Home / iGCSE Mathematics (0580) – C4.6 Angles- Exam Style Questions Paper 3

iGCSE Mathematics (0580) - C4.6 Angles- Exam Style Questions Paper 3- New Syllabus

Question

(a)

Write down the mathematical name for this type of angle.

(b) ABC is a triangle.


Lily says $x$ is $34$.
Give a geometrical reason why Lily is not correct.

(c)

ABCD is a quadrilateral. DCE is a straight line.
The interior angles are $48^\circ$, $126^\circ$, $75^\circ$, and angle BCD. Angle BCE is labeled $x^\circ$.
Calculate the value of $x$.

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

• C4.1 Geometrical terms (a)
• C4.6 Angles (b,c)
▶️ Answer/Explanation

(a)
An angle greater than $180^\circ$ and less than $360^\circ$ is a reflex angle.
✅ Answer: reflex

(b)
Sum the angles: $102 + 54 + 34 = 190^\circ$. This exceeds the sum of angles in a triangle.
✅ Answer: Angles in a triangle must add up to $180^\circ$.

(c)
First, find the interior angle BCD of the quadrilateral. The sum of angles in a quadrilateral is $360^\circ$.
$\text{Angle BCD} = 360^\circ – (126^\circ + 48^\circ + 75^\circ) = 360^\circ – 249^\circ = 111^\circ$
Since DCE is a straight line, angles on a straight line add to $180^\circ$.
$x = 180^\circ – 111^\circ = 69^\circ$
✅ Answer: $x = 69$

Question

(a) Work out the size of one interior angle of a regular 8-sided polygon.

(b)

A, B and C lie on the circumference of the circle, centre O.
AB is a diameter.
DBE is a tangent to the circle at B.
Angle BAC is unlabelled, angle ACB is on the circumference. Angle CBA is given as $71^\circ$. The angle between chord BC and tangent BD is labeled $x^\circ$.

Find the value of $x$.
Give a geometrical reason for your answer.

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

• C4.6 Angles (a,b)
• C4.7 Circle theorems (b)
▶️ Answer/Explanation

(a)
Total interior angle sum $= (8 – 2) \times 180^\circ = 6 \times 180^\circ = 1080^\circ$
One interior angle = $\frac{1080^\circ}{8} = 135^\circ$
✅ Answer: $135^\circ$

(b)
The angle between a tangent and a radius (or diameter) is $90^\circ$. So, angle ABE = $90^\circ$ and angle ABD = $90^\circ$.
Since the whole angle from diameter AB to tangent BD is $90^\circ$, and angle ABC is given as $71^\circ$,
$x = 90^\circ – 71^\circ = 19^\circ$
✅ Answer: $x = 19$ because the angle between the tangent and radius is $90^\circ$.

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