SAT MAth Practice questions – all topics
- Problem-solving and Data Analysis Weightage: 15% Questions: 5-7
- Ratios, rates, proportional relationships, and units
- Percentages
- One-variable data: distributions and measures of centre and spread
- Two-variable data: models and scatterplots
- Probability and conditional probability
- Inference from sample statistics and margin of error
- Evaluating statistical claims: observational studies and Experiments
SAT MAth and English – full syllabus practice tests
Question Easy
Each face of a fair number cube is labeled with a number from 1 through 6 , with a different number appearing on each face. If the number cube is rolled one time, what is the probability that the number 2 will be shown on the top face?
A) \(\frac{1}{6}\)
B) \(\frac{2}{6}\)
C) \(\frac{4}{6}\)
D) \(\frac{5}{6}\)
▶️Answer/Explanation
Ans:A
Each face of a fair number cube is labeled with a number from 1 through 6, with each number appearing exactly once. The question asks for the probability that the number 2 will be shown on the top face when the cube is rolled once.
Since the number cube has 6 faces, each face has an equal probability of landing on the top face. The probability \(P\) of any specific face (in this case, the face with the number 2) landing on top is given by:
\[
P(\text{number 2 on top}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{6}
\]
Therefore, the correct answer is:
\[
\boxed{\frac{1}{6}}
\]
Question Easy
A certain rock band released 20 music albums from 1963 to 1970, as shown in the bar graph. If one of these albums is selected at random, what is the probability of selecting an album that was released in 1964? (Express your answer as a decimal or fraction, not as a percent.)
▶️Answer/Explanation
Ans:7 / 20, .35
Total number of albums released:
According to the bar graph, the number of albums released each year from 1963 to 1970 is as follows:
1963: 2 albums
1964: 7 albums
1965: 3 albums
1966: 3 albums
1967: 2 albums
1968: 1 album
1969: 1 album
1970: 1 album
\[
2+7+3+3+2+1+1+1=20 \text { albums }
\]
Number of albums released in 1964 :- 7 albums
\[
P=\frac{\text { Number of albums released in } 1964}{\text { Total number of albums }}=\frac{7}{20}
\]
Thus, the probability of selecting an album that was released in 1964 is:
\[
\frac{7}{20}
\]
Question Easy
In a group of 8 children, 2 have freckles and 6 do not have freckles. If one of the 8 children is selected at random, what is the probability of selecting a child who has freckles?
A. 0.25
B. 0.33
C. 0.50
D. 0.75
▶️Answer/Explanation
Ans: A
Total number of children: 8
Number of children with freckles: 2
\[
\text{Probability} = \frac{\text{Number of children with freckles}}{\text{Total number of children}} = \frac{2}{8} = \frac{1}{4} = 0.25
\]
So, the diameter of Saturn, to the nearest ten thousand kilometers, is:
\[
\boxed{120,000}
\]
Question Easy
The table summarizes the number of public schools in two California counties in 2017.
A public middle school will be selected at random from the two counties. What is the probability, to the nearest hundredth, of selecting a school in San Diego County?
A)0.05
B)0.19
C)0.28
D)0.69
▶️Answer/Explanation
C)0.28
The table summarizes the number of public schools in two California counties in 2017. We need to find the probability of selecting a public middle school in San Diego County.
From the table, the number of middle schools in San Diego County is 165, and the total number of middle schools in both counties is 587.
The probability \(P\) of selecting a middle school in San Diego County is given by:
\[ P = \frac{\text{Number of middle schools in San Diego}}{\text{Total number of middle schools}} \]
\[ P = \frac{165}{587} \]
Calculating this value to the nearest hundredth:
\[ P \approx \frac{165}{587} \approx 0.281 \]
Rounding to the nearest hundredth:
\[ P \approx 0.28 \]
The correct answer is C) 0.28.
Questions Easy
The probability of an unfair coin landing heads side up is 0.6. A student tossed this coin into the air9 times. It landed tails side up 5 times and heads side up 4 times. What is the probability that the coin will
land heads side up on the 10th toss?
A) 0.4
B) 0.5
C) 0.6
D) 1
▶️Answer/Explanation
Ans: C
The probability of the unfair coin landing heads side up is given as 0.6. This probability is intrinsic to the coin and does not change with previous outcomes. Thus, regardless of the results of the previous 9 tosses, the probability that the coin will land heads side up on the 10th toss remains: \[ \boxed{0.6} \]