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Question 1

(a) Reproduction is one of the characteristics of living things. Complete the definition.
Reproduction is the process that makes more of the same kind of ………………………………….
(b) Fig. 1.1 is a diagram of the male reproductive system in humans.
The boxes on the left show the letters labelling some of the parts in Fig. 1.1.
The boxes on the right show functions of some of the parts.
Draw one line to link each letter to its function.
(c) Fig. 1.2 is a drawing of a sperm cell.
Label the cell structure that contains the genetic material with a label line and the correct name.
(d) State the names of two cell structures that are present in plant cells but not present in animal cells.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic B15.4 — Sexual reproduction in humans (Parts (a), (b), (c))
• Topic B2.1 — Cell structure (Part (d))

▶️ Answer/Explanation

(a) organism

Reproduction is a characteristic of all living organisms.
It is defined as the process by which organisms produce new individuals of the same species.
This ensures the continuation of the species over generations.

(b)

A links to “produces sperm” — this is the testis.
B links to “secretes fluid for sperm to swim in” — this is a gland such as the seminal vesicle.
C links to “carries semen and urine out of the body” — this is the urethra.

(c) nucleus

The head of the sperm cell contains the nucleus.
The nucleus houses the chromosomes, which carry the genetic material (DNA).
This genetic material is passed on to the offspring during fertilisation.

(d) chloroplast; cell wall; (permanent) vacuole (any two)

Plant cells have a rigid cellulose cell wall that animal cells lack.
Plant cells also contain chloroplasts, used for photosynthesis, and a large permanent vacuole for storage and support.
Animal cells do not possess any of these three structures.

Question 2

(a)(i) There are different methods of separating mixtures.
Fig. 2.1 shows that distillation is used to separate water from aqueous potassium chloride.
Complete Fig. 2.1 to show how the other three substances are separated from the mixtures.
(ii) Name the solvent in aqueous copper sulfate.
(iii) State one use for bitumen.
(b) The treatment of a water supply uses filtration and chlorination.
Give a reason for using filtration and chlorination.
(c) Electrolysis is a process which uses electricity to break down a compound.
For example, when molten lead bromide is electrolysed, lead and bromine are made.
Complete the sentences about the electrolysis of lead bromide using words from the list.
Each word may be used once, more than once or not at all.
bromine cell electrolyte electrons hydrogen ions lead molecules negative positive
Molten lead bromide is called the …………………………………………….. because it contains …………………………………………….. which are free to move.
The …………………………………………….. electrode is called the cathode and the …………………………………………….. electrode is called the anode.
…………………………………………….. forms at the anode and …………………………………………….. forms at the cathode.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic C12.4 — Separation and purification (Part (a))
• Topic C10.1 — Water (Part (b))
• Topic C4.1 — Electrolysis (Part (c))

▶️ Answer/Explanation

(a)(i)

Chromatography separates the blue dye from black ink.
Crystallisation separates copper sulfate from aqueous copper sulfate.
Fractional distillation separates bitumen from petroleum, since it is based on different boiling points.

(a)(ii) water

In aqueous copper sulfate, water is the liquid that dissolves the solute.
Copper sulfate is the solute dissolved within it.

(a)(iii) road surfaces

Bitumen is a thick, sticky, waterproof substance obtained from fractional distillation of petroleum.
It is commonly used to surface roads.

(b) filtration – removes solid particles; chlorination – kills microbes

Filtration physically removes insoluble solid particles from the water.
Chlorination adds chlorine to kill harmful microorganisms, making the water safe to drink.

(c) electrolyte; ions; negative; positive; bromine; lead

Molten lead bromide is called the electrolyte because it contains ions free to move.
The negative electrode is the cathode, and the positive electrode is the anode.
Bromine (a non-metal) forms at the anode, and lead (a metal) forms at the cathode.

