IB myp 4-5 physics – Practice Questions- All Topics
Topic :Electromagnetism-Current,Voltage,Power
Topic :Electromagnetism– Weightage : 21 %
All Questions for Topic : Electric Fields,Static Electricity ,Magnetism,Magnetic Fields,Current,Power,Voltage,Electric Circuits,Electric and Magnetic Fields,Electromagnetic forces and induction
Question (13 marks)
A flow of charge around a circuit allows us to transfer energy. We often refer to this flow as a current. The circuit diagram below shows a simple circuit.
Question a (2 mark)
Calculate the power transferred to the bulb in the circuit diagram above. You should include the unit in your answer.
▶️Answer/Explanation
Ans:
To calculate the power transferred to the bulb in the circuit, we can use the formula:
Power $(P)=$ Voltage $(V) \times$ Current $(I)$
Given:
Voltage $(\mathrm{V})=12 \mathrm{~V}$
Current $(I)=0.5 \mathrm{~A}$
Substituting the values into the formula, we have:
$
P=12 \mathrm{~V} \times 0.5 \mathrm{~A}
$
$
P=6 \mathrm{~W}
$
Therefore, the power transferred to the bulb in the circuit is 6 watts (W).
Question b (1 mark)
Calculate the charge which flows through the bulb in 100 seconds.
▶️Answer/Explanation
Ans:
To calculate the charge that flows through the bulb, we can use the formula:
Charge $(\mathrm{Q})=$ Current $(\mathrm{I}) \times \operatorname{Time}(\mathrm{t})$
Given:
Current $(\mathrm{I})=0.5 \mathrm{~A}$
Time $(t)=100$ seconds
Substituting the values into the formula, we have:
$\mathrm{Q}=0.5 \mathrm{~A} \times 100$ seconds
$\mathrm{Q}=50$ Coulombs $(\mathrm{C})$
Therefore, the charge that flows through the bulb in 100 seconds is 50 Coulombs (C).