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Question 1

Forces of 3N and 4N act at right angles, as shown.
What is the resultant force?
A. 1N along XZ
B. 5N along XZ
C. 5N along OY
D. 7N along OY

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.5.1: Effects of forces (Determine the resultant of two or more forces acting along the same straight line)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

The two forces of $3\text{ N}$ and $4\text{ N}$ are perpendicular, so the magnitude of the resultant is found using Pythagoras’ theorem: $\sqrt{3^2 + 4^2} = \sqrt{25} = 5\text{ N}$.
The resultant direction is diagonal between the two forces, not along either original axis, which corresponds to the direction OY shown in the diagram.
This matches the calculation and vector addition for forces at right angles.
Thus, the resultant force is $5\text{ N}$ along OY.

Question 2

A light ball is held at rest at the top of a tall cliff. It is released and falls through the air, eventually reaching its terminal velocity.
Which row describes the behaviour of the ball as it descends?
 the initial acceleration of the ballthe final acceleration of the ball
A00
B0g
Cg0
Dgg

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.2: Motion (Describe the motion of objects falling in a uniform gravitational field with and without air resistance, including reference to terminal velocity)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

Initially, at the moment of release, the only force acting on the ball is its weight, resulting in an acceleration equal to the acceleration of free fall \( g \).
As the ball accelerates, air resistance increases until it balances the weight of the ball, at which point the resultant force becomes zero.
When the resultant force is zero, the acceleration is zero and the ball continues to move at a constant terminal velocity.
Therefore, the initial acceleration is \( g \) and the final acceleration is \( 0 \), which corresponds to row C.

Question 3

The graph represents the motion of a car.
How far has the car moved between 0 and 5 s?
A. 2 m
B. 10 m
C. 25 m
D. 50 m

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.2: Motion (Calculate the area under a speed-time graph to determine the distance travelled for motion with constant speed)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

The distance travelled is found from the area under the speed-time graph between 0 and 5 s.
The graph shows a horizontal line at a constant speed of $5\text{ m/s}$, forming a rectangle with time.
Calculate the area: distance $=$ speed $\times$ time $= 5\text{ m/s} \times 5\text{ s}$.
This gives a total distance moved of $25\text{ m}$.
Therefore, the correct answer is Option C.

Question 4

Which statement about mass or weight is not correct?
A. Masses can be compared using a balance.
B. Mass is a force.
C. Weights can be compared using a balance.
D. Weight is a force.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.3: Mass and weight (State that mass is a measure of the quantity of matter and weight is a gravitational force)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Mass is a scalar quantity measuring the amount of matter in an object, not a force.
Weight is a vector quantity defined as the gravitational force acting on a mass (W = mg).
A balance compares gravitational forces to measure mass, meaning both masses and weights can effectively be compared using one.
Therefore, the statement “Mass is a force” is the incorrect option.
This matches Option B.

Question 5

A sphere P, made of steel, has a weight of 10 N on Earth. Another sphere Q, also made of steel, has a weight of 10 N on Mars. The gravitational field strength on Earth is greater than the gravitational field strength on Mars.
Which statement is correct?
A. The mass of sphere P is the same as the mass of sphere Q.
B. The mass of sphere P is less than the mass of sphere Q.
C. On Mars, the weight of sphere P is the same as the weight of sphere Q.
D. On Earth, the weight of sphere Q is less than 10 N.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.3: Mass and weight (Define gravitational field strength as force per unit mass; recall and use the equation $g = \frac{W}{m}$)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Weight is calculated using the formula $W = mg$. Since $g_{\text{Earth}} > g_{\text{Mars}}$, for both spheres to have the same weight ($10\text{ N}$), sphere Q on Mars must compensate for the lower field strength with a greater mass.
Therefore, the mass of sphere P is less than the mass of sphere Q.
Option B is the correct statement.

