Question 1



Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B11.1 — Gas exchange in humans (Parts (a)(i), (a)(ii), (b), (c))
• Topic B9.3 — Blood vessels (Part (a)(iii))
• Topic C12.5 — Identification of ions and gases (Part (b)(ii), CO2 test)
▶️ Answer/Explanation
(a)(i) A: rib; B: diaphragm
Structure A sits around the ribcage and is labelled as the rib.
Structure B lies beneath the lungs and is the diaphragm.
Both are muscles/bones involved in the mechanism of breathing.
(a)(ii) nose/mouth, trachea, bronchus (any three)
Inspired air travels: nose or mouth → larynx → trachea.
It then passes into a bronchus, then bronchioles.
Any three of these structures in the correct order are accepted.
(a)(iii) pulmonary artery
The pulmonary artery carries deoxygenated blood from the heart to the lungs.
This is the only vessel of the four listed that brings blood \(to\) the lungs.
The pulmonary vein does the opposite — it carries oxygenated blood away from the lungs.
(b)(i) less oxygen / more water vapour
During gas exchange, oxygen is absorbed into the blood from inspired air.
Water vapour is also added to expired air as it passes over moist airway surfaces.
So expired air contains less oxygen and more water vapour than inspired air.
(b)(ii) test: limewater; observation: turns cloudy/milky
Carbon dioxide is bubbled through or shaken with limewater.
A positive result is shown by the limewater turning cloudy (milky) white.
This occurs because \(\text{CO}_2\) reacts with the calcium hydroxide in limewater to form insoluble calcium carbonate.
(c)(i) 20 breaths per minute
This is read directly from the bar chart in Fig. 1.2.
The “walking” bar reaches the 20 mark on the y-axis.
(c)(ii) breathing rate decreases; depth of breathing decreases
At rest, the body needs less oxygen and produces less carbon dioxide than during running.
So both the rate of breathing and the depth of each breath decrease compared to running.
Question 2


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C8.3 — Group VII properties (Part (a))
• Topic C3.1 — Formulas (word equation, Part (b))
• Topic C11.5 — Alkenes (bromine/ethene test, Part (c))
• Topic C12.5 — Identification of ions and gases (bromide ion test, Part (d))
• Topic C4.1 — Electrolysis (Part (e))
▶️ Answer/Explanation
(a)(i)
| Element | Formula | Colour | Physical state at 20 °C |
|---|---|---|---|
| Chlorine | Cl2 | Pale green | Gas |
| Bromine | Br2 | Orange | Liquid |
| Iodine | I2 | Grey | Solid |
Chlorine is a pale green gas at room temperature.
Bromine is one of the few elements that is liquid at room temperature.
Iodine is a grey solid at room temperature.
(a)(ii) halogens
Group VII elements are collectively known as the halogens.
They all have 7 electrons in their outer shell.
(b) hydrogen + bromine → hydrogen bromide
The reactants, hydrogen and bromine, combine directly.
They form a single product, hydrogen bromide.
(c) colour change: orange to colourless
Ethene, \(\text{C}_2\text{H}_4\), is an unsaturated hydrocarbon containing a carbon–carbon double bond.
This double bond reacts with bromine in an addition reaction to form colourless 1,2-dibromoethane.
As the bromine is used up, the orange colour disappears.
(d) test: add aqueous silver nitrate (acidified with dilute nitric acid); observation: cream-coloured precipitate
Aqueous silver nitrate is added to the solution being tested.
Silver ions react with bromide ions to form insoluble silver bromide.
A cream-coloured precipitate confirms the presence of bromide ions.
(e) at cathode: lead; at anode: bromine
During electrolysis, positive lead ions, \(\text{Pb}^{2+}\), migrate to the negative cathode and gain electrons to form lead metal.
Negative bromide ions, \(\text{Br}^-\), migrate to the positive anode and lose electrons to form bromine.
This follows the rule that metals form at the cathode and non-metals form at the anode.
Question 3



Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P1.2 — Motion (Part (a))
• Topic P2.3.3 — Radiation (Part (b)(i))
• Topic P3.3 — Electromagnetic spectrum (Part (b)(ii))
• Topic P2.1.3 — Pressure changes (Part (b)(iii))
• Topic P1.5.2 — Turning effect of forces (Part (c))
• Topic P3.2.1 — Reflection of light (Part (d))
▶️ Answer/Explanation
(a)(i) speed-time graph with three sections
A straight line rises from (0, 0) to (20, 5) representing constant acceleration.
A horizontal line runs from (20, 5) to (110, 5) representing constant speed.
A straight line falls from (110, 5) to (115, 0) representing constant deceleration.
(a)(ii) 450 m
Distance = speed × time.
Distance \(= 5 \, \text{m/s} \times 90 \, \text{s} = 450 \, \text{m}\).
(b)(i) radiation
Thermal energy from the Sun reaches the Earth as radiation.
Radiation is the only method of thermal transfer that does not need a medium, which is why it can cross the vacuum of space.
(b)(ii) infrared
Infrared radiation from the Sun is responsible for heating dark surfaces such as the saddle.
Black surfaces are good absorbers of infrared radiation.
(b)(iii) molecules move faster and collide more often with the tyre walls
As temperature increases, the air molecules gain kinetic energy and move faster.
This causes them to collide with the walls of the tyre more frequently.
More frequent (and more forceful) collisions increase the pressure of the air in the tyre.
(c) spanner B has a longer handle, giving a greater moment for the same force
Moment = force × perpendicular distance from the pivot.
Spanner B is longer, so it gives a greater distance from the pivot (the nut).
A greater distance means a smaller force is needed to produce the same turning effect, making it easier to loosen the nut.
(d) upright; laterally inverted
The image formed in a plane mirror is upright, the same way up as the object.
It is laterally inverted, meaning left and right appear reversed.
The image is also the same size as the object and appears the same distance behind the mirror as the object is in front.
Question 4


gum pulp nerve
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B18.2 — Food chains and food webs (Part (a))
• Topic B18.1 — Energy flow (Part (b))
• Topic B7.3 — Digestion (closest surviving match, Part (c)) — see flag below
▶️ Answer/Explanation
(a)(i) grass → goat → jackal → lion
Grass is the producer, so it starts the chain.
Goats eat grass, jackals eat goats, and lions eat jackals.
Each arrow points from the organism eaten to the organism that eats it.
(a)(ii) producer: grass; secondary consumer: jackal
The producer makes its own food by photosynthesis — this is the grass.
The primary consumer (goat) eats the producer.
The secondary consumer eats the primary consumer, so this is the jackal.
(b) the Sun
The Sun provides the light energy that producers convert into chemical energy through photosynthesis.
This energy then passes along the food chain as organisms feed on one another.
(c)(i) goats have no canine teeth (humans have 4); goats have more premolars (12 vs 8)
Goats lack canine teeth entirely, while humans have four.
Goats also have a greater number of premolar teeth than humans.
These differences reflect the different diets of the two species.
(c)(ii) goats need more grinding teeth to break down tough plant material
Goats rely entirely on plant material, which is fibrous and tough to break down.
More premolars and molars provide a greater grinding surface area for this task.
Humans eat a more varied, softer diet, so fewer grinding teeth are needed.
(c)(iii) enamel and dentine
Enamel is the hard, outer protective layer of a tooth.
Dentine lies directly beneath the enamel and is the second layer.
These are the top two layers, above the pulp and nerve at the tooth’s core.
Question 5