Question 3

(a) A man is sitting on a beach on a sunny day. The man is out in the Sun for too long and gets sunburned.
(i) State the name of the electromagnetic radiation that causes sunburn.
(ii) Place the electromagnetic radiation named in 3(a)(i) into the incomplete electromagnetic spectrum shown in Fig. 3.1.
(b) The man stands up. Pressure from his feet makes footprints in the sand.
State the two quantities needed to calculate this pressure.
(c) The man catches a beach ball. The ball has a mass of \(0.50 \, \text{kg}\) and a weight of \(4.9 \, \text{N}\).
Calculate the value of the gravitational field strength \(g\). State the units of your answer.
(d) Fig. 3.2 represents a water wave on the sea.
(i) Determine the wavelength of the wave.
(ii) Determine the amplitude of the wave.
(e) A piece of glass has been left on the sand.
The glass acts as a convex lens focusing the Sun’s rays onto a piece of paper lying on the sand.
(i) Complete Fig. 3.3 to show the three rays of light focused on the paper at point X.
(ii) The lens has a mass of \(5.0 \, \text{g}\) and a volume of \(2.0 \, \text{cm}^3\). Calculate the density of the glass in the lens.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P3.3 — Electromagnetic spectrum (Part (a))
• Topic P1.7 — Pressure (Part (b))
• Topic P1.3 — Mass and weight (Part (c))
• Topic P3.1 — General properties of waves (Part (d))
• Topic P3.2.3 — Thin converging lens (Part (e)(i))
• Topic P1.4 — Density (Part (e)(ii))

▶️ Answer/Explanation

(a)(i) ultraviolet

Ultraviolet (UV) radiation from the Sun damages skin cells.
This damage causes the reddening and pain known as sunburn.

(a)(ii) UV placed to the right of X-rays

The electromagnetic spectrum is arranged in order of increasing frequency from radio waves to gamma rays.
Ultraviolet has a higher frequency than visible light but lower than X-rays, so it sits immediately to the right of X-rays.

(b) surface area of feet; weight of man

Pressure is calculated using the formula \( \text{pressure} = \dfrac{\text{force}}{\text{area}} \).
Here, the force is the man’s weight, and the area is the surface area of his feet in contact with the sand.

(c) \(g = 9.8 \, \text{N/kg}\)

Gravitational field strength is calculated as \( g = \dfrac{\text{weight}}{\text{mass}} \).
\( g = \dfrac{4.9}{0.50} = 9.8 \, \text{N/kg} \).
The unit can also be expressed as \(\text{N/kg}\), equivalent to \(\text{m/s}^2\).

(d)(i) wavelength = 4.0 m

The wavelength is the distance between two consecutive identical points on the wave, such as two crests.
From the graph, one complete wave cycle spans 4 m (e.g. from 1 m to 5 m).

(d)(ii) amplitude = 1.0 m

The amplitude is the maximum displacement from the undisturbed (zero) position.
From the graph, the displacement reaches a maximum of 1.0 m.

(e)(i) three rays converging at X

A convex lens refracts parallel incoming rays of light so that they converge at a single focal point.
All three rays should be drawn bending toward and meeting at point X on the paper.

(e)(ii) density = 2.5 g/cm³

Density is calculated using \( \text{density} = \dfrac{\text{mass}}{\text{volume}} \).
\( \text{density} = \dfrac{5.0}{2.0} = 2.5 \, \text{g/cm}^3 \).

Question 4

(a) Scientists record the area of land that is cleared by deforestation every year.
Fig. 4.1 shows a bar chart of the results in one country.
(i) Calculate the percentage decrease in area cleared by deforestation between 2004 and 2007.
Give your answer to the nearest whole number.
(ii) The change in area cleared by deforestation between 1997 and 2004 affects carbon dioxide concentration in the atmosphere.
Use ideas about the carbon cycle to explain why.
(iii) Changes to the concentration of gases in the atmosphere is one undesirable effect of deforestation.
List three other undesirable effects of deforestation on the environment.
(b) State two ways that living animals transfer carbon in the carbon cycle.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic B19.1 — Habitat destruction (Part (a)(iii))
• Topic B18.3 — Carbon cycle (Parts (a)(ii), (b))
• Mathematical skills — Data handling (Part (a)(i))

▶️ Answer/Explanation

(a)(i) 2004 = 27000 km², 2007 = 11000 km², percentage change ≈ 59%

Reading the bar chart gives values of \(27000 \, \text{km}^2\) in 2004 and \(11000 \, \text{km}^2\) in 2007.
Percentage decrease \( = \dfrac{27000 – 11000}{27000} \times 100 = 59.3\% \).
Rounded to the nearest whole number, this is \(59\%\).

