Question
Consider the function f(x) = \(\frac{x^{2}-4}{x-2}\)
(a) Find \(lim_{x\to 2}\)f(x).
(b) Is f(x) continuous at x=2? Explain why or why not.
▶️Answer/Explanation
(a) We can simplify the function by factoring the numerator:
\(f(x) = \frac{(x-2) -(x+2)}{x-2}=x+2\)
Now, we can find the limit:
\(lim_{x\to 2}\)f(x) = \(lim_{x\to 2}\)(x+2) = 2+2 = 4
(b) No, f(x) is not continuous at x=2. The function is undefined at x=2 because it would result in division by zero.