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Question 1

What is meant by respiration?

A. protein synthesis
B. sweating to lose heat
C. the function of lungs
D. the release of energy

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B1.1: Characteristics of living organisms — Respiration is defined as the chemical reactions in cells that break down nutrient molecules and release energy for metabolism.
▶️ Answer/Explanation
Respiration is defined as the chemical reactions occurring inside living cells.
These reactions break down nutrient molecules (such as glucose) to release energy.
This released energy is used for metabolism, i.e. all the chemical processes needed to keep the organism alive.
Answer: (D)

Question 2

The diagram shows a cell with a magnification of ×1000. The width of the image is 45 mm.

What is the actual width of the cell?

A. 45 mm
B. 4.5 mm
C. 0.45 mm
D. 0.045 mm

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B2.2: Size of specimens — State and use the formula: magnification = image size ÷ actual size.
▶️ Answer/Explanation
The magnification formula is \( \text{magnification} = \frac{\text{image size}}{\text{actual size}} \).
Rearranging gives \( \text{actual size} = \frac{\text{image size}}{\text{magnification}} \).
Substituting values: \( \frac{45}{1000} = 0.045 \) mm.
Answer: (D)

Question 3

Linoleic acid is a fatty acid.

Which larger molecule may contain linoleic acid?

A. glycogen
B. oil
C. protein
D. starch

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B4.1: Biological molecules — Recognise that fatty acids combine with glycerol to form lipids (fats and oils).
▶️ Answer/Explanation
Linoleic acid is a fatty acid, and fatty acids are one of the two building blocks of lipids.
Lipids form when fatty acids combine chemically with glycerol through a condensation reaction: \( \text{glycerol} + 3\,\text{fatty acid} \rightarrow \text{lipid} + 3\,\text{H}_2\text{O} \).
Oils are simply lipids that are liquid at room temperature, so oil is the larger molecule that may contain linoleic acid.
Answer: (B)

Question 4

Which type of molecule are enzymes?

A. amino acids
B. carbohydrates
C. fats
D. proteins

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B5.1: Enzymes — State that enzymes are proteins that act as biological catalysts.
▶️ Answer/Explanation
Enzymes are biological catalysts made of protein.
Their protein structure gives them a specific 3D active site that binds only to a complementary substrate molecule.
Answer: (D)

Question 5

Which two arrows represent photosynthesis?

A. 1 and 3
B. 1 and 4
C. 2 and 3
D. 2 and 4

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B6.1: Photosynthesis — Recognise the reactants and products of photosynthesis.
▶️ Answer/Explanation
Photosynthesis is summarised as \( 6CO_2 + 6H_2O \xrightarrow{\text{light}} C_6H_{12}O_6 + 6O_2 \).
This means carbon dioxide must move from the air into the plant, and oxygen must move from the plant into the air.
Arrows 1 (CO₂ in) and 4 (O₂ out) represent this exchange.
Answer: (B)

Question 6

A person has a low red blood cell count and is constipated.

Which row shows the components that may be in short supply in this person’s diet?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B7.1: Diet — Identify the roles of iron and fibre in a balanced diet.
▶️ Answer/Explanation
A low red blood cell count suggests a shortage of iron, since iron is needed to make haemoglobin.
Constipation suggests a shortage of fibre, since fibre adds bulk to help food move through the gut.
Row C shows iron and fibre as the deficient components.
Answer: (C)

Question 7

What is the sequence of blood vessels that a red blood cell passes through as it travels from the vena cava to the kidney?

A. pulmonary artery → pulmonary vein → aorta → renal artery
B. pulmonary artery → pulmonary vein → aorta → renal vein
C. pulmonary vein → pulmonary artery → aorta → renal artery
D. pulmonary vein → pulmonary artery → aorta → renal vein

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B9.3: Blood vessels — Trace the pathway of blood through the heart, lungs, and body.
▶️ Answer/Explanation
Blood from the vena cava travels to the lungs via the pulmonary artery to become oxygenated.
It returns via the pulmonary vein to the heart, then leaves through the aorta.
From the aorta, oxygenated blood reaches the kidney via the renal artery.
Answer: (A)

Question 8

In the diagram of the human breathing system, which structures are correctly labelled?

