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AP Calculus AB: 3.1 The Chain Rule – Exam Style questions with Answer- MCQ

Question

\(\frac{\mathrm{d} }{\mathrm{d} x}(x^{3}\sec (2x))\)=

A \(6x^{2}\sec (2x)\tan (2x)\)

B \(2x^{3}\tan ^{2}(2x)+3x^{2} \sec (2x)\)

C \(x^{3}\sec (2x)\tan (2x)+3x^{2}\sec (2x)\)

D \(2x^{3}\sec (2x)\tan (2x)+3x^{2}\sec (2x)\)

▶️Answer/Explanation

Ans:D

Question

\(\frac{\mathrm{d} }{\mathrm{d} x}(2(\sin \sqrt{x})^{2})\)

A \(4\cos (\frac{1}{2\sqrt{2}})\)

B \(4\sin \sqrt{x}\cos \sqrt{x}\)

C \(\frac{2\sin \sqrt{x}}{\sqrt{x}}\)

D \(\frac{2\sin \sqrt{x}\cos \sqrt{x}}{\sqrt{x}}\)

▶️Answer/Explanation

Ans:D

Question

If f is a differentiable function and \(y=\sin (f(x^{2}))\) what is \(\frac{\mathrm{d} y}{\mathrm{d} x}\) when x = 3 ?

A \(\cos (f{}'(9))\)

B \(6\cos (f{}(9))\)

C \(f{}'(9)\cos (f(9))\)

D \(6f{}'(9)\cos (f(9))\)

▶️Answer/Explanation

Ans:D

Question

If \(f(x)=\sin (x^{2}+\pi )\) ,then \(f{}'(\sqrt{2\pi })\)

A \(-2\sqrt{2\pi }\)

B -2

C -1

D \(\cos (2\sqrt{2})\)

▶️Answer/Explanation

Ans:A

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