Question 6

Which two quantities must be known to determine the density of a material?
A. mass and area
B. mass and volume
C. weight and area
D. weight and volume

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.4: Density (Define density as mass per unit volume; recall and use the equation $\rho = \frac{m}{V}$)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Density ($\rho$) is defined by the equation $\rho = \frac{m}{V}$, representing the mass ($m$) of a substance contained within a unit volume ($V$).
Therefore, calculating the density of any material strictly requires knowing its total mass and the volume it occupies.
Options involving area or weight are incorrect as area is not a measure of three-dimensional space and weight is a force dependent on gravity, not an inherent property like mass.
This matches Option B.

Question 7

A truck is towing a car along a straight horizontal road at a constant speed.
The rope breaks.
Which row gives the direction of the initial acceleration of the truck after the rope breaks and the reason for the acceleration?
 direction of acceleration of the truckreason
Aleftthe driving force is greater than the resistive forces on the truck
Bleftthe driving force is smaller than the resistive forces on the truck
Crightthe driving force is greater than the resistive forces on the truck
Drightthe driving force is smaller than the resistive forces on the truck

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.5.1: Effects of forces (State that a resultant force may change the velocity of an object by changing its direction of motion or its speed)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

Before the rope breaks, the truck moves at constant speed, so the forward driving force is balanced by the total resistive forces plus the tension from towing the car.
When the rope breaks, the tension force is suddenly removed, making the driving force greater than the remaining resistive forces on the truck alone.
This creates a resultant force acting to the right, causing the truck to accelerate in the direction of the driving force.
Therefore, the initial acceleration is to the right because the driving force exceeds the resistive forces.

Question 8

A uniform beam is pivoted at the centre and two identical masses, X and Y, are placed so that the beam balances.
A smaller mass is then added at the position shown.
How can the masses be positioned so the beam balances again?
A. Move X away from the pivot.
B. Move X towards the pivot.
C. Move Y towards the pivot.
D. Move the small mass away from the pivot.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.5.2: Turning effect of forces (Apply the principle of moments to situations with one force each side of the pivot, including balancing of a beam)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Adding the smaller mass on the right side creates an additional clockwise moment about the pivot.
To restore balance, the total clockwise moment must equal the total anticlockwise moment.
Moving mass X towards the pivot decreases its anticlockwise moment, allowing the beam to balance again.
This application of the principle of moments confirms that option B is correct.

Question 9

A resultant force of 2.0 N acts on an object of mass 3.0 kg for 6.0 s.
What is the change in velocity of the object?
A. 0.25 m/s
B. 1.0 m/s
C. 4.0 m/s
D. 36 m/s

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.5.1: Effects of forces (Recall and use the equation $F = ma$)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

Using Newton’s second law, calculate the acceleration: $a = \frac{F}{m} = \frac{2.0}{3.0} = \frac{2}{3} \text{ m/s}^2$.
The change in velocity is given by $\Delta v = a \times t = \frac{2}{3} \times 6.0 = 4.0 \text{ m/s}$.
This matches Option C.

Question 10

The diagram shows the energy stores for a mobile (cell) phone and how the energy is transferred between stores.
What describes how the chemical energy is transferred?
A. electrical work done
B. mechanical work done
C. electromagnetic waves
D. sound waves

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.7.1: Energy (Describe how energy is transferred between stores during events and processes, including examples of transfer by electrical currents (electrical work done))
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

In a mobile phone, the chemical energy store of the battery is depleted to transfer energy to other components.
This transfer occurs via an electric current flowing through the phone’s circuits.
According to the syllabus, energy transferred by electrical currents is defined as electrical work done.
Therefore, the process linking the chemical store to the electrical components is correctly described as electrical work done.
This aligns with Option A.

Question 11

A wind turbine is 30% efficient and has an output of 2.5 MW of electrical power.

What is the power input to the turbine?

A. 0.75 MW
B. 8.3 MW
C. 75 MW
D. 83 MW

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.7.3: Energy resources (Understand, qualitatively, the concept of efficiency of energy transfer; Supplement: Define efficiency and recall and use the equation)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Efficiency is the ratio of useful power output to total power input: $\text{Efficiency} = \frac{\text{Output Power}}{\text{Input Power}}$.
Rearranging this gives $\text{Input Power} = \frac{\text{Output Power}}{\text{Efficiency}}$.
Substitute the given values: $\text{Input Power} = \frac{2.5\text{ MW}}{0.30} = 8.33\text{ MW}$.
Rounding to two significant figures (consistent with 2.5 MW) yields $8.3\text{ MW}$.
This corresponds to Option B.

