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AP Chemistry 1.6 Photoelectron Spectroscopy Study Notes - New Syllabus 2024-2025

AP Chemistry 1.6 Photoelectron Spectroscopy Study Notes- New syllabus

AP Chemistry 1.6 Photoelectron Spectroscopy Study Notes – AP Chemistry – per latest AP Chemistry Syllabus.

LEARNING OBJECTIVE

  • Explain the relationship between the photoelectron spectrum of an atom or ion and:
    i. The ground-state electron configuration of the species.
    ii. The interactions between the electrons and the nucleus.

Key Concepts: 

  • Photoelectron Spectroscopy

AP Chemistry-Concise Summary Notes- All Topics

Photoelectron Spectroscopy (PES)

Photoelectron spectroscopy is an experimental technique used to measure the energies of electrons in atoms and ions. High-energy photons (usually ultraviolet or X-rays) strike the atom, causing electrons to be ejected. The kinetic energy of the emitted electron is measured and used to calculate the binding (ionization) energy.

 

The Photoelectric Effect

When a photon of energy \( E_{photon} \) hits an atom:

\( E_{photon} = E_{binding} + E_{kinetic} \)

  • \( E_{binding} \): the energy holding the electron in the atom (ionization energy).
  • \( E_{kinetic} \): the measured kinetic energy of the ejected electron.

Thus, the binding energy can be determined as:

\( E_{binding} = E_{photon} – E_{kinetic} \)

Photoelectron Spectrum

A photoelectron spectrum is a graph with:

  • x-axis: Binding energy (in eV).
  • y-axis: Relative number of electrons detected (intensity/peaks).

Each peak corresponds to electrons from a specific subshell (1s, 2s, 2p, etc.).
The area under a peak = number of electrons in that subshell.

Relationship to Ground-State Electron Configuration

  • Peaks in the spectrum correspond directly to subshells in the electron configuration.
  • For example, a peak with 2 electrons → s subshell; a peak with 6 electrons → p subshell.
  • The relative sizes of the peaks match the number of electrons in each subshell.
  • The order of binding energies reflects the relative distances of the subshells from the nucleus: \( 1s > 2s > 2p > 3s \), etc.

Coulomb’s Law and Electron-Nucleus Interaction

PES data can be explained by Coulomb’s law:

\( F = k \dfrac{q_1 q_2}{r^2} \)

  • Electrons closer to the nucleus (smaller \( r \)) experience stronger attraction → higher binding energy.
  • Greater effective nuclear charge (\( Z_{eff} \)) increases attraction → higher binding energy.
  • Core electrons show much higher binding energies than valence electrons.
  • Shielding by inner electrons reduces nuclear attraction felt by outer electrons, giving them lower binding energies.

Example

The photoelectron spectrum of oxygen shows two main peaks: one at high binding energy (2 electrons) and one at lower binding energy (6 electrons). Explain how this relates to the electron configuration of oxygen.

▶️ Answer/Explanation

Oxygen electron configuration: \( 1s^2 2s^2 2p^4 \).
• The high-energy (large binding energy) peak corresponds to 1s electrons (2 electrons).
• The lower-energy peaks correspond to 2s (2 electrons) and 2p (4 electrons).
• Thus, the spectrum directly confirms the ground-state configuration.

Example

Why do the 1s electrons in oxygen have a much higher binding energy than the 2p electrons?

▶️ Answer/Explanation

The 1s electrons are closer to the nucleus (smaller \( r \)) and experience little shielding, so they feel nearly the full nuclear charge. According to Coulomb’s law, this strong attraction gives them a very high binding energy. The 2p electrons are farther from the nucleus and shielded by 1s and 2s electrons, so their binding energy is lower.

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