Question 1

- fertilisation occurs,
- gametes are produced.



Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B15.4 — Sexual reproduction in humans (Parts (a), (b), (c))
• Topic B15.2 — Sexual reproduction (Part (d))
▶️ Answer/Explanation
(a)(i) Fertilisation occurs at A; gametes are produced at E
Fertilisation occurs in the oviduct (fallopian tube), labelled A.
Gametes (eggs) are produced in the ovaries, labelled E.
(a)(ii) Uterus
Part B is the uterus.
This is the organ where a fertilised egg implants and develops during pregnancy.
(b) “separation” and “ovary” are incorrect
Fertilisation is the fusion, not separation, of nuclei.
It involves a sperm cell and an egg cell, not an ovary cell.
(c)(i) Ticks under days 1–4
The uterus lining is shed during menstruation.
Fig. 1.3 shows the lining thickness falling sharply over days 1–4.
(c)(ii) Crosses under days 24–26
The lining reaches its maximum thickness just before the next menstrual period begins.
This corresponds to days 24–26 on the graph.
(d) More; kind
Reproduction is the process that makes more of the same kind of organism.
This ensures the continuation of a species across generations.
Question 2
Magnesium oxide and carbon are made.

State the separation technique used to remove magnesium carbonate from a mixture of magnesium carbonate and water.
State the separation technique used to obtain solid magnesium chloride from a solution of magnesium chloride.
Complete the balanced symbol equation for this reaction.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C8.1 — Arrangement of elements (Part (a))
• Topic C6.3 — Redox (Part (b))
• Topic C2.2 — Atomic structure and the Periodic Table (Part (c))
• Topic C12.4 — Separation and purification (Part (d)(i), (ii))
• Topic C7.1 — The characteristic properties of acids and bases (Part (d)(iii))
• Topic C12.5 — Qualitative analysis (Part (d)(iv))
• Topic C9.3 — Alloys and their properties (Part (e))
▶️ Answer/Explanation
(a)(i) Argon
Noble gases are found in Group 18 (Group VIII) of the Periodic Table.
In Period 3, the noble gas is argon (Ar).
(a)(ii) Metallic character decreases across Period 3 (metal to non-metal)
Moving left to right, elements become less metallic and more non-metallic.
The tendency to lose electrons decreases while the tendency to gain electrons increases.
(b)(i) Magnesium + carbon dioxide → magnesium oxide + carbon
Magnesium displaces carbon from carbon dioxide because magnesium is more reactive.
The word equation shows reactants converting to the two named products.
(b)(ii) Thermal energy is released to the surroundings
An exothermic reaction releases energy, usually as heat, to the surroundings.
This causes the temperature of the surroundings to rise.
(c) Protons = 12; Neutrons = 12
Proton number = number of protons = 12.
Nucleon number − proton number = neutrons: \( 24 – 12 = 12 \).
(d)(i) Filtration
Filtration separates an insoluble solid from a liquid.
Magnesium carbonate remains on the filter paper while water passes through.
(d)(ii) Crystallisation
Crystallisation obtains a solid from a solution by evaporating the solvent.
Solid magnesium chloride crystals form as the water evaporates.
(d)(iii) \( \text{MgCO}_3 + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \)
Balancing chlorine and hydrogen atoms requires 2 moles of HCl.
This balances both sides of the equation for all elements.
(d)(iv) Test: add acidified (aqueous) silver nitrate; Observation: white precipitate forms
Silver nitrate reacts with chloride ions to form insoluble silver chloride.
The white precipitate confirms the presence of chloride ions.
(e)(i) 470 kg
Mass of magnesium = 94% of 500 kg.
\( 0.94 \times 500 = 470 \, \text{kg} \).
(e)(ii) The alloy is stronger and/or less dense than pure magnesium
Alloys are generally stronger and more durable than pure metals.
A lighter, stronger material is ideal for aircraft bodies, improving strength while reducing weight.
Question 3
The resistance of the lamp is \(5.0 \, \Omega\) when lit.
Calculate the current in the lamp.
Calculate the combined resistance of the two lamps in series.
This energy is transferred into ……………… energy which passes through the lamp.
The useful energy from the lamp is ……………… energy.
Some energy is wasted as ……………… energy.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P4.3.1 — Circuit diagrams and symbols (Part (a)(i))
• Topic P4.2.4 — Ohm’s law (Part (a)(ii))
• Topic P4.3.2 — Series circuits (Part (a)(iii))
• Topic P1.6.1 — Energy stores and transfers (Part (b))
• Topic P1.6.3 — Renewable energy resources (Part (c))
• Topic P3.2.1 — Reflection of light (Part (d))
▶️ Answer/Explanation
(a)(i) Circuit diagram: 4 cells, 1 lamp, 1 switch, all in series
Standard symbols are used for cells, lamp, and switch.
All four cells, the lamp, and the switch must be connected in a single loop (series).
(a)(ii) 1.2 A
Using Ohm’s law, \( I = \dfrac{V}{R} \).
\( I = \dfrac{6.0}{5.0} = 1.2 \, \text{A} \).
(a)(iii) 10.0 Ω
In series, total resistance is the sum of individual resistances.
\( R_{total} = 5.0 + 5.0 = 10.0 \, \Omega \).
(b) chemical; electrical; light; thermal
Energy stored in cells is chemical potential energy.
It converts to electrical energy in the circuit, producing useful light energy and wasted thermal energy.
(c) Any two: wind, hydroelectric power, tidal, geothermal, wave
Wind energy is harnessed using wind turbines.
Hydroelectric power is generated from the movement of water, such as in dams.
(d)(i) Normal
Line XZ is the normal.
It is an imaginary line drawn perpendicular to the mirror’s surface at the point of incidence.
(d)(ii) Reflection
At point X, the light ray is reflected off the mirror.
The angle of incidence equals the angle of reflection, both measured from the normal.
Question 4

