Home / iGCSE Mathematics (0580) :E6.3 Recognise, sketch and interpret graphs of simple trigonometric functions.iGCSE Style Questions Paper 2

iGCSE Mathematics (0580) :E6.3 Recognise, sketch and interpret graphs of simple trigonometric functions.iGCSE Style Questions Paper 2

Question

(a) On the diagram, sketch the graph of \(y=\cos x\) for \(0^{\circ}\leq x\leq 360^{\circ}.\)

(b) Solve the equation \(4\cos x+2=3\) for \(0^{\circ}\leq x\leq 360^{\circ}.\)
x = ……………….. and x = ………………..

▶️ Answer/Explanation
Solution

(a)

The graph of \(y = \cos x\) for \(0^{\circ} \leq x \leq 360^{\circ}\) is a wave starting at \((0^{\circ}, 1)\), decreasing to \((180^{\circ}, -1)\), and returning to \((360^{\circ}, 1)\). Key points: peaks at \(0^{\circ}\) and \(360^{\circ}\), trough at \(180^{\circ}\), and zeros at \(90^{\circ}\) and \(270^{\circ}\).

(b) Ans: 75.5° and 284.5°

Rearrange the equation: \(4\cos x + 2 = 3 \implies \cos x = \frac{1}{4}\).

Find the principal solution: \(x = \cos^{-1}(0.25) \approx 75.52^{\circ}\).

Using the symmetry of the cosine function, the second solution is \(x = 360^{\circ} – 75.52^{\circ} \approx 284.48^{\circ}\).

Question

Calculate the area of this triangle.

………………………… \(\text{cm}^2\)

▶️ Answer/Explanation
Solution

Ans: 130 or 130.0 to 130.1

First, identify the base (20 cm) and height (13 cm) from the given triangle.

Use the area formula for a triangle: \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \).

Substitute the values: \( \text{Area} = \frac{1}{2} \times 20 \times 13 = 130 \text{ cm}^2 \).

The area of the triangle is \(\boxed{130}\) cm².

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