Question 12

Which two physical quantities must be used to calculate the power developed by a student running up a flight of steps?
A. force exerted and the vertical height of the steps only
B. force exerted and the time taken only
C. work done and the vertical height of the steps only
D. work done and the time taken only

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.7.4: Power (Define power as work done per unit time and also as energy transferred per unit time; recall and use the equations)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Power is defined as the rate of doing work, given by the equation $P = \frac{W}{t}$ or $P = \frac{\Delta E}{t}$.
To calculate the power, the total work done ($W$) against gravity must be known along with the time ($t$) taken.
While work itself depends on force and height, power specifically requires the work done and the time taken only.
Therefore, the two essential quantities are work done and time taken, matching Option D.

Question 13

The density of sea water is \(1030 \, \text{kg/m}^3\). The gravitational field strength on the Earth is \(9.8 \, \text{N/kg}\). Atmospheric pressure is \(101 \, 000 \, \text{Pa}\).

At which depth in sea water is the total pressure due to the atmosphere and the water equal to \(513 \, 000 \, \text{Pa}\)?

A. 40.8 m
B. 50.8 m
C. 400 m
D. 498 m

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 1.8: Pressure (Recall and use the equation for the change in pressure beneath the surface of a liquid \(\Delta p = \rho g\Delta h\))
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

Total pressure \(P_{\text{total}} = P_{\text{atm}} + \rho g h\). Rearranging gives \(h = \frac{P_{\text{total}} – P_{\text{atm}}}{\rho g}\).
Substitute the values: \(h = \frac{513000 – 101000}{1030 \times 9.8} = \frac{412000}{10094} \approx 40.8 \text{ m}\).
This is the depth at which the water pressure adds to atmospheric pressure to reach the total.
The calculation uses the supplement equation \(\Delta p = \rho g \Delta h\) from topic 1.8.

Question 14

Four students describe the phrase ‘absolute zero’ during a lesson on the particle model.

Which student is correct?

A. This is the lowest possible temperature.
B. Particles in a solid start vibrating.
C. Particles do not have any weight.
D. Particles have the least gravitational potential energy.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 2.1.2: Particle model (Describe the relationship between the motion of particles and temperature, including the idea that there is a lowest possible temperature (-273°C), known as absolute zero)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

Absolute zero is defined as $0\text{ K}$ or $-273^{\circ}\text{C}$, the theoretical temperature at which particles have minimum internal energy and cease to move.
It is the lowest possible limit of the thermodynamic temperature scale and cannot be fully reached in practice.
Option A correctly identifies this fundamental concept from the kinetic particle model.
Other options incorrectly describe phase changes or unrelated energy forms.
Therefore, Option A is the accurate statement.

Question 15

Four students are asked to state and explain the relative magnitudes of the thermal expansion of solids and gases.
Which student is correct?
A. Gases expand more than solids because the molecules in a gas are in random motion.
B. Gases expand more than solids because the attractive forces between molecules are much weaker in gases.
C. Solids expand more than gases because the molecules are closer together in solids.
D. Solids expand more than gases because the molecules in a solid are in a regular pattern.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

2.2.1: Thermal expansion of solids, liquids and gases (Explain, in terms of the motion and arrangement of particles, the relative order of magnitudes of the expansion of solids, liquids and gases as their temperatures rise)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Thermal expansion occurs because particles vibrate more and move further apart when heated.
In solids, strong intermolecular forces restrict the particles, resulting in relatively small expansion.
In gases, the intermolecular forces are negligible, so particles can move much further apart, causing significantly greater expansion.
Option B correctly identifies that the weaker attractive forces in gases allow for a larger magnitude of expansion compared to solids.
This aligns with the kinetic particle model described in the syllabus.