A. alveoli and bronchiole
B. alveoli and trachea
C. bronchus and bronchiole
D. bronchus and trachea

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B11.1: Gas exchange in humans — Identify the structures of the breathing system.
▶️ Answer/Explanation
The trachea splits into two bronchi, which divide further into smaller bronchioles.
Bronchioles end in tiny air sacs called alveoli, where gas exchange takes place.
In the diagram, only the alveoli and the trachea are correctly labelled.
Answer: (B)

Question 9

What are the effects of adrenaline?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B13.2: Hormones — Describe the effects of adrenaline on the body.
▶️ Answer/Explanation
Adrenaline is the “fight or flight” hormone released in response to stress or danger.
It increases breathing rate and pulse rate to deliver more oxygen and glucose to the muscles.
It also widens the pupils to improve vision in an emergency.
Answer: (D)

Question 10

In a plant, what leads to offspring that are genetically identical to the parent?

A. asexual reproduction
B. insect pollination
C. seed germination
D. sexual reproduction

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B15.1: Asexual reproduction — Explain that asexual reproduction produces genetically identical offspring.
▶️ Answer/Explanation
Asexual reproduction involves only one parent and no fusion of gametes.
Because there is no mixing of genetic material from two parents, the offspring are genetically identical to the parent (clones).
Answer: (A)

Question 11

The diagram shows eggs and sperm containing sex chromosomes.

Which row gives the correct combination of sex chromosomes for a male and female offspring?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B16.1: Chromosomes and genes — Explain sex determination using X and Y chromosomes.
▶️ Answer/Explanation
Sperm can carry either an X or a Y chromosome, while all eggs carry an X chromosome.
A male offspring \( (XY) \) results from an X-egg combining with a Y-sperm, while a female offspring \( (XX) \) results from an X-egg combining with an X-sperm.
Row B shows the correct sperm-egg combinations for each.
Answer: (B)

Question 12

How do herbivores get their energy?

A. by eating animals and plants
B. by eating animals only
C. by eating plants only
D. directly from sunlight

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B18.2: Food chains and food webs — Define herbivores as primary consumers that eat only plants.
▶️ Answer/Explanation
Herbivores are animals that only eat plant material as their source of food.
Since they consume plants directly, they obtain all their energy solely by eating plants.
Answer: (C)

Question 13

The graph shows the change in atmospheric carbon dioxide levels over time.

A reduction of which process could cause the change in carbon dioxide shown?

A. combustion
B. decomposition
C. photosynthesis
D. respiration

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic B18.3: Carbon cycle — Explain how photosynthesis removes carbon dioxide from the atmosphere.
▶️ Answer/Explanation
The graph shows atmospheric CO₂ steadily increasing over the years.
Photosynthesis removes CO₂ from the atmosphere: \( 6CO_2 + 6H_2O \xrightarrow{\text{light}} C_6H_{12}O_6 + 6O_2 \).
A reduction in photosynthesis (e.g. through deforestation) means less CO₂ is removed, explaining the rising trend.
Answer: (C)

Question 14

An aqueous salt solution contains an insoluble impurity.

Which processes are used to obtain pure salt crystals?

A. distillation then crystallisation
B. distillation then chromatography
C. filtration then crystallisation
D. filtration then chromatography

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C12.4: Separation and purification — Select filtration and crystallisation to purify a soluble salt.
▶️ Answer/Explanation
Filtration is used first to remove the insoluble impurity from the salt solution.
The filtrate (pure salt solution) is then evaporated/crystallised to obtain pure salt crystals.
Answer: (C)

Question 15

The element phosphorus burns in air, as shown: \( 4P + 5O_2 \rightarrow P_4O_{10} \).

