Home / IB MYP Year 4-5: Exntended Mathematics : Unit 5: Trigonometry -Converse of Pythagoras’ theorem MYP Style Questions

IB MYP Year 4-5: Exntended Mathematics : Unit 5: Trigonometry -Converse of Pythagoras’ theorem MYP Style Questions

IB myp 4-5 MATHEMATICS – Practice Questions- All Topics

Topic :TrigonometryVolume and capacity

Topic :Trigonometry- Weightage : 21 % 

All Questions for Topic : Converse of Pythagoras’ theorem,Sine rule and cosine rule, including applications (link to trigonometric functions)

Question

The lines $B D$ and $C E$ pass through the centre $(O)$ of the circle.
$\bullet$ Determine the value of the angle DAC.
$\bullet$ Write down the value of the angle ADE.
$\bullet$ Determine the value of the angle AEC.
$\bullet$ Find the value of the angle OGD.
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▶️Answer/Explanation

Ans:

a (DAC =) 58 (degrees)

b  (ADE =) 28

c  180 – (90 + 28) OR 90 – 28
(AEC =) 62

d  (OED =) 58
• (OGD =) sum of their 58 OED and their 28 ADE
• Their = 86

 

Question (a)

An engineer is examining a weak bridge from a safe distance. In order to make a calculation for the height of the bridge to the ground vertically below she uses a measuring instrument called a theodolite that allows her to measure angles accurately. The theodolite is set at a height of 1.2 metres $(\mathrm{m})$. It is placed $57.25 \mathrm{~m}$, to the nearest centimetre, from the point $A$ at the bottom of the bridge. The angle of elevation from the horizontal to the top of the arch at $B$ is measured at $22^{\circ}$ to the nearest degree.

The measurements are modelled in the diagram below which is a side view from the bridge to the theodolite.

Calculate the height from the top of the bridge at $\rm B$ to the ground vertically below at $\rm A$ to the nearest centimetre.

▶️Answer/Explanation

Ans:

$\tan 22=\frac{\text { height }}{57.25}$

\[\tan 22 \times 57.25 = \text{height}\]

Using a calculator, we can find the value of \(\tan 22\) to be approximately 0.4040:

\[0.4040 \times 57.25 = \text{height}\]

Simplifying the calculation:

\[23.069 \approx \text{height}\]

Therefore, the height is approximately 23.069.

$\rm{AB}=23.069 + 1.2 = 24.269$

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