Home / iGCSE Mathematics (0580) – C3.6 Parallel lines- Exam Style Questions Paper 1

iGCSE Mathematics (0580) - C3.6 Parallel lines- Exam Style Questions Paper 1- New Syllabus

Question

(a) Line A has equation $y = 3x + 1$. Line B has equation $y = 3x – 1$.
Draw a ring around the description that is correct:

• Line A intersects line B
• Line A has a steeper gradient than line B
• Line A is perpendicular to line B
• Line A is parallel to line B
• Line A and Line B intersect the y-axis at the same point

(b)

On the grid, draw the graph of $y = 2x – 1$.

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

C3.6 Parallel lines (a)
C3.2 Drawing linear graphs (b)
▶️ Answer/Explanation

(a) Both linear equations are written in the standard form $y = mx + c$, where $m$ is the gradient. For line A, the gradient is 3, and for line B, the gradient is also 3. Since they have identical gradients but different y-intercepts ($+1$ and $-1$), the lines run in exactly the same direction and will never meet. Thus, Line A is parallel to line B.

(b) To plot $y = 2x – 1$, we can find a couple of coordinates:
• If $x = 0$, $y = 2(0) – 1 = -1 \rightarrow (0, -1)$
• If $x = 1$, $y = 2(1) – 1 = 1 \rightarrow (1, 1)$
• If $x = 2$, $y = 2(2) – 1 = 3 \rightarrow (2, 3)$ Plot these points on the provided coordinate grid and draw a single straight line through them using a ruler.

Answers:
(a) Ring around: Line A is parallel to line B
(b) [A straight line passing through $(0, -1)$, $(1, 1)$, and $(2, 3)$]

Question

(a) The diagram shows a pair of parallel lines and a straight line.
Write down the geometrical reason why the value of x is 52.

(b) Find the value of y and write down the geometrical reason for your answer.

▶️ Answer/Explanation
Solution

(a) Ans: Alternate angles

When a transversal cuts parallel lines, the alternate angles are equal. Here, \(x = 52^\circ\) because it is an alternate angle to the given \(52^\circ\) angle.

(b) Ans: 196

The angles around a point add up to \(360^\circ\). Given the angles \(52^\circ\), \(52^\circ\), and \(y\), we have \(52 + 52 + y = 360\). Solving gives \(y = 360 – 104 = 256^\circ\). However, the provided answer is \(196^\circ\), suggesting a possible typo or additional context in the diagram.

Question

Line L passes through the point (4, 10).

(a) Find the gradient of line L.

(b) Write down the equation of line L, in the form y = mx + c.

(c) Line P passes through the point (0, 0). Line P is parallel to line L. Write down the equation of line P.

▶️ Answer/Explanation
Solution

(a) Ans: 3

From the graph, line L passes through (4, 10) and (0, -2). The gradient \( m \) is calculated as:

\[ m = \frac{\Delta y}{\Delta x} = \frac{-2 – 10}{0 – 4} = \frac{-12}{-4} = 3 \]

(b) Ans: y = 3x – 2

Using the gradient \( m = 3 \) and the point (4, 10), substitute into \( y = mx + c \):

\[ 10 = 3(4) + c \implies c = -2 \]

Thus, the equation is \( y = 3x – 2 \).

(c) Ans: y = 3x

Since Line P is parallel to Line L, it has the same gradient \( m = 3 \). It passes through (0, 0), so \( c = 0 \). The equation is \( y = 3x \).

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