State the name of one other greenhouse gas.
State the names of two fossil fuels.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C8.4 — Transition elements (Part (a)(i))
• Topic C9.1 — Properties of metals (Part (a)(ii))
• Topic C9.4 — Reactivity series (Part (a)(iii))
• Topic C3.1 — Formulas (Part (b)(i))
• Topic C6.3 — Redox (Part (b)(ii))
• Topic C10.2 — Air quality and climate (Part (c)(i), (c)(ii))
• Topic C11.3 — Fuels (Part (c)(iii))
▶️ Answer/Explanation
(a)(i) copper and iron
Transition elements are metals with high density, high melting points, and coloured compounds, positioned in the central block of the Periodic Table.
Of the four metals listed, copper and iron are transition elements.
Lithium and sodium are Group I (alkali) metals instead.
(a)(ii) hydrogen
Alkali metals react with water to form a metal hydroxide and hydrogen gas.
For example: sodium + water → sodium hydroxide + hydrogen.
(a)(iii) sodium, lithium, iron, copper (most to least reactive)
Reactivity with water increases down this list based on how vigorously each metal reacts.
Sodium reacts most violently, followed by lithium, then iron (very slowly), then copper (not at all).
(b)(i) 2CuO + C → 2Cu + CO₂
Balancing requires 2 copper oxide units to supply enough oxygen for one \(\text{CO}_2\).
This gives 2 copper atoms and one carbon atom on each side, so the equation balances.
(b)(ii) copper oxide is reduced
Copper oxide loses oxygen during the reaction, forming copper metal.
Loss of oxygen is the definition of reduction.
Carbon, meanwhile, gains oxygen and is oxidised to carbon dioxide.
(c)(i) oxygen and nitrogen
Clean, dry air is approximately 78% nitrogen and 21% oxygen.
These two gases make up the vast majority of clean air by volume.
(c)(ii) methane
Methane is released from the decomposition of vegetation and from digestion in animals.
Like carbon dioxide, it traps heat in the atmosphere, making it a greenhouse gas.
(c)(iii) coal and petroleum (natural gas also accepted)
Fossil fuels form from the remains of ancient organisms over millions of years.
Coal, petroleum (oil), and natural gas are the three main fossil fuels; any two are acceptable here.
Question 6
A single switch is used to turn on both lamps.
Calculate the current in each lamp when lit.


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P4.3.2 — Series and parallel circuits (Part (a))
• Topic P2.3.2 — Convection (Part (b)(i))
• Topic P2.3.1 — Conduction (Part (b)(ii))
• Topic P4.2.1 — Electrical charge (Part (c))
• Topic P4.1 — Simple phenomena of magnetism (Part (d))
▶️ Answer/Explanation
(a)(i) circuit with two lamps in parallel, both controlled by one switch
The circuit shows a 12 V battery as the power source.
Both lamps are drawn side by side in parallel branches.
A single switch is placed in the main circuit so it controls both lamps together.
(a)(ii) 4 A
Using Ohm’s law, \(I = \dfrac{V}{R}\).
Each lamp has the full 12 V across it since they are in parallel.
\(I = \dfrac{12\,\text{V}}{3.0\,\Omega} = 4\,\text{A}\).
(a)(iii) if one lamp fails, the other still lights
In a parallel circuit, each lamp has its own independent path connected across the battery.
If one lamp fails or is removed, the circuit for the other lamp remains complete.
In series, one broken lamp would break the whole circuit and switch off both lamps.
(b)(i) convection
The nitrogen gas near the hot filament heats up and becomes less dense.
It rises and carries thermal energy to the glass bulb through convection currents.
(b)(ii) conduction
Heat passes through the solid glass bulb by conduction.
Vibrations are passed from particle to particle through the glass lattice.
(c) friction between the car and air/road transfers electrons
As the car moves, friction occurs between its surface and the air (or the tyres and the road).
This friction causes electrons to be transferred from one surface to another.
This leaves the car with an overall imbalance of charge, making it electrostatically charged.
(d) a magnet will not stick to the plastic filler
Steel is a magnetic material, so a magnet will be attracted to and stick to the normal steel bodywork.
The plastic filler is non-magnetic, so the magnet will not stick over the repaired area.
Moving the magnet over the door and noting where it fails to stick reveals the location of the repair.
Question 7


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B9.4 — Blood (Part (a))
• Topic B1.1 — Characteristics of living organisms (Part (b), (c))
▶️ Answer/Explanation
(a) platelets; red blood cells; white blood cells; plasma
Platelets are cell fragments responsible for blood clotting.
Red blood cells contain haemoglobin, which binds oxygen for transport.
White blood cells carry out phagocytosis and produce antibodies.
Plasma is the liquid component of blood, and it carries dissolved substances such as hormones.
(b) excretion is the removal from organisms of toxic materials and substances in excess of requirements
Excretion specifically refers to waste removal, not intake or digestion of substances.
It covers both toxic materials and substances the body simply has too much of.
This distinguishes excretion from egestion, which is the removal of undigested food.
(c) movement; growth (any two of: movement, sensitivity, growth, reproduction)
Living organisms share a set of characteristic life processes.
Alongside excretion, respiration and nutrition, these include movement, sensitivity, growth and reproduction.
Any two of these (other than the three already given) are accepted.
Question 8