Describe the role of arteries in the circulatory system.

Estimate the length of time of the fitness class.
Describe and explain the result seen at 18:00 hours in Fig. 4.2.
Use ideas about hormones in your answer.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B9.2 — Heart (Part (a)(i), (ii))
• Topic B9.3 — Blood vessels (Part (a)(iii))
• Topic B9.4 — Blood (Part (b))
• Topic B13.2 — Hormones (Part (c))
▶️ Answer/Explanation
(a)(i) B: septum; C: muscle/muscle wall; D: ventricles
The septum (B) divides the left and right sides of the heart.
The muscle wall (C) contracts to pump blood, and the ventricles (D) are the lower chambers of the heart.
(a)(ii) Ensures one-way flow of blood
Structure E is a valve.
Valves prevent the backflow of blood, keeping it moving in one direction through the heart.
(a)(iii) Transport blood away from the heart
Arteries carry oxygenated blood away from the heart to the rest of the body (except the pulmonary artery).
They have thick, muscular, elastic walls to withstand high pressure.
(b) Any two: red blood cells, white blood cells, platelets, plasma
Red blood cells transport oxygen.
White blood cells are involved in immunity, while plasma is the liquid component that carries dissolved substances.
(c)(i) 110 bpm
Maximum heart rate on the graph is approximately 180 bpm.
Minimum heart rate is approximately 70 bpm, giving a difference of \( 180 – 70 = 110 \, \text{bpm} \).
(c)(ii) 4 hours
The heart rate rises sharply at 10:00 and remains elevated before falling back to resting level.
This elevated period lasts approximately 4 hours, from around 10:00 to 14:00.
(c)(iii) Rapid increase in heart rate (by about 70 bpm, to around 140 bpm) due to adrenaline release
Fear triggers the release of adrenaline from the adrenal glands.
Adrenaline increases heart rate rapidly, preparing the body for a “fight or flight” response.
Question 5



Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C9.4 — Reactivity series (Part (a))
• Topic C2.2 — Atomic structure and the Periodic Table (Part (b))
• Topic C1.1 — Solids, liquids and gases (Part (c)(i))
• Topic C2.4 — Ions and ionic bonds (Part (c)(ii))
• Topic C2.1 — Elements, compounds and mixtures (Part (c)(iii))
• Topic C12.4 — Separation and purification (Part (d))
▶️ Answer/Explanation
(a) To prevent potassium reacting with air/oxygen; to prevent potassium reacting with water vapour
Potassium is highly reactive and reacts readily with oxygen and moisture in the air.
Storing it under oil forms a barrier that prevents contact with these substances.
(b) Electronic structure: 2, 8, 8, 1
Potassium has 19 electrons in total, with 2 already drawn in the inner shells.
The remaining electrons fill the shells as 8, 8, 1 (outer shell has 1 electron).
(c)(i) Particle separation: close/touching in a solid, far apart in a gas. Particle arrangement: regular in a solid, random in a gas
In a solid, particles are closely packed and arranged in a regular, fixed pattern.
In a gas, particles are far apart and move randomly with no fixed arrangement.
(c)(ii) The potassium atom loses one electron
A potassium atom has one electron in its outer shell.
It loses this electron to form a positively charged potassium ion, \( \text{K}^+ \).
(c)(iii) An element contains only one type of atom; a compound contains two or more elements/different atoms chemically combined
Elements consist of a single type of atom, such as potassium or chlorine alone.
Compounds form when different elements chemically bond together, such as potassium chloride.
(d)(i) Solubility increases as temperature rises
The graph in Fig. 5.3 shows an upward trend.
As temperature increases, more potassium chloride can dissolve in the same volume of water.
(d)(ii) 41 g (±1)
Reading from the graph at \( 45\,^\circ\text{C} \) gives a solubility value of approximately 41 g.
This is read by drawing a vertical line up from 45 °C to the curve, then horizontally to the y-axis.
Question 6


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P1.2 — Speed, distance and speed-time graphs (Part (a))
• Topic P1.2 — Forces and motion at constant speed (Part (b))
▶️ Answer/Explanation
(a)(i) A and D
The train’s speed is zero at point A, the starting station.
The speed returns to zero again at point D, the final station.
(a)(ii) X placed anywhere between A and B, or between C and D
Acceleration occurs where the speed is increasing on the graph.
This happens during the rising sections A–B and C–D.
(a)(iii) 2500 m
Total distance is the area under the speed-time graph.
Area of triangle A–B \( = \frac{1}{2} \times 100 \times 20 = 1000 \, \text{m} \), area of rectangle B–C \( = 50 \times 20 = 1000 \, \text{m} \), and area of triangle C–D \( = \frac{1}{2} \times 50 \times 20 = 500 \, \text{m} \), giving a total of \( 1000 + 1000 + 500 = 2500 \, \text{m} \).
(b)(i) R
Weight always acts vertically downward due to gravity.
In Fig. 6.2, this direction corresponds to force R.
(b)(ii) Equal in magnitude, opposite in direction
At constant speed, the resultant force on the train is zero.
So the driving force Q must be equal in size but opposite in direction to the frictional/resistive force S.
Question 7


Name the tissue that transports sugars through the plant stem.
Name two other requirements for photosynthesis.
This is because tree roots hold the soil together, stopping it being washed away.
Suggest two other benefits of protecting land from deforestation.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B3.2 — Osmosis in plant cells (Part (a))
• Topic B8.1 — Transport in plants (Part (b), (c))
• Topic B6.1 — Photosynthesis (Part (d))
• Topic B19.1 — Human influences on ecosystems (Part (e))
▶️ Answer/Explanation
(a)(i) The cell swells/increases in size
Beaker A contains a dilute sugar solution, less concentrated than the cell contents.
Water moves into the cell by osmosis, causing it to swell.
(a)(ii) Beaker B; the cells have not changed
In beaker B, the plant cells show no visible change in Table 7.1.
This indicates no net movement of water, meaning the solution concentration equals the cell’s internal concentration.
(b) root hair cell → root cortex cell → xylem → mesophyll cell
Water travels from the root hair cell into the root cortex cells.
It then moves into the xylem for transport up the plant, finally reaching the mesophyll cells in the leaf.
(c) Phloem
Phloem tissue transports dissolved sugars produced during photosynthesis.
This process is called translocation.
(d) Light; chlorophyll
Light provides the energy needed to drive photosynthesis.
Chlorophyll is the pigment that absorbs this light energy within chloroplasts.
(e) Any two: prevents extinction of animals; conserves habitats; protects food sources; maintains food chains/webs; maintains wood/fuel resources; protects natural beauty
Deforestation destroys habitats, threatening animal species with extinction.
Protecting forests also maintains food chains and preserves natural resources such as wood.
Question 8