(a)(ii) increase in carbon dioxide; less photosynthesis

Between 1997 and 2004, the area cleared by deforestation increased.
Fewer trees means less photosynthesis occurring, so less carbon dioxide is removed from the atmosphere.
This causes carbon dioxide concentration in the atmosphere to increase.

(a)(iii) habitat destruction; extinction; soil erosion; flooding (any three)

Removing trees destroys habitats, which can lead to species extinction.
Without tree roots to bind the soil, soil erosion increases.
Loss of trees can also increase the risk of flooding, since less water is absorbed by roots.

(b) feeding; respiration (any two)

Animals transfer carbon by feeding, since carbon compounds pass along the food chain when animals eat plants or other animals.
Animals also transfer carbon through respiration, releasing carbon dioxide back into the atmosphere.

Question 5

(a) Table 5.1 shows some information about three Group VII elements.
Complete Table 5.1.
(b) State the name given to the Group VII elements in the Periodic Table.
(c) An atom of one of the isotopes of iodine contains 53 protons and 74 neutrons.
Some statements about iodine are shown below.
Place a tick (✓) to show the correct statements about iodine.
(d) Describe what is observed when aqueous silver nitrate is added to aqueous potassium chloride and to aqueous potassium bromide.
(e) A gas jar filled with air is placed on top of a gas jar filled with orange bromine vapour. After several hours, the bromine vapour has mixed with the air.
This is shown in Fig. 5.1.
Explain why the bromine mixes with the air.
Use ideas about the movement of molecules in your answer.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic C8.3 — Group VII properties (Parts (a), (b), (d))
• Topic C2.2 — Atomic structure and the Periodic Table (Part (c))
• Topic C1.1 — Solids, liquids and gases (diffusion) (Part (e))

▶️ Answer/Explanation

(a)

Bromine has the formula \(\text{Br}_2\) and is a non-metal.
Chlorine has the formula \(\text{Cl}_2\), is pale green in colour, and is also a non-metal.
Iodine is a non-metal, matching the pattern shown by the other Group VII elements.

(b) halogens

Group VII elements are collectively known as the halogens.
They are all non-metals with seven electrons in their outer shell.

(c) “All iodine atoms contain 53 electrons” and “The protons are found in the nucleus” and “The neutrons are found in the nucleus” (correct statements)

An atom is neutral, so the number of electrons equals the number of protons, which is 53.
Protons and neutrons are both located in the nucleus of the atom.
The statement about molecules containing 148 neutrons is incorrect, since not all iodine atoms are necessarily the same isotope.

(d) potassium chloride – white precipitate; potassium bromide – cream/off-white precipitate

Silver nitrate reacts with halide ions to form insoluble silver halide precipitates.
Silver chloride is white in colour, while silver bromide is cream or off-white.

(e) diffusion; random molecular movement

Bromine molecules and air molecules are in constant, random motion.
This causes bromine molecules to move from a region of high concentration to a region of low concentration.
This process, called diffusion, continues until the bromine is evenly spread throughout the air.

Question 6

(a) Fig. 6.1 shows a double electric hotplate used to heat food.
Fig. 6.2 shows the circuit diagram for the hotplates.
Hotplate A and hotplate B are identical and are connected to a \(240 \, \text{V}\) a.c. supply. Each hotplate has a resistance of \(40 \, \Omega\).
(i) Calculate the current in hotplate A.
(ii) State the term used for the circuit arrangement of the hotplates in Fig. 6.2.
(iii) Circle the correct value for the combined resistance of the two hotplates connected as shown in Fig. 6.2.
20Ω 40Ω 80Ω 1600Ω
Explain your answer.
(b) A steel saucepan containing water is placed on one of the hotplates as shown in Fig. 6.3.
(i) State the method by which thermal energy is transferred through the base of the steel saucepan.
(ii) The water at the bottom of the saucepan is heated. All the water in the saucepan is warmed by convection. On Fig. 6.3, draw arrows to show how the heated water circulates around the saucepan. One arrow has been drawn for you.
(iii) As the water in the saucepan is heated, some of the water evaporates. Choose words from the list to complete the sentences to describe evaporation.
bottom density energy mass middle surface
Water molecules escape from the …………………………………………….. of the liquid.
Only the water molecules with the greatest …………………………………………….. escape.
(iv) Eventually the water boils as it reaches the boiling point of water.
State the boiling point of water.
(v) While the water boils, the hotplate continues to heat the water in the saucepan.
State what happens to the temperature of the water when it is boiling.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P4.3.2 — Series and parallel circuits (Part (a))
• Topic P2.3.4 — Consequences of thermal energy transfer (Part (b)(i)–(ii))
• Topic P2.2.2 — Melting, boiling and evaporation (Part (b)(iii)–(v))

▶️ Answer/Explanation

(a)(i) 6 A

Current is calculated using \( I = \dfrac{V}{R} \).
\( I = \dfrac{240}{40} = 6 \, \text{A} \).