Use this information to explain the difference between an element and a compound.
An atom of hydrogen has a nucleon number (mass number) of 1 and a proton number (atomic number) of 1.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C11.5 — Alkenes (Part (a))
• Topic C2.1 — Elements, compounds and mixtures (Part (b))
• Topic C11.4 — Alkanes (Part (c))
• Topic C5.1 — Exothermic and endothermic reactions (Part (d))
• Topic C2.2 — Atomic structure and the Periodic Table (Part (e))
• Topic C2.5 — Simple molecules and covalent bonds (Part (f))
▶️ Answer/Explanation
(a) H₂O
Molecule C is ethene, \(\text{C}_2\text{H}_4\), shown by its carbon–carbon double bond.
Molecule A is ethanol, \(\text{C}_2\text{H}_5\text{OH}\), formed by adding water across the double bond.
This addition reaction (hydration of an alkene) requires the substance \(\text{H}_2\text{O}\).
(b) an element has one type of atom; a compound has two or more elements chemically combined
Carbon and hydrogen are each elements, made of only one type of atom.
Methane, \(\text{CH}_4\), is a compound because carbon and hydrogen atoms are chemically bonded together.
A compound has different chemical properties from the elements that make it up.
(c) carbon dioxide and water
Complete combustion of a hydrocarbon in plenty of oxygen produces carbon dioxide and water.
\(\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}\).
(d) exothermic means thermal energy is released to the surroundings
In an exothermic reaction, energy is transferred from the reacting chemicals to the surroundings.
This is usually observed as a rise in temperature of the surroundings.
(e)(i) carbon: 6 electrons; hydrogen: 1 electron
In a neutral atom, the number of electrons equals the number of protons.
Carbon has a proton number of 6, so it has 6 electrons.
Hydrogen has a proton number of 1, so it has 1 electron.
(e)(ii) 0 neutrons
Number of neutrons = nucleon number − proton number.
For hydrogen: \(1 – 1 = 0\) neutrons.
(f) carbon shares one electron pair with each of the four hydrogen atoms
Methane forms four single covalent bonds, one between carbon and each hydrogen atom.
Each bond is shown as a shared pair of electrons, with one dot (from carbon) and one cross (from hydrogen) in each overlapping region.
All four hydrogen atoms end up with a full outer shell of 2 electrons, and carbon ends up with a full outer shell of 8.
Question 9

The mass of the flute is 801 g.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P3.1 — General properties of waves (Part (a)(i))
• Topic P3.4 — Sound (Part (a)(ii), (a)(iii), (a)(iv))
• Topic P1.4 — Density (Part (b))
▶️ Answer/Explanation
(a)(i) the number of waves produced (or passing a point) per second
Frequency describes how many complete wave cycles occur in one second.
It is measured in hertz, Hz, where 1 Hz equals one wave per second.
(a)(ii) piano
Pitch is directly related to frequency — a lower frequency gives a lower pitch.
The piano has the lowest frequency in the table, at 30 Hz.
So the piano produces the sound with the lowest pitch.
(a)(iii) piano
Range = highest frequency − lowest frequency for each instrument.
The piano’s range is \(4200 – 30 = 4170\,\text{Hz}\), the largest of the four instruments.
(a)(iv) 20 Hz to 20 000 Hz
This is the typical range of frequencies a healthy human ear can detect.
Sounds below 20 Hz are infrasound, and sounds above 20 000 Hz are ultrasound.
(b)(i) 8.90 g/cm³
Density = mass ÷ volume.
Density \(= \dfrac{801\,\text{g}}{90\,\text{cm}^3} = 8.90\,\text{g/cm}^3\).
(b)(ii) 8.01 N
Weight = mass × gravitational field strength, using mass in kilograms.
\(801\,\text{g} = 0.801\,\text{kg}\), so weight \(= 0.801 \times 10 = 8.01\,\text{N}\).
Question 10
Circle two parts of a plant that are adapted for transport from the list below.
phloem vena cava xylem


