Home / CIE iGCSE Maths C2.4 Indices II – Exam Style Practice Questions- Paper 3

CIE iGCSE Maths C2.4 Indices II - Exam Style Practice Questions- Paper 3- New Syllabus

Question

Simplify.

(a) $(w^3)^{10}$

(b) $t^6 v^7 \times t^3 v^{-2}$

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

• TOPIC C2.4 Indices: Use rules of indices to simplify algebraic expressions (Core)
▶️ Answer/Explanation

(a)
When raising a power to another power, you simply multiply the exponents: $3 \times 10 = 30$.
✅ Answer: $w^{30}$

(b)
When multiplying terms with the same base, you add their exponents.
For $t$: $6 + 3 = 9$. For $v$: $7 + (-2) = 5$.
✅ Answer: $t^9 v^5$

Question

(a) Work out \(48\div 3-5\times 2\).

(b) Insert one pair of brackets to make this statement correct.

3 + 2 × 12 – 4 = 19

(c) Write the following in order, starting with the smallest.

\(\frac{3}{4}\)  0.749  76%

(d) Find the value of [1 each]

(i) \(\sqrt{265.69}\)

(ii) 83

(e) Write down the smallest prime number.

(f) Write down all the factors of 18.

(g) Write down a common factor of 16 and 72 that is greater than 2.

(h) Write \(\frac{28}{140}\) as a fraction in its simplest form. 

(i) Jeff and his friends win a prize.
Jeff’s share is $160 which is \(\frac{5}{11}\) of the prize.
Work out the value of the prize.

▶️ Answer/Explanation
Solution

(a) Ans: 6

Using BIDMAS/BODMAS rules:
48 ÷ 3 = 16
5 × 2 = 10
16 – 10 = 6

(b) Ans: 3 + 2 × (12 – 4) = 19

Calculation:
12 – 4 = 8
2 × 8 = 16
3 + 16 = 19

(c) Ans: 0.749, \(\frac{3}{4}\), 76%

Convert all to decimals:
\(\frac{3}{4}\) = 0.75
76% = 0.76
Order: 0.749, 0.75, 0.76

(d)

(i) Ans: 16.3 (since 16.3 × 16.3 = 265.69)

(ii) Ans: 512 (8 × 8 × 8)

(e) Ans: 2

2 is the smallest and only even prime number

(f) Ans: 1, 2, 3, 6, 9, 18

Numbers that divide exactly into 18

(g) Ans: 4 or 8

Common factors of 16 (1,2,4,8,16) and 72 (1,2,3,4,6,8,9,12,18,24,36,72) >2

(h) Ans: \(\frac{1}{5}\)

Simplify by dividing numerator and denominator by 28

(i) Ans: $352

Let P = prize value
\(\frac{5}{11}\)P = 160 → P = 160 × \(\frac{11}{5}\) = 352

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