(a) On the diagram, sketch the graph of \(y=\cos x\) for \(0^{\circ}\leq x\leq 360^{\circ}.\)
(b) Solve the equation \(4\cos x+2=3\) for \(0^{\circ}\leq x\leq 360^{\circ}.\)
x = ……………….. and x = ………………..
▶️ Answer/Explanation
(a)
The graph of \(y = \cos x\) for \(0^{\circ} \leq x \leq 360^{\circ}\) is a wave starting at \((0^{\circ}, 1)\), decreasing to \((180^{\circ}, -1)\), and returning to \((360^{\circ}, 1)\). Key points: peaks at \(0^{\circ}\) and \(360^{\circ}\), trough at \(180^{\circ}\), and zeros at \(90^{\circ}\) and \(270^{\circ}\).
(b) Ans: 75.5° and 284.5°
Rearrange the equation: \(4\cos x + 2 = 3 \implies \cos x = \frac{1}{4}\).
Find the principal solution: \(x = \cos^{-1}(0.25) \approx 75.52^{\circ}\).
Using the symmetry of the cosine function, the second solution is \(x = 360^{\circ} – 75.52^{\circ} \approx 284.48^{\circ}\).
Calculate the area of this triangle.
………………………… \(\text{cm}^2\)
▶️ Answer/Explanation
Ans: 130 or 130.0 to 130.1
First, identify the base (20 cm) and height (13 cm) from the given triangle.
Use the area formula for a triangle: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \).
Substitute the values: \( \text{Area} = \frac{1}{2} \times 20 \times 13 = 130 \text{ cm}^2 \).
The area of the triangle is \(\boxed{130}\) cm².