Suggest one test to show that lead is a metal.
State two ways of increasing the rate of reaction between lead and dilute sulfuric acid.
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C4.1 — Electrolysis (Part (a))
• Topic C6.3 — Redox (Part (b))
• Topic C9.1 — Properties of metals (Part (c))
• Topic C6.2 — Rate of reaction (Part (d))
▶️ Answer/Explanation
(a)(i) Cathode
Positive lead ions (\( \text{Pb}^{2+} \)) are attracted to the negative electrode.
They gain electrons there and are reduced to lead metal.
(a)(ii) Bromine (vapour) is released
Bromide ions (\( \text{Br}^- \)) lose electrons at the anode, forming bromine gas (\( \text{Br}_2 \)).
Bromine gas has a distinctive orange colour.
(b) Substance oxidised: carbon; substance reduced: lead oxide
Carbon gains oxygen to form carbon dioxide, so it is oxidised.
Lead oxide loses oxygen to form lead metal, so it is reduced.
(c) Test for electrical conductivity
Metals are typically good conductors of electricity.
If lead conducts electricity, this supports the conclusion that it is a metal.
(d) Increase temperature; increase surface area of lead (or increase concentration of acid)
Raising the temperature gives particles more energy, increasing collision frequency and rate.
Increasing the surface area of the lead exposes more particles to the acid, also increasing the rate.
Question 9

Use ideas about molecules in your answer.
State the boiling point of water.
State the term used to describe a gas changing into a liquid.
State the method of thermal energy transfer through metals.
Describe the sound waves in terms of their amplitude and frequency.
State the unit of your answer.
Calculate the time taken for a sound wave to travel \(85 \, \text{m}\).
Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P2.2.2 — Melting, boiling and evaporation (Part (a)(i), (ii), (iii))
• Topic P2.3.1 — Conduction (Part (a)(iv))
• Topic P3.4 — Sound (Part (b)(i), (ii), (iii))
▶️ Answer/Explanation
(a)(i) Faster-moving/more energetic molecules escape/leave the surface
Molecules in a liquid have a range of energies.
The most energetic molecules at the surface overcome intermolecular forces and escape as vapour, even below boiling point.
(a)(ii) 100 °C
This is the standard boiling point of water at atmospheric pressure.
At this temperature, water changes rapidly from liquid to gas throughout the bulk of the liquid.
(a)(iii) Condensation
Condensation describes a gas changing into a liquid.
Water vapour loses energy and molecules slow down enough to form liquid water.
(a)(iv) Conduction
Thermal energy transfer through a solid metal occurs by conduction.
Vibrating particles and free electrons transfer energy through the metal casing.
(b)(i) Large amplitude; low frequency
Amplitude relates to loudness, so loud sound has a large amplitude.
Frequency relates to pitch, so a low pitch corresponds to a low frequency.
(b)(ii) 20 Hz
The lowest audible frequency for a healthy human ear is approximately 20 Hz.
The unit for frequency is the hertz (Hz).
(b)(iii) 0.25 s
Time = distance ÷ speed.
\( t = \dfrac{85}{340} = 0.25 \, \text{s} \).
Question 10

- anus
- large intestine
- mouth
- pancreas
- small intestine
- stomach


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic B7.2 — Digestive system (Part (a))
• Topic B7.3 — Digestion (Part (b))
• Topic B7.3 — Digestion, assimilation (Part (c))
▶️ Answer/Explanation
(a)(i) Labels: stomach; pancreas; small intestine
Fig. 10.1 shows three unlabelled organs pointed to by lines.
These correspond to the stomach, pancreas, and small intestine respectively.
(a)(ii) ingestion → mouth; egestion → anus; mechanical digestion → mouth/stomach
Ingestion is the taking in of food, which occurs at the mouth.
Egestion is the removal of undigested waste from the anus, while mechanical digestion (physical breakdown) occurs at the mouth or stomach.
(b) Large/insoluble food molecules are broken down into small/soluble molecules; ref. to absorption
Chemical digestion uses enzymes to break down large, insoluble molecules into smaller, soluble ones.
This allows the small molecules to be absorbed into the bloodstream through the walls of the small intestine.
(c) Assimilation is the movement of digested food molecules into the cells of the body, where they are used, becoming part of the cells
Only digested (soluble) molecules can be assimilated, not undigested food.
These molecules move into body cells and are used to build new cell material or release energy.
Question 11


Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic C11.4 — Alkanes (Part (a), (b), (c))
• Topic C2.5 — Simple molecules and covalent bonds (Part (d))
• Topic C11.4 — Alkanes (Part (e)(i))
• Topic C11.3 — Fuels (Part (e)(ii))
• Topic C11.5 — Alkenes (Part (e)(iii))
▶️ Answer/Explanation
(a) B, C and D
Hydrocarbons contain only carbon and hydrogen atoms.
B (methane), C (ethane), and D (ethene) fit this description, while A contains oxygen and E contains oxygen too.
(b) A and E
Complete combustion of a hydrocarbon produces carbon dioxide and water.
A represents \( \text{CO}_2 \) and E represents \( \text{H}_2\text{O} \).
(c) Carbon dioxide (or methane)
Carbon dioxide (compound A) is a well-known greenhouse gas that traps heat in the atmosphere.
Methane (compound B) is also a potent greenhouse gas.
(d) One shared pair of electrons between O and each H; oxygen has an octet
Oxygen has six outer shell electrons and shares one electron with each hydrogen atom.
This forms two single covalent bonds, giving oxygen a full outer shell of eight electrons.
(e)(i) Contains a carbon-carbon double (or triple) bond
Unsaturated compounds have at least one C=C double bond.
This allows them to undergo addition reactions, unlike saturated compounds.
(e)(ii) Cracking
Cracking breaks down large saturated hydrocarbon molecules using heat and a catalyst.
This produces smaller, more useful molecules, often including unsaturated hydrocarbons.
(e)(iii) Test: add aqueous bromine (bromine water); Observation: orange to colourless
Bromine water reacts with the double bond in an unsaturated hydrocarbon via an addition reaction.
This causes the bromine water to change from orange to colourless.
Question 12
Suggest how a small sample of plutonium-239 can be stored safely.
A sample of plutonium-239 has a mass of \(800 \, \text{g}\).
Calculate the mass of plutonium-239 remaining after \(48\,000\) years.
Place γ-radiation in its correct place in Fig. 12.1.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):
• Topic P5.1 — Nuclear fission (Part (a))
• Topic C2.3 — Isotopes (Part (b)(i))
• Topic P5.2.5 — Safe storage and use of radioactive sources (Part (b)(ii))
• Topic P5.2.4 — Half-life calculations (Part (b)(iii))
• Topic P5.2.2 — Properties of radiation (Part (b)(iv))
• Topic P3.3 — Electromagnetic spectrum (Part (b)(v))
▶️ Answer/Explanation
(a) The nucleus splits
A neutron is absorbed by the plutonium-239 nucleus, making it unstable.
The unstable nucleus splits into two smaller nuclei, releasing energy and further neutrons.
(b)(i) Atoms of the same element with the same number of protons but different numbers of neutrons
Isotopes share the same atomic number since they have identical proton numbers.
They differ in mass number because they contain different numbers of neutrons.
(b)(ii) Store in a lead-lined container
Although the sample emits β-radiation, lead provides effective shielding.
This prevents the radiation from escaping and harming people nearby.
(b)(iii) 200 g
\( 48\,000 \) years represents 2 half-lives (\( 48\,000 \div 24\,000 = 2 \)).
Mass remaining: \( 800 \to 400 \) g (1st half-life) \( \to 200 \) g (2nd half-life).
(b)(iv) β is more ionising; γ is more penetrating (β is charged, γ is uncharged)
β-particles are charged and interact more strongly with matter, making them more ionising.
γ-rays are electromagnetic waves with no charge, allowing them to penetrate much further through materials.
(b)(v) γ-radiation placed in the left-hand box, before ultraviolet
The electromagnetic spectrum is ordered by increasing wavelength (decreasing frequency) from gamma to radio waves.
γ-radiation has the shortest wavelength and highest frequency, so it sits at the far left, before ultraviolet.
