AP Calculus BC 10.2 Working with Geometric Series Study Notes - New Syllabus
AP Calculus BC 10.2 Working with Geometric Series Study Notes- New syllabus
AP Calculus BC 10.2 Working with Geometric Series Study Notes – AP Calculus BC- per latest AP Calculus BC Syllabus.
LEARNING OBJECTIVE
- Applying limits may allow us to determine the finite sum of infinitely many terms.
Key Concepts:
- Working with Geometric Series
Working with Geometric Series
Working with Geometric Series
A geometric series is a series in which each term is obtained by multiplying the previous term by a constant ratio \( r \).
The general form of a geometric series is:
\( a + ar + ar^2 + ar^3 + \dots \)
where:
- \( a \) is the first term
- \( r \) is the common ratio
Sum of the First \( n \) Terms
The sum of the first \( n \) terms (partial sum) is:
\( S_n = \dfrac{a(1 – r^n)}{1 – r} \) for \( r \neq 1 \)
Sum of an Infinite Geometric Series
If \( |r| < 1 \), the series converges, and the sum is:
\( S = \dfrac{a}{1 – r} \)
If \( |r| \geq 1 \), the series diverges (sum does not exist).
Properties of Geometric Series
- If \( r > 0 \), terms keep the same sign.
- If \( r < 0 \), the terms alternate in sign.
- For \( |r| < 1 \), terms get smaller in magnitude and approach zero.
Example
Find the sum of the first 8 terms of the geometric series \( 3 + 6 + 12 + 24 + \dots \).
▶️ Answer/Explanation
Here, \( a = 3 \), \( r = \dfrac{6}{3} = 2 \), \( n = 8 \).
Since \( r \neq 1 \), we use:
\( S_n = \dfrac{a(1 – r^n)}{1 – r} \)
\( S_8 = \dfrac{3(1 – 2^8)}{1 – 2} \)
\( S_8 = \dfrac{3(1 – 256)}{-1} = \dfrac{3(-255)}{-1} = 765 \)
Final Answer: \( S_8 = 765 \)
Example
Find the sum of the infinite geometric series \( 5 + 2.5 + 1.25 + 0.625 + \dots \).
▶️ Answer/Explanation
Here, \( a = 5 \), \( r = \dfrac{2.5}{5} = 0.5 \).
Since \( |r| = 0.5 < 1 \), the series converges and we use:
\( S = \dfrac{a}{1 – r} \)
\( S = \dfrac{5}{1 – 0.5} = \dfrac{5}{0.5} = 10 \)
Final Answer: \( S = 10 \)
Example
Determine whether the geometric series \( 7 – 14 + 28 – 56 + \dots \) converges or diverges.
▶️ Answer/Explanation
Here, \( a = 7 \), \( r = \dfrac{-14}{7} = -2 \).
Since \( |r| = 2 > 1 \), the series diverges.
Final Answer: Divergent, sum does not exist.