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B8.1 — Xylem and phloem (Part (a))
• Topic B8.2 — Water uptake (Part (b))
• Topic B15.3 — Sexual reproduction in plants (germination conditions, Part (c), (d))
▶️ Answer/Explanation
(a) phloem and xylem
Xylem transports water and mineral ions and provides support.
Phloem transports sucrose and amino acids (translocation).
Vena cava and capillaries are transport structures in animals, not plants.
(b)(i) name: root hair cell; function: absorption of water and mineral ions
The cell shown has a long, thin extension that increases its surface area.
This shape is characteristic of a root hair cell.
Its large surface area increases the rate of absorption of water and mineral ions from the soil.
(b)(ii) X: cell wall; Y: nucleus
X is the outer boundary layer of the cell, which is the cell wall.
Y is the structure inside the cytoplasm that controls the cell, the nucleus.
(c)

(d) effect: no germination; reason: boiling denatures the enzymes needed for germination
Boiling the seeds exposes them to a very high temperature.
This denatures the enzymes that control the metabolic reactions involved in germination.
Without functioning enzymes, the seeds cannot germinate.
Question 11

State one use for stainless steel.
Describe one difference in the properties of a solid compared to a liquid.
Fig. 11.2 shows other processes involved when substances change state.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C9.5 — Corrosion of metals (Part (a))
• Topic C9.3 — Alloys and their properties (Part (b))
• Topic C1.1 — Solids, liquids and gases (Part (c), (d))
▶️ Answer/Explanation
(a)(i) oxygen and water
Rusting is a chemical reaction between iron, oxygen, and water.
If either oxygen or water is absent, rusting does not occur.
(a)(ii) painting/greasing/coating with plastic — creates a barrier that excludes oxygen and water
Painting the iron surface forms a physical barrier over the metal.
This barrier keeps oxygen and water away from the iron surface.
Without contact with both oxygen and water, rusting cannot take place.
(b) cutlery (knives, forks, spoons)
Stainless steel resists rusting and corrosion.
This makes it ideal for items in regular contact with moisture and food, such as cutlery.
(c) a solid has a fixed shape; a liquid takes the shape of its container
In a solid, particles are held in fixed positions by strong forces of attraction.
In a liquid, particles are close together but can move past one another.
This allows a liquid to flow and take up the shape of whatever container it is in, while a solid keeps its own shape.
(d) A: boiling; B: condensing; C: freezing
A is the change from liquid to gas, which is boiling.
B is the change from gas back to liquid, which is condensing.
C is the change from liquid to solid, which is freezing.
Question 12
A sample of uranium-235 has a mass of 0.1 g.
Calculate how many grams of uranium-235 will remain in the sample after 704 million years.
Explain what is meant by isotope.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P5.2.2 — The three types of nuclear emission (Part (a))
• Topic P5.1 — The nucleus (Part (b)(i), (b)(iii))
• Topic P5.2.4 — Half-life (Part (b)(ii))
• Topic P4.5.5 — The d.c. motor (Part (c))
▶️ Answer/Explanation
(a) show that the radiation penetrates lead / thick material, but a lighter absorber (paper/aluminium) would stop α and β
Alpha particles are stopped by paper, and beta particles are stopped by a few mm of aluminium.
Gamma rays are far more penetrating and pass through several cm of lead.
If a detector still registers radiation through a thick lead absorber, this confirms the source is emitting γ-rays and not α- or β-particles.
(b)(i) the nucleus splits into two smaller nuclei, releasing neutrons and energy
A uranium-235 nucleus absorbs a neutron, making it unstable.
The unstable nucleus splits into two smaller (daughter) nuclei.
This releases further neutrons along with a large amount of energy.
(b)(ii) 0.05 g
One half-life (704 million years) means exactly one half of the sample has decayed.
Remaining mass \(= \dfrac{0.1\,\text{g}}{2} = 0.05\,\text{g}\).
(b)(iii) atoms of the same element with the same proton number but different numbers of neutrons
Isotopes have identical proton (atomic) numbers, so they are the same element.
They differ in nucleon (mass) number because they have different numbers of neutrons.
Uranium-235 and uranium-238 both have 92 protons but 143 and 146 neutrons respectively.
(c) increase the current; increase the number of turns on the coil (or increase the strength of the magnetic field)
A larger current in the coil produces a greater force on the coil in the magnetic field.
Increasing the number of turns multiplies this force across more loops of wire.
A stronger magnetic field also increases the force on the current-carrying coil, giving a greater turning effect.