What does the formula \( P_4O_{10} \) show?

A. a mixture of atoms of two elements
B. a mixture of molecules of two elements
C. a molecule of a compound
D. an atom of a compound

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C2.2: Atomic structure and the Periodic Table — Distinguish between atoms, molecules, and compounds.
▶️ Answer/Explanation
The formula \( P_4O_{10} \) shows one unit containing 4 phosphorus atoms and 10 oxygen atoms chemically bonded together.
Since phosphorus and oxygen are different elements joined by covalent bonds, this represents a single molecule of a compound.
Answer: (C)

Question 16

Which row describes an atom that has the nucleon number 24?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C2.2: Atomic structure and the Periodic Table — Calculate nucleon number from protons and neutrons.
▶️ Answer/Explanation
The nucleon number (mass number) equals the sum of protons and neutrons: \( A = Z + N \).
For a neutral atom, the number of electrons always equals the number of protons.
Row B (12 protons, 12 neutrons, 12 electrons) gives \( 12+12 = 24 \), matching a neutral magnesium atom.
Answer: (B)

Question 17

Lithium is in Group I and bromine is in Group VII of the Periodic Table.

What is the formula of lithium bromide?

A. \( LiBr \)
B. \( LiBr_2 \)
C. \( Li_2Br \)
D. \( Li_2Br_2 \)

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C2.4: Ions and ionic bonds — Deduce the formula of an ionic compound from ionic charges.
▶️ Answer/Explanation
Lithium (Group I) forms an ion with a single positive charge: \( Li^+ \).
Bromine (Group VII) forms an ion with a single negative charge: \( Br^- \).
Since the charges are equal and opposite, they combine in a 1:1 ratio to give the formula LiBr.
Answer: (A)

Question 18

Which diagram shows equipment used to electroplate nickel with copper?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C4.1: Electrolysis — Describe the electroplating of metals using aqueous electrolytes.
▶️ Answer/Explanation
To electroplate nickel with copper, the nickel object must be the negative electrode (cathode) and copper the positive electrode (anode).
The electrolyte must be aqueous copper chloride, not molten, so that copper ions are free to move and be deposited onto the cathode.
Diagram D shows copper as the anode and nickel as the cathode in an aqueous solution.
Answer: (D)

Question 19

Which statement about exothermic and endothermic reactions is correct?

A. An endothermic reaction involves heat energy being taken in by the reactants.
B. An exothermic reaction involves heat energy being taken in by the products.
C. In an endothermic reaction, the temperature of the reaction mixture increases.
D. In an exothermic reaction, the temperature of the reaction mixture decreases.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C5.1: Exothermic and endothermic reactions — Distinguish energy changes in exothermic and endothermic reactions.
▶️ Answer/Explanation
An endothermic reaction takes in heat energy from the surroundings.
This heat energy is absorbed by the reactants to break bonds, which is why the temperature of the mixture actually decreases.
Answer: (A)

Question 20

Which statement shows that methane, \( CH_4 \), is oxidised when it burns?

A. The products of the reaction are gaseous.
B. The products of the reaction are water and carbon dioxide.
C. The reaction is exothermic.
D. The total number of oxygen atoms has increased during the reaction.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C6.3: Redox — Define oxidation as the gain of oxygen.
▶️ Answer/Explanation
Oxidation is defined as a reaction in which oxygen is gained.
When methane burns: \( CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \), carbon and hydrogen atoms gain oxygen atoms to form the products.
Since the products are water and carbon dioxide, this confirms oxygen has been gained by methane.
Answer: (B)

Question 21

Magnesium chloride is prepared by reacting an excess of insoluble magnesium oxide with dilute hydrochloric acid.

Which processes are used to obtain pure crystals of magnesium chloride from the reaction mixture?