(a)(ii) parallel

Fig. 6.2 shows both hotplates connected across the same two points of the supply.
This is the arrangement known as a parallel circuit.

(a)(iii) 20 Ω

For resistors in parallel, the combined resistance is always less than the smallest individual resistance.
Since both hotplates have equal resistance of \(40 \, \Omega\), the combined resistance is \(20 \, \Omega\).

(b)(i) conduction

Thermal energy passes through the solid metal base of the saucepan by conduction.
This occurs as vibrating particles pass on energy to neighbouring particles.

(b)(ii) arrows circulating upward then outward and down

Water heated at the bottom becomes less dense and rises.
Cooler, denser water then sinks to take its place, creating a circulating convection current.

(b)(iii) surface; energy

Evaporation occurs only at the surface of the liquid.
Only the water molecules with the greatest energy have enough energy to escape into the air.

(b)(iv) 100 °C

Water boils at \(100\,^\circ\text{C}\) at standard atmospheric pressure.

(b)(v) no change in temperature

While boiling, the extra thermal energy supplied is used to change state rather than raise temperature.
So the temperature of the water remains constant at \(100\,^\circ\text{C}\) throughout boiling.

Question 7

(a) Enzymes are only active within a specific pH range.
Table 7.1 shows the specific pH range for five different enzymes.
Identify the enzyme(s) from Table 7.1 that are:
only active in acidic conditions ……………………………………………..
active over the widest range of pH values ……………………………………………..
active at pH 8. ……………………………………………..
(b) State one factor, other than pH, that affects enzyme activity.
(c) Enzymes are proteins.
Circle the elements that all enzymes contain.
calcium carbon chlorine hydrogen magnesium nitrogen oxygen
(d) Table 7.2 lists some large nutrient molecules and the smaller molecules from which they are made. Complete Table 7.2.
(e) Digested nutrients are absorbed by the body.
Place ticks (✓) in the boxes to show two correct statements about absorption.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic B5.1 — Enzymes (Parts (a), (b), (c))
• Topic B4.1 — Biological molecules (Part (d))
• Topic B7.3 — Digestion (absorption) (Part (e))

▶️ Answer/Explanation

(a) A and D; C; B and C

A (pH 1–5) and D (pH 2–3) are active only within acidic pH ranges.
C has the widest active range, from pH 7 to 12.
Both B (pH 5–9) and C (pH 7–12) are active at pH 8.

(b) temperature

Enzyme activity is also affected by temperature.
At high temperatures, enzymes become denatured and lose their activity.

(c) carbon, hydrogen, oxygen, nitrogen

Enzymes are proteins made up of amino acids.
All amino acids contain the elements carbon, hydrogen, oxygen, and nitrogen.

(d)

Fats and oils are made from fatty acids and glycerol.
Proteins are made from amino acids.
Both starch and glycogen are made up of smaller glucose molecules.

(e)

Absorption is the movement of small, soluble, digested food molecules into the bloodstream.
This process occurs across the wall of the small intestine, which is adapted with a large surface area for absorption.

