IBDP Physics SL 2025 – C.5 Doppler Effect SL Paper 1 Exam Style Questions
IBDP Physics 2025 SL Paper 1 – All Chapters
Topic: C.5 Doppler Effect SL Paper 1
Moving Source & Moving Observer Doppler Effects
Question- C.5 Doppler Effect SL Paper 1
A standing wave is formed between two loudspeakers that emit sound waves of frequency f.
A student walking between the two loudspeakers finds that the distance between two consecutive sound maxima is \(1.5 \mathrm{~m}\). The speed of sound is \(300 \mathrm{~m} \mathrm{~s}^{-1}\).
What is \(f\) ?
A. \(400 \mathrm{~Hz}\)
B. \(200 \mathrm{~Hz}\)
C. \(100 \mathrm{~Hz}\)
D. \(50 \mathrm{~Hz}\)
▶️Answer/Explanation
Ans:C
In a standing wave, the distance between consecutive maxima (or minima) is half of the wavelength (\(\lambda/2\)). Given that the distance between two consecutive sound maxima is \(1.5 \, \text{m}\), we can find the wavelength (\(\lambda\)):
\(\lambda/2 = 1.5 \, \text{m}\)
\(\lambda = 2 \cdot 1.5 \, \text{m} = 3 \, \text{m}\)
Now, we can use the formula for the speed of a wave:
\[v = f \cdot \lambda\]
Let’s solve for \(f\):
\[300 \, \text{m/s} = f \cdot 3 \, \text{m}\]
Now, divide both sides by 3:
\[f = \frac{300 \, \text{m/s}}{3 \, \text{m}} = 100 \, \text{Hz}\]
So, the frequency (\(f\)) of the sound waves is \(100 \, \text{Hz}\).
Question
A radar detector is used to measure the speed of a car. The car is moving with a speed v towards the detector.
The detector emits microwaves of frequency f and speed c. Which of the following is the change in frequency of the microwaves measured at the detector after reflection by the car?
▶️Answer/Explanation
Ans C
(First Shift)
The car moves toward the radar detector with speed \( v \), and the radar emits microwaves of frequency \( f \) and speed \( c \).
The frequency received by the moving car is given by the Doppler formula
$
f’ = f \left(\frac{c + v}{c}\right)
$
where:
\( f’ \) is the frequency detected by the moving car.
\( c \) is the speed of light.
Since the car is moving toward the source, the frequency increases.
(Second Shift)
The moving car acts as a new source, reflecting the frequency \( f’ \) back to the detector.
the detector is stationary and the car is moving toward it, another Doppler shift occurs
$
f” = f’ \left(\frac{c + v}{c}\right)
$
$
f” = f \left(\frac{c + v}{c}\right) \times \left(\frac{c + v}{c}\right)
$
$
f” = f \left(\frac{(c + v)^2}{c^2}\right)
$
Expanding for small \( v/c \), using approximation \( (1 + x)^2 \approx 1 + 2x \) for small \( x \)
$
f” \approx f \left(1 + \frac{2v}{c}\right)
$
$
\Delta f = f” – f = f \frac{2v}{c}
$
Question
A fire engine with its siren sounding approaches and passes a stationary observer. The frequency of the sound emitted by the siren is \({f_s}\). The frequency of the sound measured by the observer is \({f_o}\). Which of the following describes the relationship between \({f_o}\) and \({f_s}\)?
Answer/Explanation
Answer – A
If the observer moves toward the stationary source,
The observed frequency is higher than the source frequency. If the observer is moving away from the stationary source, the observed frequency is lower than the source frequency
Question
An ambulance emits a sound of frequency f as it travels along a straight road between stationary observers A and B.
Which of the following shows how the frequency of the sound heard by each observer compares with f?
Answer/Explanation
Answer – C
For observer B ambulance is approaching towards him so fobs is greater then f.
If the observer moves toward the stationary source,
The observed frequency is higher than the source frequency
And for observer A source is moving away from him so fobs is lesser then f
If the observer is moving away from the stationary source, the observed frequency is lower than the source frequency
Question
A point source of sound is moving to the right at constant speed. The source emits sound waves of constant frequency. The speed of the source is less than the speed of sound. Which diagram correctly shows the wavefronts of the sound?
Answer/Explanation
Answer – A
Towards right wavelength gets compressed and towards left wavelength gets expanded