  1. distillation
  2. evaporation
  3. filtration

A. 1 followed by 2
B. 3 followed by 2
C. 3 followed by 1
D. 1 followed by 3, followed by 2

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C7.3: Preparation of salts — Prepare a soluble salt from an insoluble base and an acid.
▶️ Answer/Explanation
Filtration is used first to remove the excess, unreacted insoluble magnesium oxide from the mixture.
The remaining magnesium chloride solution is then evaporated to concentrate it, allowing crystals to form on cooling.
Answer: (B)

Question 22

The properties of some substances are listed.

  1. form acidic oxides
  2. have high melting points
  3. act as catalysts
  4. form coloured compounds

What are the properties of transition metals?

A. 1, 2 and 3
B. 1, 2 and 4
C. 1, 3 and 4
D. 2, 3 and 4

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C8.4: Transition elements — Describe the physical and chemical properties of transition elements.
▶️ Answer/Explanation
Transition metals typically have high melting points due to strong metallic bonding.
They commonly act as catalysts in industrial reactions, such as iron in the Haber process.
They also form coloured compounds because of their variable oxidation states.
Answer: (D)

Question 23

Which statement describes a chemical test for water?

A. Add blue cobalt(II) chloride.
B. Add blue copper(II) sulfate.
C. Measure the boiling point.
D. Use universal indicator.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C10.1: Water — State the chemical test to identify water.
▶️ Answer/Explanation
Anhydrous cobalt(II) chloride is blue when dry but turns pink when water is added.
This colour change is a reliable chemical test that specifically confirms the presence of water, unlike a physical test such as measuring the boiling point.
Answer: (A)

Question 24

Which statement about sulfur is correct?

A. It is a metallic element.
B. It is used to make sulfuric acid.
C. It is in Group VII of the Periodic Table.
D. An atom of sulfur contains 32 electrons.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C9.1: Sulfur — Describe sulfur as a raw material for manufacturing sulfuric acid.
▶️ Answer/Explanation
Sulfur is a non-metallic element, found in Group VI (not VII) of the Periodic Table.
It is a key raw material used industrially to manufacture sulfuric acid, \( H_2SO_4 \), via the Contact Process.
Answer: (B)

Question 25

Which statements about limestone are correct?

  1. Its main constituent is calcium oxide.
  2. It can be used to manufacture lime.
  3. It thermally decomposes to release carbon dioxide.
  4. It is used to neutralise alkaline soils.

A. 1 and 2
B. 1 and 4
C. 2 and 3
D. 3 and 4

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C10.2: Limestone — Describe the thermal decomposition of limestone to make lime.
▶️ Answer/Explanation
Limestone’s main constituent is calcium carbonate, \( CaCO_3 \), not calcium oxide, so statement 1 is incorrect.
Limestone is heated to manufacture lime (calcium oxide), which also releases carbon dioxide: \( CaCO_3 \rightarrow CaO + CO_2 \).
Statements 2 and 3 correctly describe this thermal decomposition process.
Answer: (C)

Question 26

Petroleum is separated into fractions by fractional distillation.

Information about uses of some fractions and positions in the fractionating column where they are collected is shown.

Which rows are correct?

A. 1 and 2
B. 1 and 4
C. 2 and 3
D. 3 and 4

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C11.3: Fuels — Relate fractional distillation of petroleum to fraction uses and column position.
▶️ Answer/Explanation
In a fractionating column, fractions with lower boiling points (like refinery gas) collect at the top, while those with higher boiling points (like bitumen) collect at the bottom.
Naphtha is used to make chemicals and is collected below gasoline, while refinery gas is used for heating/cooking and is collected at the top of the column.
Rows 3 and 4 correctly describe these two fractions.
Answer: (D)

Question 27

Which process forms ethanol?

A. combustion
B. cracking
C. distillation
D. fermentation

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic C11.6: Alcohols — Describe fermentation as a method of producing ethanol.
▶️ Answer/Explanation
Fermentation is the process in which yeast breaks down sugar into ethanol and carbon dioxide: \( C_6H_{12}O_6 \rightarrow 2C_2H_5OH + 2CO_2 \).
This biological process is the standard method used to produce ethanol.
Answer: (D)

Question 28

The graph shows how the speed of an object varies with time.