Question 8

(a) Fig. 8.1 shows the apparatus a student uses to investigate the rate of reaction between magnesium and dilute hydrochloric acid.
Hydrogen gas is collected in the measuring cylinder.
The other product is aqueous magnesium chloride.
(i) Construct the word equation for this reaction.
…………………………. + …………………………. → …………………………. + ………………………….
(ii) State two changes to the reaction conditions that increase the rate of reaction.
(iii) The reaction between magnesium and dilute hydrochloric acid is exothermic. State the meaning of exothermic.
(iv) The student repeats the experiment using three different metals, copper, iron and calcium.
The observations are shown in Table 8.1.
Place the four metals in order of their reactivity from the most reactive to the least reactive.
(b) Table 8.2 shows information about the four metals in a magnesium alloy.
(i) Calculate the percentage of magnesium contained in the alloy.
(ii) Calculate the mass of aluminium contained in \(20 \, \text{kg}\) of the alloy.
(iii) Suggest why, apart from cost, this alloy of magnesium is used rather than pure magnesium for making parts for car engines.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic C6.2 — Rate of reaction (Parts (a)(i), (ii)); Topic C5.1 — Exothermic and endothermic reactions (Part (a)(iii))
• Topic C9.4 — Reactivity series (Part (a)(iv))
• Topic C9.3 — Alloys and their properties (Part (b))

▶️ Answer/Explanation

(a)(i) magnesium + hydrochloric acid → magnesium chloride + hydrogen

Magnesium reacts with hydrochloric acid to form a salt and hydrogen gas.
The salt formed is magnesium chloride, and hydrogen is released and collected in the cylinder.

(a)(ii) increase temperature; increase concentration (any two)

Increasing the temperature of the acid gives particles more kinetic energy, increasing collision frequency.
Increasing the concentration of the acid, or decreasing the particle size of magnesium, also increases the rate of reaction.

(a)(iii) releases thermal energy

An exothermic reaction is one that releases thermal energy to the surroundings.
This is why the temperature of the reaction mixture increases during the reaction.

(a)(iv) calcium, magnesium, iron, copper

Calcium reacts most rapidly, so it is the most reactive of the four metals.
Copper does not react at all, making it the least reactive.
Magnesium and iron fall in between, with magnesium reacting faster than iron.

(b)(i) 89%

The percentages of aluminium, manganese, and zinc total \(9.0 + 1.0 + 1.0 = 11.0\%\).
Since all percentages must sum to 100%, magnesium makes up \(100 – 11 = 89\%\).

(b)(ii) 1.8 kg

Aluminium makes up 9.0% of the alloy.
Mass of aluminium \( = \dfrac{9.0}{100} \times 20 = 1.8 \, \text{kg}\).

(b)(iii) stronger

Pure metals have layers of identical-sized atoms that can slide over each other easily.
Adding other elements to form an alloy disrupts this regular arrangement, making the alloy stronger and harder than the pure metal.

Question 9

(a) Fig. 9.1 shows four energy sources and four descriptions of energy sources.
Draw one straight line from each energy source to the correct description of the energy source.
(b) Nuclear fuels are used to generate electricity in a nuclear power station.
State the name of the process by which a nuclear fuel produces heat.
(c) Plutonium-239 is an example of a nuclear fuel.
Plutonium-239 has the nuclide notation \(^{239}_{94}\text{Pu}\).
Determine the number of neutrons in one atom of plutonium-239.
(d)(i) Plutonium-239 decays by alpha emission.
The decay product is uranium-235.
Write the word equation for this decay process.
(ii) Describe an alpha particle.
(e) α-particles, β-particles, and γ-radiation are three radioactive emissions.
Place the three emissions in order of their ionising ability.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P1.6.3 — Energy resources (Part (a))
• Topic P5.1 — The nucleus (Part (c)); Topic P5.2.3 — Radioactive decay (Part (b), (d))
• Topic P5.2.2 — The three types of nuclear emission (Part (e))

▶️ Answer/Explanation

(a)

Geothermal energy uses energy from inside the Earth.
Hydroelectric (HEP) uses energy from falling water.
Nuclear energy produces dangerous waste, and wind energy is unreliable since it depends on wind conditions.

(b) (nuclear) fission

In a nuclear power station, heat is produced by nuclear fission.
This is the splitting of large, unstable nuclei into smaller nuclei, releasing energy.

(c) 145

The nucleon (mass) number is 239, and the proton (atomic) number is 94.
Number of neutrons \( = 239 – 94 = 145\).

(d)(i) plutonium-239 → uranium-235 + alpha particle

During alpha decay, the nucleus emits an alpha particle.
This causes the mass number to decrease by 4 and the atomic number by 2, forming uranium-235 from plutonium-239.

(d)(ii) helium nucleus / 2 protons and 2 neutrons

An alpha particle consists of 2 protons and 2 neutrons.
This is identical in composition to the nucleus of a helium atom.

