Home / A level Biology 16.1 Passage of information from parents to offspring – Exam style question – Paper 4

A level Biology 16.1 Passage of information from parents to offspring – Exam style question – Paper 4

Question

The tiger barb, Puntigrus tetrazona, is a South American fish that is popular worldwide as an aquarium fish. Fig. 6.1 shows the appearance (phenotype) of a normal (wild-type) tiger barb.

• Tiger barbs that show a wild-type phenotype are gold with black stripes.
• Tiger barbs that show an albino phenotype are gold with white stripes.
• In 2012, a fish breeder discovered a tiger barb with a new, transparent, phenotype. This fish had a transparent body and black stripes.

The fish breeder crossed the tiger barb showing the new transparent phenotype with a tiger barb showing the albino phenotype.

All the F1 offspring were wild-type. These F1 offspring were crossed with each other.

Table 6.1 shows the phenotypes obtained in the F2 generation and the number of fish showing each phenotype.

 

(a) (i) The fish breeder concluded that the new transparent phenotype had occurred because of a mutation.

Explain how the results in Table 6.1 support this conclusion.

(a) (ii) State the approximate whole-number ratio shown by the results in Table 6.1.

(a) (iii) Explain what the results in Table 6.1 show about the genes and alleles that determine the wild-type, albino and the two different transparent phenotypes in tiger barbs.

(b) The F1 tiger barbs all looked the same but the F2 offspring showed variation. The F2 offspring showed four different phenotypes.

Describe the processes that occurred during meiosis in the F1 fish that allowed this variation to occur.

▶️ Answer/Explanation
Solution

(a) (i)

The results support the mutation conclusion because:

  1. The transparent phenotype reappeared in the F2 generation but was not present in the F1 generation, showing it’s an inherited trait rather than an environmental effect.
  2. The pattern of inheritance follows Mendelian genetics, suggesting the transparent phenotype is caused by a new recessive allele that arose through mutation.
  3. The transparent phenotype wasn’t present in either parent population before 2012, indicating it’s a new genetic variant.

(a) (ii)

The approximate whole-number ratio is 9:3:3:1 (wild-type:albino:transparent with black stripes:transparent with white stripes).

This can be seen by dividing all numbers by the smallest count (19):
173 ÷ 19 ≈ 9, 57 ÷ 19 ≈ 3, 58 ÷ 19 ≈ 3, 19 ÷ 19 = 1

(a) (iii)

The results show that:

  1. There are two genes involved in determining these phenotypes.
  2. The genes are on separate chromosomes (not linked) as shown by the 9:3:3:1 ratio.
  3. Both genes have two alleles each – one dominant and one recessive.
  4. The albino (white stripes) phenotype is caused by a recessive allele at one gene.
  5. The transparent body phenotype is caused by a recessive allele at the other gene.
  6. The wild-type phenotype is dominant for both genes (gold with black stripes).
  7. The phenotypes are not sex-linked as they appear in both sexes.

(b)

The variation in F2 offspring occurs through these meiotic processes:

  1. Independent assortment of chromosomes during metaphase I, where homologous chromosome pairs align randomly at the cell equator.
  2. Crossing over during prophase I, where homologous chromosomes exchange genetic material, creating new allele combinations.
  3. Random segregation of chromosomes during anaphase I, where each homologous chromosome moves randomly to opposite poles.
  4. Separation of sister chromatids during anaphase II, further increasing genetic diversity.
  5. Each F1 fish produces gametes with different combinations of the alleles for color and transparency.
  6. When these gametes randomly combine during fertilization, they produce the four different phenotypes seen in the F2 generation.

This meiotic variation explains why the F2 generation shows all possible combinations of the parental traits in the classic 9:3:3:1 dihybrid ratio.

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