What is the distance moved by the object between time 0 s and time 10 s?

A. 30 m
B. 40 m
C. 50 m
D. 80 m

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P1.2: Motion — Determine distance travelled as the area under a speed-time graph.
▶️ Answer/Explanation
Distance travelled equals the area under a speed-time graph.
The graph shows a trapezium shape between 2.0 m/s and 8.0 m/s over 10 s.
Area \( = \frac{1}{2}(2.0+8.0)\times10 = 50 \) m.
Answer: (C)

Question 29

The weight of an object of mass m is given by the expression \( mg \).

Which row gives the units for weight and \( g \)?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P1.3: Mass and weight — State the units of weight and gravitational field strength.
▶️ Answer/Explanation
Weight is a force, so it is measured in newtons (N), following \( \text{weight} = mg \).
Since \( g = \frac{\text{weight}}{\text{mass}} \), the units of \( g \) must be \( N/kg \).
Row D correctly shows N for weight and N/kg for \( g \).
Answer: (D)

Question 30

The diagrams show all the forces acting on each of four objects.

Which object is not in equilibrium?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P1.5.1: Effects of Forces — Determine whether an object is in equilibrium from force diagrams.
▶️ Answer/Explanation
An object is in equilibrium when the resultant force acting on it is zero in all directions.
Checking each diagram, the forces on object D do not balance to zero horizontally and vertically.
Answer: (D)

Question 31

The diagram shows a triangular sheet of metal with sides of length 50 cm, 40 cm and 30 cm. The sheet is free to move about a pivot at the top corner, as shown.

A cord is attached to the bottom left corner of the sheet and pulled with a horizontal force of 5.0 N to the left.

What is the moment of the 5.0 N force about the pivot?

A. 150 N cm
B. 200 N cm
C. 250 N cm
D. 600 N cm

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P1.5.2: Turning effect of forces — Calculate the moment of a force using force × perpendicular distance.
▶️ Answer/Explanation
The moment of a force is calculated using \( \text{moment} = \text{force} \times \text{perpendicular distance from the pivot} \).
The perpendicular distance from the pivot to the line of action of the horizontal force is the vertical side of the triangle, 40 cm.
So moment \( = 5.0 \times 40 = 200 \) N cm.
Answer: (B)

Question 32

A skier starts from rest at P, accelerates down a slope and then comes to rest at Q.

Which series of energy transfers takes place?

A. elastic potential (strain) energy → kinetic energy → thermal energy
B. gravitational potential energy → kinetic energy → thermal energy
C. kinetic energy → elastic potential (strain) energy → thermal energy
D. kinetic energy → gravitational potential energy → thermal energy

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P1.6.1: Energy — Trace energy transfers in a moving object down a slope.
▶️ Answer/Explanation
At P, the skier is at rest at a height, so all their energy is gravitational potential energy.
As the skier moves down the slope, this converts into kinetic energy.
At Q, the skier comes to rest, so the kinetic energy is converted into thermal energy through friction.
Answer: (B)

Question 33

Which term describes a gas changing into a liquid?

A. boiling
B. condensation
C. evaporation
D. melting

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P2.1.1: States of matter — Name the change of state from gas to liquid.
▶️ Answer/Explanation
When a gas changes into a liquid, it is losing energy and its particles are moving closer together.
This change of state is called condensation.
Answer: (B)

Question 34

A man stands 420 m away from a high wall. He bangs a drum once and starts a stop-watch at the same time. \

When he hears an echo from the wall, the stop-watch reads 2.4 s.

What is the speed of sound, calculated from this information?