(e) alpha, beta, gamma (most to least ionising)

Alpha particles are the most strongly ionising due to their larger mass and charge.
Gamma radiation is the least ionising, as it has no mass or charge and interacts weakly with matter.

Question 10

(a) Fig. 10.1 is a diagram of a cross-section through a leaf.
(i) State the name of the part labelled X and the cell labelled Y in Fig. 10.1.
(ii) Draw one arrow on Fig. 10.1 to show the pathway of water vapour during transpiration.
(b) Fig. 10.2 is an incomplete sketch graph.
Complete Fig. 10.2 to show the effect of humidity on the rate of transpiration by:
  • including axis labels
  • drawing a line to show the trend.
(c) State the name of the type of plant cell that absorbs water from the soil.
(d) State the name of the plant tissue that transports water from the roots to the leaves.
(e) Suggest one reason why not all the water absorbed is lost through transpiration.
(f) Blood has several functions including transport in humans.
(i) State one function of white blood cells.
(ii) State two other main components of blood.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic B6.2 — Leaf structure (Parts (a), (b))
• Topic B8.2 — Water uptake (Part (c))
• Topic B8.1 — Xylem and phloem (Part (d))
• Topic B8.2 — Water uptake (Part (e))
• Topic B9.4 — Blood (Part (f))

▶️ Answer/Explanation

(a)(i) X – (upper) epidermis; Y – spongy mesophyll

X is the outer layer of cells covering the leaf, called the (upper) epidermis.
Y is a loosely packed cell type located below the palisade layer, called spongy mesophyll.

(a)(ii) arrow from inside the leaf out through a stoma

Water vapour diffuses out of the air spaces inside the leaf.
It exits the leaf through a stoma, typically found on the lower epidermis.

(b) axis labels; negative correlation

The x-axis should be labelled humidity, and the y-axis labelled rate of transpiration.
As humidity increases, the rate of transpiration decreases, so the line should show a negative correlation.

(c) root hair cell

Root hair cells have long, thin extensions that increase the surface area for water absorption.
This adaptation allows efficient uptake of water from the soil.

(d) xylem

Xylem tissue is responsible for transporting water and dissolved mineral ions.
It carries this from the roots up through the stem to the leaves.

(e) used in photosynthesis / used for support

Not all absorbed water is lost through transpiration.
Some of the water is used in photosynthesis, and some provides turgor pressure for support of the plant.

(f)(i) phagocytosis / production of antibodies

White blood cells help defend the body against disease.
They do this through phagocytosis, engulfing pathogens, or by producing antibodies.

(f)(ii) red blood cells; plasma; platelets (any two)

Besides white blood cells, blood also contains red blood cells, which transport oxygen.
It also contains plasma, the liquid component, and platelets, which help blood clotting.

Question 11

(a) Sodium forms a basic oxide. Carbon forms acidic oxides. State why they are different.
(b) Carbon is a solid and carbon dioxide is a gas.
Describe the differences between a solid and a gas using ideas about particle separation and particle motion.
(c) Diamond is one form of carbon. Fig. 11.1 shows the arrangement of carbon atoms in diamond.
Circle two words from the list to describe the structure and bonding in diamond.
simple giant metallic ionic covalent polymer
(d)(i) Sodium metal reacts with chlorine gas to make sodium chloride.
Balance the symbol equation for this reaction.
……..Na + \(\text{Cl}_2\) → ……..NaCl
(ii) During the reaction sodium atoms form sodium ions, \(\text{Na}^+\), and chlorine atoms form chloride ions, \(\text{Cl}^-\).
Fig. 11.2 shows the electronic structure of a sodium ion and a chloride ion.
Write down the electronic structure of a sodium atom and a chlorine atom.
(iii) Sodium and lithium are both in Group I of the Periodic Table.
Sodium reacts violently with water.
Describe the reaction of lithium with water.
Describe the trend in the reactivity of Group I elements as shown by sodium and lithium.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic C7.2 — Oxides (Part (a))
• Topic C1.1 — Solids, liquids and gases (Part (b))
• Topic C2.6 — Giant covalent structures (Part (c))
• Topic C2.4 — Ions and ionic bonds (Part (d)(i), (ii))
• Topic C8.2 — Group I properties (Part (d)(iii))

▶️ Answer/Explanation

(a) non-metals form acidic oxides; metals form basic oxides

Sodium is a metal, and metals typically form basic oxides.
Carbon is a non-metal, and non-metals typically form acidic oxides.