Question 16

Four cups A, B, C and D contain hot coffee.
Which cup keeps the coffee warm the longest?
 the outside surface of the cupthe top of the cup
Ablackcovered with a lid
Bblackno lid
Cwhitecovered with a lid
Dwhiteno lid

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 2.3.3: Radiation (Describe the effect of surface colour on the emission, absorption, and reflection of infrared radiation)
TOPIC 2.3.2: Convection (Explain convection in liquids and gases in terms of density changes)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

A white surface is a poor emitter of thermal radiation, so less heat is lost from the sides of the cup.
A lid prevents heat loss by convection currents and reduces evaporation from the liquid surface.
The combination of a reflective (white) outer surface and a sealed lid minimizes both radiation and convection.
This ensures the rate of thermal energy transfer to the surroundings is the lowest among the options.
Therefore, Cup C keeps the coffee warm for the longest time.

Question 17

The diagram shows a wave.
What are the amplitude and the wavelength of this wave?
 amplitude/cmwavelength/cm
A34
B38
C64
D68

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 3.1: General properties of waves (Describe the features of a wave in terms of wavelength and amplitude)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Amplitude is the maximum displacement from the undisturbed position; here it is $3\text{ cm}$ (half the total vertical height of $6\text{ cm}$).
Wavelength is the distance between two adjacent crests or troughs; the diagram shows one full cycle covering $8\text{ cm}$.
Therefore, the amplitude is $3\text{ cm}$ and the wavelength is $8\text{ cm}$, corresponding to Option B.

Question 18

Optical fibres are used to transmit digital signals using infrared radiation. The average refractive index of the fibres is 1.50.

Which row describes a digital signal and gives the speed of infrared radiation in the fibres?

 digital signalspeed of infrared radiation in the fibres m/s
Aa signal that consists of only two values\( 2.0 \times 10^8 \)
Ba signal that consists of only two values\( 4.5 \times 10^8 \)
Ca signal that consists of a continuous range of values\( 2.0 \times 10^8 \)
Da signal that consists of a continuous range of values\( 4.5 \times 10^8 \)

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 3.2.2: Refraction of light (Define refractive index and calculate the speed of light in a medium)
TOPIC 3.3: Electromagnetic spectrum (Know the difference between a digital and analogue signal)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

A digital signal is characterized by having only two discrete values, typically representing 0 and 1.
The speed of light in a medium is calculated using \( v = \frac{c}{n} \), where \( c = 3.0 \times 10^8 \text{ m/s} \) and \( n = 1.50 \).
Substituting the values gives \( v = \frac{3.0 \times 10^8}{1.50} = 2.0 \times 10^8 \text{ m/s} \).
Therefore, the row with a two-value digital signal and a speed of \( 2.0 \times 10^8 \text{ m/s} \) is correct.
This matches Option A.

Question 19

Which statement describes monochromatic light?
A. light of a single frequency
B. light transmitted by a transparent prism
C. visible light
D. white light

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

3.2.4 Dispersion of light: Recall that visible light of a single frequency is described as monochromatic (Supplement)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

Monochromatic light is defined as light that consists of a single frequency or a single wavelength.
This is a specific term used in physics to distinguish pure spectral colours from white light, which is a mixture of all visible frequencies.
Options B, C, and D do not accurately describe this property; for instance, white light contains multiple frequencies and visible light spans a range of frequencies.
Therefore, Option A correctly matches the scientific definition of monochromatic light.

Question 20

A beam of light consists of yellow and blue light. The beam of light is incident on a glass prism. Which diagram is correct?

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 3.2.4: Dispersion of light (Describe the dispersion of light as illustrated by the refraction of white light by a glass prism)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

When a beam of mixed light enters a glass prism, it undergoes dispersion due to different refractive indices for different wavelengths.
Blue light has a shorter wavelength and higher frequency than yellow light, so it experiences greater refraction and bends more towards the normal.
Therefore, the blue ray deviates further from the original path than the yellow ray, which matches the separation shown in diagram D.
This confirms Option D as the correct representation of dispersion through the prism.

