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Mock Exam IB DP Chemistry HL Paper 1 Set 5

Question

Which pairs of reactants could produce the following intermediate?


A. I and II only
B. I and III only
C. II and III only
D. I, II and III

Answer/Explanation

Markscheme: A

Question

Which terms describe the nitronium ion in the nitration of benzene?

▶️Answer/Explanation

Markscheme: D

In the nitration of benzene, the nitronium ion (\(\rm NO_2^+\)) acts as an electrophile. Electrophiles are species that are electron-deficient and seek electrons from other molecules. The nitronium ion is attracted to the electron-rich benzene ring and acts as an electrophile in the reaction.

So, the correct terms describing the nitronium ion in the nitration of benzene are:

 Type of reactant: Electrophile
 Acid-base nature: Lewis acid

Question

What is the percentage error if the enthalpy of combustion of a substance is determined experimentally to be -2100kJ \(mol^{-1}\) , but the literature value is -3500kJ \(mol^{-1}\)?

A. 80%
B. 60%
C. 40%
D. 20%

▶️Answer/Explanation

Markscheme: C

The percentage error is calculated using the formula:

\[ \text{Percentage Error} = \left| \frac{\text{Experimental Value} – \text{Literature Value}}{\text{Literature Value}} \right| \times 100\]

Given:
– Experimental Value = -2100 kJ/mol
– Literature Value = -3500 kJ/mol

\[ \text{Percentage Error} = \left| \frac{-2100 – (-3500)}{-3500} \right| \times 100\]

\[ \text{Percentage Error} = \left| \frac{1400}{3500} \right| \times 100\]

\[ \text{Percentage Error} = \frac{2}{5} \times 100\]

\[ \text{Percentage Error} = 40\%\]

Question

Which molecule produces this \(^1H-NMR\) spectrum?

A. \(CH_3COOCH_3\)
B. \(CH_3COCH_3\)
C. \(CH_3CHO\)
D. \(CH_3CH_2CH_3\)

Answer/Explanation

Markscheme: B

Question

What is the index of hydrogen deficiency of adenine?

A. 3
B. 4
C. 5
D. 6

▶️Answer/Explanation

Markscheme: D

The index of hydrogen deficiency (IHD), also known as the degree of unsaturation or double bond equivalent, can be calculated using the formula:

\[IHD = \frac{{2C + 2 + N – H – X}}{2}\]

where:
 \(C\) is the number of carbon atoms,
 \(N\) is the number of nitrogen atoms,
 \(H\) is the number of hydrogen atoms, and
\(X\) is the number of halogen atoms (Cl, Br, I).

For adenine, the molecular formula is \(C_5H_5N_5\). Applying these values to the formula:

\[IHD = \frac{{2(5) + 2 + 5 – 5 – 0}}{2} = \frac{{12}}{2} = 6\]

So, the index of hydrogen deficiency (IHD) for adenine is 6.

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