{49} = 7 \),
\( \sqrt{37} \approx 6.08276… \) is irrational and between 6 and 7

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