Question 21

A radio station broadcasts a signal with a frequency of 89 MHz. What is the wavelength of this signal?
A. 3.7 µm
B. 3.4 m
C. 3.7 km
D. 3.4 Mm

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 3.3: Electromagnetic spectrum (Recall and use the equation $v = f\lambda$ for electromagnetic waves; Know that all electromagnetic waves travel at the speed of light in a vacuum)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Using the wave equation $\lambda = \frac{v}{f}$, substitute $v = 3.0 \times 10^8 \text{ m/s}$ and $f = 89 \times 10^6 \text{ Hz}$.
Calculate $\lambda = \frac{3.0 \times 10^8}{89 \times 10^6} = \frac{300}{89} \approx 3.37 \text{ m}$, which rounds to $3.4 \text{ m}$.
This wavelength is typical for radio waves in the VHF band, consistent with the electromagnetic spectrum.
Therefore, the wavelength of the 89 MHz signal is approximately $3.4 \text{ m}$.

Question 22

A boy shouts and hears the echo from a tall building 2.2 s later. The speed of sound in air is 330 m/s. How far away from the boy is the building?
A. 150 m
B. 300 m
C. 360 m
D. 730 m

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 3.4: Sound (Describe an echo as the reflection of sound waves and perform calculations involving distance, time, and wave speed)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

The time of 2.2 s is for the sound to travel to the building and back.
The distance traveled one way is \( d = \frac{v \times t}{2} \).
Substituting the values: \( d = \frac{330 \times 2.2}{2} = 363 \text{ m} \).
Rounding to two significant figures gives approximately 360 m.
This corresponds to Option C.

Question 23

The magnetic field of a bar magnet can be represented by magnetic field lines.
Which diagram shows two magnetic field lines correctly?

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.1: Simple phenomena of magnetism (Draw the pattern and direction of magnetic field lines around a bar magnet)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

Magnetic field lines always emerge from the north pole (N) and enter the south pole (S) of a magnet.
The lines must form continuous, closed loops and should never intersect each other.
In diagram A, the lines correctly curve outward from N and into S without crossing.
This matches the standard representation of the field around a bar magnet.

Question 24

A plastic rod is rubbed with a dry cloth. The rod becomes positively charged.
Why has the rod become positively charged?
A. It has gained electrons.
B. It has gained neutrons.
C. It has lost electrons.
D. It has lost neutrons.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.2.1: Electric charge (Explain that charging of solids by friction involves only a transfer of negative charge (electrons))
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

When a plastic rod is rubbed with a dry cloth, friction causes negative charges (electrons) to transfer from the rod to the cloth.
The removal of these negatively charged electrons leaves the rod with a net positive charge.
Neutrons are located in the nucleus and are not transferred during simple friction.
Therefore, the rod becomes positively charged because it has lost electrons.
This corresponds to Option C.

Question 25

Which statement about electric current in a conductor is correct?

A. In a d.c. circuit, the electric current gradually decreases along the conductor.
B. In a d.c. circuit, the free electrons flow back and forth.
C. In an a.c. circuit, the electric current remains exactly the same all the time.
D. In an a.c. circuit, the flow of charge changes direction continually.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

4.2.2 Electric current: Know the difference between direct current (d.c.) and alternating current (a.c.)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Direct current (d.c.) flows in one direction only, while alternating current (a.c.) periodically reverses direction.
The current in a series d.c. circuit is the same at all points, not decreasing gradually.
Electrons in a.c. circuits oscillate back and forth rather than maintaining a steady flow in one direction.
Therefore, the statement that the flow of charge changes direction continually correctly describes a.c.
This matches the syllabus definition of a.c. in Topic 4.2.2.

Question 26

A piece of metal wire X with a uniform diameter has resistance \( R \).

A second piece of wire Y is made of the same metal and has a uniform diameter. Y has double the cross-sectional area of X and half the length of X.

What is the resistance of Y?

A. \(\frac{R}{4}\)
B. \(\frac{R}{2}\)
C. \( R \)
D. \( 4R \)

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.2.4: Resistance (Recall and use relationship for metallic conductor: resistance directly proportional to length and inversely proportional to cross-sectional area)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

The resistance \( R \) of a wire is given by \( R = \rho \frac{L}{A} \).
For wire Y, the length \( L \) is halved (\( \frac{L}{2} \)) and the cross-sectional area \( A \) is doubled (\( 2A \)).
Substituting these values: \( R_Y = \rho \frac{L/2}{2A} = \rho \frac{L}{4A} \).
Since \( \rho \frac{L}{A} = R \), the new resistance is \( \frac{R}{4} \).
This matches Option A.

