Home / IB MYP 4-5 Physics | Electromagnetism |AC & DC Generation and transmission of electricity Practice Question

IB MYP 4-5 Physics | Electromagnetism |AC & DC Generation and transmission of electricity Practice Question

IB myp 4-5 physics – Practice Questions- All Topics

Topic :Electromagnetism-AC & DC Generation and transmission of electricity

Topic :Electromagnetism– Weightage : 21 % 

All Questions for Topic : Electric Fields,Static Electricity ,Magnetism,Magnetic Fields,Current,Power,Voltage,Electric Circuits,Electric and Magnetic Fields,Electromagnetic forces and induction

Question (7 marks)

Question a (1 mark)

Transformers are electrical devices that are used for reducing or increasing the voltage of an alternating current.
Select the correct terms to complete the sentence.

In a transformer that is $100 \%$ efficient, the input ______________ must be  ___________________  the output power.

▶️Answer/Explanation

Ans:

In a transformer that is $100 \%$ efficient, the input power  must be equal to the output power.

 

Question b (2 mark)

Transformers are composed of primary and secondary coils wrapped around an iron core.

Transformers are commonly used to reduce the voltage from supply lines to the voltage required for homes.

Use information from the formula sheet to calculate the primary supply voltage. You should assume this transformer is $100 \%$ efficient.

▶️Answer/Explanation

Ans:

Power Primary = Power Seconday
$\mathrm{Vp}~\rm I\mathrm{p}=\mathrm{Vs}~\rm I \mathrm{s}$
$$
\begin{aligned}
& \frac{\rm V p}{\rm V s}=\frac{\rm I s}{\rm I p} \\
& \rm V_ p=\frac{I s \times \rm V s}{\rm I p} \\
& \rm V p=\frac{(240 \times 60)}{1.2}=12000 \\
& \rm V p=12000 \mathrm{~V}
\end{aligned}
$$

Question c (2 mark)

In reality, transformers are only $98 \%$ efficient. Calculate the actual power supplied by the secondary coil.

▶️Answer/Explanation

Ans:

Power Primary $=\rm Vp \rm Ip$
Power Primary $=12000 \times 1.2$
Power Primary $=14400$
transformers are only $98 \%$ efficient, therefore.
actual power supplied by the secondary coil $=0.98 \times 14400$
actual power supplied by the secondary coil is $14112 \mathrm{~W}$

 
 
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