Home / IB MYP Chemistry : Periodic table – Periodic trends groups and periods Practice Question

IB MYP Chemistry : Periodic table – Periodic trends groups and periods Practice Question

IB myp 4-5 Chemistry – Practice Questions- All Topics

Topic :Periodic Table-Periodic trend group and periods

Topic :Periodic Table- Weightage : 21 % 

All Questions for Topic : Metals and Non metals,Transition metals,Noble gases,Periodic trend groups and periods

Question  (8 marks) – Solar Energy Chemistry

 

Solar panels are an alternative to fossil fuels. Silicon (Si) is used in 95% of panels sold today. Elements like gallium (Ga), arsenic (As) and tellurium (Te) are also used in advanced solar panels.

a (2 marks)

Criterion A

Complete the periodic table information for gallium (Ga) and arsenic (As):

PropertyGaAs
Group3 
Period 4
▶️ Show Answer

Completed Table:

PropertyGaAs
Group315
Period44

Periodic Table Explanation:

Gallium (Ga):

  • Group: 13 (formerly IIIA)
  • Period: 4
  • Atomic Number: 31
  • Uses: Gallium arsenide (GaAs) solar cells

Arsenic (As):

  • Group: 15 (formerly VA)
  • Period: 4
  • Atomic Number: 33
  • Uses: Semiconductor dopant in solar cells

Periodic Trends:

Both elements are p-block metals in Period 4, demonstrating how elements in the same period can have different properties but similar applications in solar technology.

b (2 marks)

Criterion A

Explain why solar power is environmentally preferable to fossil fuels.

▶️ Show Answer

Key Advantages:

  1. Zero operational emissions: No greenhouse gases or air pollutants during electricity generation
  2. Renewable source: Sunlight is virtually inexhaustible compared to finite fossil fuels

Environmental Impact Comparison:

FactorSolar PowerFossil Fuels
CO₂ Emissions~40g CO₂/kWh (manufacturing only)500-1000g CO₂/kWh
Air PollutionNoneSO₂, NOx, particulates
Water UsageMinimalHigh (cooling, extraction)

Syllabus Connection:

Relates to The Atmosphere → Emission and environmental implications and demonstrates understanding of sustainable energy solutions.

c (1 mark)

Criterion A

Identify the correct alcohol structure from the options below:

 

Option A

CH₃-O-CH₃

Option B

CH₃-CH₂-OH

Option C

CH₃-COOH
▶️ Show Answer

Answer: Option B (CH₃-CH₂-OH)

Functional Group Analysis:

OptionStructureClassification
ACH₃-O-CH₃Ether (not alcohol)
BCH₃-CH₂-OHAlcohol (ethanol)
CCH₃-COOHCarboxylic acid

Key Identification:

Alcohols are characterized by the presence of a hydroxyl (-OH) group attached to a carbon atom. In Option B, the -OH group is clearly visible at the end of the carbon chain.

d (3 marks)

Criterion A

Explain why carbon and silicon form compounds with similar formulas (e.g., CH₄ and SiH₄).

▶️ Show Answer

Key Reasons:

  1. Both are in Group 14 of the periodic table
  2. Have 4 valence electrons (ns²np² configuration)
  3. Can form 4 covalent bonds to complete their octet

Chemical Bonding Analysis:

Carbon (C):

  • Atomic number: 6
  • Electron config: 1s² 2s² 2p²
  • Forms strong covalent bonds
  • Example: Methane (CH₄)

Silicon (Si):

  • Atomic number: 14
  • Electron config: [Ne] 3s² 3p²
  • Forms weaker bonds than carbon
  • Example: Silane (SiH₄)

Tetrahedral Structure Comparison

Methane (CH₄)

 
 
 
 
 

Silane (SiH₄)

 
 
 
 
 

Syllabus Connection:

Demonstrates understanding of Periodic Table → Groups and periods and Bonding → Structure and bonding through comparative analysis of group trends.

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