Question 27

An electric fire is connected to a 240 V supply and transfers energy at a rate of 1.0 kW.
How much charge passes through the fire in 1.0 h?
A. 42 C
B. 250 C
C. \( 1.5 \times 10^4 \) C
D. \( 2.4 \times 10^5 \) C

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.2.5: Electrical energy and electrical power (Recall and use the equation for electrical power \( P = IV \) and electrical energy \( E = IVt \))
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

First, calculate the current using \( P = IV \): \( I = \frac{1000\text{ W}}{240\text{ V}} = 4.17\text{ A} \).
Then, convert time to seconds: \( 1.0\text{ h} = 3600\text{ s} \).
Finally, find the charge using \( Q = It \): \( Q = 4.17\text{ A} \times 3600\text{ s} \approx 1.5 \times 10^4\text{ C} \).
This calculation directly applies the relationship between power, current, voltage, and charge.
Therefore, Option C is the correct answer.

Question 28

Two lamps are connected in parallel.
Which switches must be closed so that both lamps light?
A. \( S_1 \) and \( S_2 \) only
B. \( S_1 \) and \( S_3 \) only
C. \( S_2 \) and \( S_3 \) only
D. \( S_1 \), \( S_2 \) and \( S_3 \)

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.3.2: Series and parallel circuits (Know how to construct and use series and parallel circuits)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

In the given parallel circuit, switch \( S_1 \) controls the main current from the power supply, so it must be closed to deliver power.
Switches \( S_2 \) and \( S_3 \) control the individual branches containing each lamp, so both must be closed to complete the path for each lamp.
Therefore, closing \( S_1 \), \( S_2 \), and \( S_3 \) ensures that both lamps are connected to the power supply and can light up.
This matches Option D.

Question 29

The diagram shows a circuit that switches on a lamp when there is a change in the environment.
Which change in the environment causes the lamp to be switched on?
A. a decrease in light intensity
B. a decrease in temperature
C. an increase in light intensity
D. an increase in temperature

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.3.1: Circuit diagrams and circuit components (Know how thermistors behave in a circuit)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

The circuit contains a thermistor, which is a type of resistor whose resistance decreases as its temperature increases.
When the environmental temperature rises, the thermistor’s resistance falls, allowing more current to flow in the circuit.
This increased current activates the switching component (such as a relay or transistor), which then turns on the lamp.
Conversely, a decrease in temperature would increase the resistance and reduce the current, keeping the lamp off.
Options A and C relate to a light-dependent resistor (LDR), which is not the primary sensor shown here.

Question 30

A step-down transformer is 100% efficient. It has an input voltage of 240 V a.c. and an output voltage of 60 V a.c. The current in the primary coil is 0.50 A.

What is the current in the secondary coil?

A. 0.13 A
B. 0.50 A
C. 2.0 A
D. 8.0 A

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.5.6: The transformer (Recall and use the equation for 100% efficiency in a transformer $I_p V_p = I_s V_s$)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

For a 100% efficient transformer, the power in the primary coil equals the power in the secondary coil, given by $V_p I_p = V_s I_s$.
Substitute the known values: $(240\text{ V}) \times (0.50\text{ A}) = (60\text{ V}) \times I_s$.
Calculate the primary power: $240 \times 0.50 = 120\text{ W}$.
Solve for the secondary current: $I_s = \frac{120\text{ W}}{60\text{ V}} = 2.0\text{ A}$.
This matches Option C.

