AP Calculus BC : 8.4 Finding the Area Between Curves Expressed as Functions of x- Exam Style questions with Answer- MCQ

Question

 The area of the region between the graph of \(y= 4x^3 +2\) and the x-axis from \(x =1\) to \(x = 2\) is

(A) 36                 (B) 23                 (C) 20                     (D) 17                       (E) 9

Answer/Explanation

Ans:D

 

Question 

The area of the region in the first quadrant enclosed by the graph of y = x(x-1 )  and the x-axis is
(A) \(\frac{1}{6}\)                       (B) \(\frac{1} {3}\)                  (C) \(\frac{2}{3}\)                                 (D) \(\frac{5}{6}\)                                     (E) 1

Answer/Explanation

Ans:A

 

Question

 If you were to use 3 midpoint rectangles of equal length to approximate the area under the curve of \(f(x)=x^{2}+2\) from x = 0 to x = 3, how close would the approximation be to the exact area under the curve?

(A) \(\frac{1}{2}\)
(B) \(\frac{1}{4}\)
(C) \(\frac{1}{8}\)
(D) \(\frac{3}{4}\)

Answer/Explanation

Ans:(B)

The exact area is computed
\(\int_{0}^{3}x^{2}+2dx=\left [ \frac{x^{3}}{3} +2x\right ]^{3}_{0}=9+6=15\)
The approximation using 3 midpoint rectangles is computed
\(\sum_{i=1}^{3}f(x_{i})\left ( \frac{3-0}{3} \right )=f\left ( \frac{1}{2} \right ).1+f\left ( \frac{3}{2} \right ).1+f\left ( \frac{5}{2} \right ).1=\frac{9}{4}+\frac{17}{4}+\frac{33}{4}=\frac{59}{4}\) or 14.75

 Question

 Find the exact area of the region bounded by the graph of \(f(x)=\sin x\) , \(g(x)=\cos x \), and the lines x = 0 to x = π/2.
(A) \(\sqrt{2}\)
(B) 1
(C) \(\sqrt{2}-2\)
(D) \(2(\sqrt{2}-1)\)

Answer/Explanation

Ans:(D)

The area of this region may be attained by computing 

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