AP Calculus AB : 8.5 Finding the Area Between Curves Expressed as Functions of y- Exam Style questions with Answer- MCQ

Question

 The area of the region bounded by the lines x x = 0, 2, = and y = 0 and the curve \(y=e^{\frac{x}{2}}\) is

(A)\(\frac{e-1}{2} \)        (B) e −1                                (C) 2 (e −1 )                             (D) 2 e −1                                                        (E) 2e

▶️Answer/Explanation

Ans:C

\(Area =\int_{0}^{2}e^{\frac{x}{2}} dx=2e^{\frac{x}{2}}\)

Question

What is the area of the region completely bounded by the curve  \(y=-x^{2}+x+6\) and the line y = 4 ?
(A) \(\frac{3}{2}\)
(B) \(\frac{7}{3}\)
(C) \(\frac{9}{2}\)
(D) \(\frac{31}{6}\)
(E) \(\frac{33}{2}\)

▶️Answer/Explanation

Ans:C

Question

 If\( y = 2x – 8\) , what is the minimum value of the product xy ?
(A) –16                                     (B) –8                                        (C) –4                           (D) 0                                              (E) 2

▶️Answer/Explanation

Ans:B

\(p(x)=2x^2-8x;P'(x)=4x-8;p\)’; changes from negative to positive at x= 2.p (2)= 8

Scroll to Top