Question 31

The diagram shows the pattern of the magnetic field due to the current \( I \) in a straight wire.
Which row is correct?
 direction of fieldrelative strength of field
AXgreater at P than Q
BYgreater at P than Q
CXgreater at Q than P
DYgreater at Q than P

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.5.3: Magnetic effect of a current (Describe the pattern and direction of the magnetic field due to currents in straight wires and state the qualitative variation of the strength of the magnetic field around straight wires.)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

The magnetic field around a straight current-carrying wire forms concentric circles, and its direction (X or Y) is determined by the right-hand grip rule.
The strength of the magnetic field decreases as the distance from the wire increases.
Since point Q is closer to the wire than point P, the field strength is greater at Q than at P.
Based on the diagram and the application of the right-hand rule, the correct direction corresponds to Y.
Therefore, Option D (direction Y, greater at Q) is correct.

Question 32

In which device is the magnetic effect of a current not used?
A. electromagnet
B. loudspeaker
C. potential divider
D. relay

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 4.5.3: Magnetic effect of a current (Describe how the magnetic effect of a current is used in relays and loudspeakers)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

An electromagnet uses a coil to create a magnetic field, while relays and loudspeakers operate based on the force exerted on a current-carrying conductor in a magnetic field.
A potential divider, however, consists of resistors arranged to provide a fraction of the input voltage and does not require any magnetic interaction to function.
Therefore, the magnetic effect of a current is not used in a potential divider.

Question 33

Fission and fusion are two types of nuclear process.
How does the total mass of the nuclides produced compare with the total mass of the original nuclide or nuclides in these nuclear processes?
 total mass of fission products compared to original nuclidetotal mass of fusion products compared to original nuclides
Asamesame
Bmoreless
Clessmore
Dlessless

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 5.1.2: The nucleus (Describe the processes of nuclear fission and nuclear fusion as the splitting or joining of nuclei, to include the nuclide equation and qualitative description of mass and energy changes without values)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

In both nuclear fission (splitting of a heavy nucleus) and nuclear fusion (joining of light nuclei), the total mass of the final products is less than the total mass of the original reactants.
This difference in mass, often called the mass defect, is converted into a large amount of energy as described by the equation \( E = mc^2 \).
This energy release is the principle behind the power of atomic bombs, nuclear reactors, and the Sun.
Therefore, for both processes, the mass of the products is less than the mass of the original components.
This corresponds to Option D.

Question 34

The table shows the composition of three different nuclei.
nucleusnumber of protonsnumber of neutrons
X33
Y34
Z43
Which nuclei are isotopes of the same element?
A. X, Y and Z
B. X and Y only
C. X and Z only
D. Y and Z only

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 5.1.2: The nucleus (Explain what is meant by an isotope and state that an element may have more than one isotope)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

Isotopes are defined as nuclei of the same element that have an identical proton number ($Z$) but a different nucleon number ($A$) due to varying numbers of neutrons.
Nucleus X and Nucleus Y both contain $3$ protons, identifying them as the same element (Lithium), while differing in neutron count ($3$ vs $4$).
Nucleus Z contains $4$ protons, which corresponds to a different element (Beryllium) entirely.
Therefore, only X and Y represent isotopes of the same element.
This corresponds to Option B.

Question 35

Which change occurs in the nucleus of a radioactive atom during β-emission?
A. A neutron transforms into a proton and an electron.
B. A neutron transforms into a proton only.
C. A proton transforms into a neutron and an electron.
D. A proton transforms into a neutron only.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 5.2.3: Radioactive decay (Describe the effect of β-decay on the nucleus, including the change: neutron → proton + electron)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

In β⁻ emission, a neutron in the unstable nucleus decays into a proton, an electron, and an antineutrino.
The proton remains in the nucleus, increasing the atomic number by 1, while the electron is ejected as the beta particle.
This process reduces the neutron-to-proton ratio, moving the nucleus toward stability.
Therefore, the correct description is that a neutron transforms into a proton and an electron.

Question 36

A radioactive isotope has a half-life of 8 days. A detector close to a sample of this isotope gives a count rate of 200 counts per minute. Without the source, the background count is 20 counts per minute.
What is the count rate due to the source after 8 days?
A. 80 counts per minute
B. 90 counts per minute
C. 100 counts per minute
D. 110 counts per minute

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 5.2.4: Half-life (Define half-life and use in simple calculations involving tables or decay curves)
▶️ Answer/Explanation
Correct Option: B

Detailed solution:

First, find the initial count rate from the source by subtracting background radiation: $200 – 20 = 180$ counts/min.
After one half-life (8 days), the activity of the source halves, so the source count rate becomes $180 \div 2 = 90$ counts/min.
The question asks specifically for the count rate due to the source, not the total detected rate including background.
Therefore, the correct value is $90$ counts per minute, which corresponds to Option B.