A. 87.5 m/s
B. 175 m/s
C. 330 m/s
D. 350 m/s

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P3.4: Sound — Calculate the speed of sound using echo timing and distance.
▶️ Answer/Explanation
The sound travels to the wall and back again, covering a total distance of \( 2 \times 420 = 840 \) m.
Speed is calculated using \( \text{speed} = \frac{\text{distance}}{\text{time}} = \frac{840}{2.4} \).
This gives a speed of 350 m/s.
Answer: (D)

Question 35

A student stands in front of a plane mirror on a wall.

Which statement about the image of the student is not correct?

A. The image is laterally inverted (left to right).
B. The image is smaller than the student.
C. The image is upright.
D. The student and the image are equal distances from the mirror.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P3.2.1: Reflection of light — Describe the properties of an image formed in a plane mirror.
▶️ Answer/Explanation
In a plane mirror, the image formed is always the same size as the object, never smaller.
The image is also upright, laterally inverted, and the same distance behind the mirror as the object is in front of it.
Statement B is not correct, since the image is not smaller than the student.
Answer: (B)

Question 36

Two insulators are charged by rubbing them with a cloth. After this, the charged insulators repel each other.

Which statement is a possible description of how the insulators become charged?

A. One gained electrons and the other gained protons.
B. One gained electrons and the other lost electrons.
C. They both lost electrons.
D. They both lost protons.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P4.2.1: Electrical charge — Explain how insulators become charged by the transfer of electrons.
▶️ Answer/Explanation
Charging occurs by the transfer of electrons, never protons, since protons are fixed inside the nucleus.
For the two insulators to repel, they must end up with the same sign of charge.
If both lost the same amount of electrons, both become positively charged with the same sign, so they repel.
Answer: (C)

Question 37

A battery of e.m.f. V is connected across a resistor of resistance R. There is a current in the resistor.

Which row shows two changes that both increase the current in the resistor?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P4.2.2: Electric current — Apply \( I = V/R \) to determine the effect of changes in V and R on current.
▶️ Answer/Explanation
Current is related to e.m.f. and resistance by Ohm’s law: \( I = \frac{V}{R} \).
To increase the current, V must increase and/or R must decrease.
Row C shows an increase in V combined with a decrease in R, which both act to increase the current.
Answer: (C)

Question 38

Fuses are used in domestic electric circuits.

Which statement about fuses is correct?

A. A fuse is connected in the live wire.
B. A fuse is connected in the neutral wire.
C. A 3.0 A fuse produces a current of exactly 3.0 A in the circuit.
D. A 3.0 A fuse produces a minimum current of 3.0 A in the circuit.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P4.4: Electrical safety — Explain the purpose and correct wiring position of a fuse.
▶️ Answer/Explanation
A fuse is always connected in the live wire of a domestic circuit.
This ensures that if excessive current flows and the fuse blows, the live supply is cut off, making the appliance safe to touch.
Answer: (A)

Question 39

A straight wire carries a current into the page.

Which diagram shows the pattern and direction of the magnetic field around the wire due to the current?

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P4.5.3: Magnetic effect of current — Apply the right-hand grip rule to a current-carrying wire.
▶️ Answer/Explanation
The magnetic field around a straight current-carrying wire forms concentric circles around the wire.
The direction of these field lines is given by the right-hand grip rule, based on the direction of current flow.
For current flowing into the page, applying the right-hand rule gives the pattern and direction shown in diagram A.
Answer: (A)

Question 40

A radioactive isotope has a half-life of 3.0 days. A sample contains 4000 atoms of this isotope.

How many atoms of the isotope remain after 6.0 days?

A. 0
B. 500
C. 1000
D. 2000

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

Topic P5.2.4: Half-life — Calculate remaining atoms after multiple half-lives.
▶️ Answer/Explanation
The half-life of the isotope is 3.0 days, meaning the number of atoms halves every 3.0 days.
After 3.0 days (1 half-life): \( 4000 \div 2 = 2000 \) atoms remain.
After 6.0 days (2 half-lives): \( 2000 \div 2 = 1000 \) atoms remain.
Answer: (C)
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