IB DP Chemistry Reactivity 1.2 Energy cycles in reactions IB Style Question Bank SL Paper 1

Question

Consider the following equations.

     \({\text{2Fe(s)}} + {\text{1}}\frac{1}{2}{{\text{O}}_{\text{2}}}{\text{(g)}} \to {\text{F}}{{\text{e}}_{\text{2}}}{{\text{O}}_{\text{3}}}{\text{(s) }}\)     \(\Delta {{\text{H}}^\Theta } = x\)

     \({\text{CO(g)}} + \frac{1}{2}{{\text{O}}_{\text{2}}}{\text{(g)}} \to {\text{C}}{{\text{O}}_{\text{2}}}{\text{(g)}}\)     \(\Delta {{\text{H}}^\Theta } = y\)

What is the enthalpy change of the reaction below?

\[{\text{F}}{{\text{e}}_{\text{2}}}{{\text{O}}_{\text{3}}}{\text{(s)}} + {\text{3CO(g)}} \to {\text{3C}}{{\text{O}}_{\text{2}}}{\text{(g)}} + {\text{2Fe(s)}}\]

A.     \(3y – x\)

B.     \(3y + x\)

C.     \( – 3y – x\)

D.     \( – 3y + x\)

Answer/Explanation

Markscheme

A

Examiners report

This question was answered correctly by nearly 85% of the candidates which was encouraging.

Question

Hydrazine reacts with oxygen.

N2H4(l) + O2(g) → N2(g) + 2H2O(l)      ΔHθ = -623 kJ

What is the standard enthalpy of formation of N2H4(l) in kJ? The standard enthalpy of formation of H2O(l) is -286 kJ.

A. -623 – 286
B. -623 + 572
C. -572 + 623
D. -286 + 623

Answer/Explanation

Markscheme

C

Examiners report

[N/A]

Question

What is the enthalpy of combustion of butane in kJ mol1?

2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l)

\[\begin{array}{*{20}{l}} {{\text{C(s)}} + {{\text{O}}_2}{\text{(g)}} \to {\text{C}}{{\text{O}}_2}{\text{(g)}}}&{\Delta H = x{\text{ kJ}}} \\ {{{\text{H}}_2}{\text{(g)}} + \frac{{\text{1}}}{2}{{\text{O}}_2}{\text{(g)}} \to {{\text{H}}_2}{\text{O(l)}}}&{\Delta H = y{\text{ kJ}}} \\ {4{\text{C(s)}} + {\text{5}}{{\text{H}}_2}{\text{(g)}} \to {{\text{C}}_4}{{\text{H}}_{{\text{10}}}}{\text{(g)}}}&{\Delta H = z{\text{ kJ}}} \end{array}\]

A.     4x + 5y z 

B.     4x + 5y + z 

C.     8x + 10y − 2z 

D.     8x + 5y + 2z

Answer/Explanation

Markscheme

A

Examiners report

[N/A]

Question

Enthalpy changes of reaction are provided for the following reactions.

\[\begin{array}{*{20}{l}} {{\text{2C(s)}} + {\text{2}}{{\text{H}}_2}{\text{(g)}} \to {{\text{C}}_2}{{\text{H}}_4}{\text{(g)}}}&{\Delta {H^\Theta } =  + {\text{52 kJ}}\,{\text{mo}}{{\text{l}}^{ – 1}}} \\ {{\text{2C(s)}} + {\text{3}}{{\text{H}}_2}{\text{(g)}} \to {{\text{C}}_2}{{\text{H}}_6}{\text{(g)}}}&{\Delta {H^\Theta } =  – {\text{85 kJ}}\,{\text{mo}}{{\text{l}}^{ – 1}}} \end{array}\]

What is the enthalpy change, in \({\text{kJ}}\,{\text{mo}}{{\text{l}}^{ – 1}}\), for the reaction between ethene and hydrogen?

\[{{\text{C}}_2}{{\text{H}}_4}{\text{(g)}} + {{\text{H}}_2}{\text{(g)}} \to {{\text{C}}_2}{{\text{H}}_6}{\text{(g)}}\]

A.     –137

B.     –33

C.     +33

D.     +137

Answer/Explanation

Markscheme

A

Question

The equation for the formation of ethyne is:
2C(s) + H2 (g) → C2H2 (g)
What is the enthalpy change, in kJ, for this reaction using the enthalpy of combustion data below?
 
A.  2 × (−394) + \(\frac{1}{2}\) (−572) − \(\frac{1}{2}\) (−2602)
B.  2 × (−394) + (−572) − (−2602)
C.  2 × (−394) + \(\frac{1}{2}\) (−572) + \(\frac{1}{2}\) (−2602)
D.  2 × (−394) + (−572) + (−2602)
Answer/Explanation

Markscheme

A

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