Home / iGCSE Physics (0625) 2.2.2 Specific heat capacity-Exam Style Questions

iGCSE Physics (0625) 2.2.2 Specific heat capacity -Exam Style Questions Paper 1 - New Syllabus

Question

When a hot gas cools, its internal energy decreases.
What causes this?
A. a decrease in the average kinetic energy of the gas particles
B. a decrease in the gravitational potential energy of the gas particles
C. an increase in the average speed of the gas particles
D. an increase in the average distance of separation of the gas particles
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

Temperature is a macroscopic measure of the average kinetic energy of the particles in a substance.
When a gas cools, its temperature $\theta$ decreases, which directly corresponds to a reduction in the average kinetic energy $E_{k}$ of its constituent molecules.
The internal energy of an ideal gas is primarily determined by the sum of the kinetic energies of all its particles.
Therefore, a decrease in internal energy during cooling is caused by the particles moving more slowly on average.
Option C and D describe changes that would typically increase energy or occur during expansion, while B is irrelevant to thermal cooling.
Thus, the decrease in internal energy is due to a decrease in the average kinetic energy of the gas particles.

Question

A student has two blocks of metal, \(\mathrm{X}\) and \(\mathrm{Y}\). The temperature of \(\mathrm{X}\) is \(50^{\circ} \mathrm{C}\) and the temperature of \(\mathrm{Y}\) is \(0^{\circ} \mathrm{C}\).
The two blocks are placed in contact with each other, as shown.
After some time, both blocks have a temperature of \(25^{\circ} \mathrm{C}\).
What has happened to the internal energy of each block?
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Block X cools from \(50^{\circ}\mathrm{C}\) to \(25^{\circ}\mathrm{C}\), so its particles lose kinetic energy and its internal energy decreases.
Block Y warms from \(0^{\circ}\mathrm{C}\) to \(25^{\circ}\mathrm{C}\), so its particles gain kinetic energy and its internal energy increases.
Energy is transferred thermally from the hotter block to the colder block until thermal equilibrium is reached.
Therefore, the internal energy of X decreases and the internal energy of Y increases.
This matches Option B.

Question
The air temperature rises from $10^\circ\text{C}$ to $40^\circ\text{C}$.
What is the change in temperature, expressed in kelvin?
A. $30\text{ K}$
B. $50\text{ K}$
C. $243\text{ K}$
D. $303\text{ K}$
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

To find the change in temperature, we first calculate the difference in degrees Celsius: $40^\circ\text{C} – 10^\circ\text{C} = 30^\circ\text{C}$.
It is a fundamental rule in physics that a change of $1$ degree Celsius is exactly equal to a change of $1$ kelvin.
Even if you convert both temperatures to kelvin first ($10^\circ\text{C} = 283\text{ K}$ and $40^\circ\text{C} = 313\text{ K}$), the difference remains the same.
Subtracting these values gives: $313\text{ K} – 283\text{ K} = 30\text{ K}$.
Therefore, the change in temperature expressed in kelvin is $30\text{ K}$, which matches Option A.

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