Question 37

Which statement about the Solar System is correct?
A. All the planets are rocky.
B. Only the Earth has a moon.
C. Pluto is a dwarf planet.
D. There are many stars in the Solar System.

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 6.1.2: The Solar System (Describe the Solar System as containing minor planets including dwarf planets such as Pluto)
▶️ Answer/Explanation
Correct Option: C

Detailed solution:

Option A is incorrect: The four inner planets are rocky and small, while the four outer planets are gaseous and large.
Option B is incorrect: Most planets in the Solar System have moons (natural satellites) orbiting them.
Option C is correct: According to the syllabus, the Solar System contains minor planets including dwarf planets such as Pluto.
Option D is incorrect: The Solar System contains only one star, which is the Sun.
Therefore, the statement that Pluto is a dwarf planet is the only correct option.

Question 38

Comets are bodies which orbit the Sun in the Solar System.
What is the shape of the orbit and how is the Sun positioned within the orbit?
 shape of orbitposition of the Sun
Acircularcentre of orbit
Bcircularnot at centre of orbit
Cellipticalcentre of orbit
Dellipticalnot at centre of orbit

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 6.1.2: The Solar System (Know that planets, minor planets and comets have elliptical orbits, and recall that the Sun is not at the centre of the elliptical orbit)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Comets travel in highly elongated, elliptical paths rather than perfect circles.
In an elliptical orbit, the Sun is located at one of the two foci of the ellipse, meaning it is offset from the geometric centre.
This positioning explains why comets move much faster when they are closer to the Sun (near perihelion) and slower when they are farther away.
Option D correctly identifies both the shape as elliptical and the Sun’s position as not at the centre.

Question 39

Which nuclear reaction produces the release of energy to power a star?
A. nuclear fission of helium into hydrogen
B. nuclear fission of hydrogen into helium
C. nuclear fusion of helium into hydrogen
D. nuclear fusion of hydrogen into helium

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

TOPIC 6.2.1: The Sun as a star (Know that stars are powered by nuclear reactions involving the fusion of hydrogen into helium)
▶️ Answer/Explanation
Correct Option: D

Detailed solution:

Stars generate energy through the process of nuclear fusion, not fission.
In the core of a stable star like the Sun, hydrogen nuclei (protons) combine under extreme temperature and pressure to form helium nuclei.
This reaction results in a mass defect, which is converted into a large amount of energy according to $E = mc^2$.
Therefore, the correct description of the reaction is the nuclear fusion of hydrogen into helium, making Option D the accurate choice.

Question 40

What is the definition of the Hubble constant?
A. the ratio of the speed at which a galaxy is receding from the Earth to its distance from the Earth
B. the value of the change in wavelength of the galaxy’s starlight due to redshift
C. the constant used to represent the rate of expansion of the Universe in all directions
D. the estimated constant equal to the age of the Universe

Most-appropriate topic codes (Cambridge IGCSE Physics 0625):

6.2.3 The Universe: Define the Hubble constant \(H_{0}\) as the ratio of the speed at which the galaxy is moving away from the Earth to its distance from the Earth; recall and use the equation \(H_{0} = \frac{v}{d}\)
▶️ Answer/Explanation
Correct Option: A

Detailed solution:

The Hubble constant (\(H_0\)) is precisely defined as the constant of proportionality between the recessional velocity (\(v\)) of a galaxy and its distance (\(d\)) from the observer.
This relationship is given by the equation \(H_0 = \frac{v}{d}\) and is fundamental evidence for the expansion of the Universe.
Option A correctly states this ratio, which is distinct from the redshift value itself (Option B) or the reciprocal relationship used to estimate the age of the Universe (Option D).
Therefore, the definition required matches Option A.

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