(b) particle separation: solid closer together, gas further apart; particle motion: solid vibrates about a fixed point, gas moves freely and faster

In a solid, particles are packed closely together and only vibrate about fixed positions.
In a gas, particles are far apart and move freely and rapidly in random directions.

(c) giant; covalent

Diamond consists of a giant covalent (macromolecular) structure.
Each carbon atom forms four strong covalent bonds with neighbouring carbon atoms.

(d)(i) \(2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}\)

The equation must be balanced so the number of atoms of each element is equal on both sides.
Using a coefficient of 2 for both sodium and sodium chloride balances the equation.

(d)(ii) sodium atom: 2,8,1; chlorine atom: 2,8,7

A sodium atom has the electronic structure 2,8,1, with one electron in its outer shell.
A chlorine atom has the electronic structure 2,8,7, with seven electrons in its outer shell.
During the reaction, sodium loses its outer electron to chlorine, forming ions with full outer shells.

(d)(iii) reaction: lithium reacts less rapidly/vigorously than sodium; explanation: reactivity increases down Group I

Lithium reacts with water, but less vigorously and more slowly than sodium.
This shows that as you go down Group I, the reactivity of the metals increases.

Question 12

(a) Fig. 12.1 is a distance–time graph for two cyclists A and B who are racing for a distance of \(1000 \, \text{m}\).
(i) Calculate the time difference over the \(1000 \, \text{m}\) for cyclist A compared to cyclist B.
(ii) Calculate the speed of cyclist B.
(iii) Describe how the graph shows that cyclist B moves at a constant speed.
(b)(i) Fig. 12.2 shows a cyclist moving along a flat road.
Choose words or phrases from the list to complete the sentence.
Each word or phrase may be used once, more than once or not at all.
chemical potential elastic potential gravitational potential kinetic
As the cyclist’s speed increases, the …………………………………………….. energy in the cyclist’s body decreases and the …………………………………………….. energy of the cyclist increases.
(ii) As the cyclist rides along the road, the temperature of the air in the tyres increases.
Describe the change in the motion of the air molecules.
(c) The cyclist has a tyre puncture and needs to remove the wheel.
Fig. 12.3 shows the wheel nut that must be unscrewed.
The cyclist has two spanners X and Y which can be used to unscrew the wheel nut.
Fig. 12.4 shows the two spanners.
Explain why spanner X will unscrew the wheel nut more easily than spanner Y.

Most-appropriate topic codes (Cambridge IGCSE Co-ordinated Sciences 0654):

• Topic P1.2 — Motion (Part (a))
• Topic P1.6.1 — Energy (Part (b)(i)); Topic P2.1.2 — Particle model (Part (b)(ii))
• Topic P1.5.2 — Turning effect of forces (Part (c))

▶️ Answer/Explanation

(a)(i) 20 s

From the graph, cyclist A reaches \(1000 \, \text{m}\) at \(100 \, \text{s}\), and cyclist B reaches it at \(120 \, \text{s}\).
Time difference \( = 120 – 100 = 20 \, \text{s}\).

(a)(ii) 8.3 m/s

Speed is calculated using \( \text{speed} = \dfrac{\text{distance}}{\text{time}} \).
\( \text{speed} = \dfrac{1000}{120} = 8.3 \, \text{m/s} \) (or \(8.33 \, \text{m/s}\)).

(a)(iii) constant gradient

The line for cyclist B on the distance–time graph is a straight line.
A straight line has a constant gradient, which indicates the cyclist is moving at a constant speed.

(b)(i) chemical (potential); kinetic

The cyclist’s body stores energy as chemical potential energy.
As the cyclist speeds up, this chemical potential energy is converted into kinetic energy.

(b)(ii) molecules move faster

As temperature increases, the air molecules inside the tyre gain kinetic energy.
This causes the molecules to move faster.

(c) X is longer, so provides a greater moment

The moment (turning effect) of a force is calculated as \( \text{moment} = \text{force} \times \text{perpendicular distance} \).
Since spanner X is longer than spanner Y, the same applied force produces a greater moment.
This greater moment makes it easier to unscrew the wheel nut.

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