Home / iGCSE Mathematics (0580) – C9.1 Classifying statistical data- Exam Style Questions Paper 3

iGCSE Mathematics (0580) - C9.1 Classifying statistical data- Exam Style Questions Paper 3- New Syllabus

IGCSE Mathematics(0580) Practice Questions Paper 3 - All Chapters

Question

A newspaper prints this bar chart to show the number of cars sold by a garage in March, April and May.

Give two reasons why the bar chart is incorrect.

Most-appropriate topic codes (Cambridge IGCSE Mathematics 0580):

• TOPIC C9.1 Statistics: Interpret and draw inferences from statistical diagrams (Core)
▶️ Answer/Explanation

When analyzing the vertical axis scale, we can see that the numerical gaps between gridlines change inconsistently.
The intervals jump from tens to twenty-fives arbitrarily, meaning the vertical scale is non-linear.
Additionally, the individual rectangular bars drawn for each month vary in horizontal width, which breaks standard charting rules.
✅ Answer: 1. Bar width not equal. 2. Scale is not linear.

Question

(a) One day a survey is taken of the ages of 120 children at a fairground.
The results are shown in the frequency table.

(i) On the grid, draw a bar chart for this data.
Complete the scale on the frequency axis.

(ii) What is the modal age group?

(iii) One of the 120 children is chosen at random.
Write down the probability that the child is aged 4 to 6.

(b) Lalia says the probability of taking a yellow bead from a bag containing yellow beads and black beads is \(\frac{7}{5}.\)

Explain why \(\frac{7}{5}\) cannot be a correct probability

(c) Another bag contains 9 green marbles and 11 red marbles.
A marble is taken at random.
Write down the probability that the marble is
(i) green,
(ii) blue.

▶️ Answer/Explanation
Solution

(a)(i) Ans: Correct diagram with scale

Draw bars for each age group (4-6: height 19, 7-9: height 28, 10-12: height 42, 13-15: height 31). Label frequency axis up to at least 42.

(a)(ii) Ans: 10 to 12 cao

The modal age group is the one with the highest frequency. Here, 10-12 has 42 children, which is the largest.

(a)(iii) Ans: \(\frac{19}{120}\) or 0.158[3….] or 15.8[3……]%

Probability = \(\frac{\text{Frequency of 4-6}}{\text{Total children}} = \frac{19}{120}\).

(b) Ans: Probability must be between 0 and 1 oe

\(\frac{7}{5} = 1.4\), which exceeds 1. Probabilities range from 0 (impossible) to 1 (certain).

(c)(i) Ans: \(\frac{9}{20}\) or 0.45 or 45%

Total marbles = 9 green + 11 red = 20. P(green) = \(\frac{9}{20}\).

(c)(ii) Ans: 0 oe

There are no blue marbles, so the probability is 0.

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