AP Chemistry 3.10 Solubility Study Notes - New Syllabus 2024-2025
AP Chemistry 3.10 Solubility Study Notes- New syllabus
AP Chemistry 3.10 Solubility Study Notes – AP Chemistry – per latest AP Chemistry Syllabus.
LEARNING OBJECTIVE
Explain the relationship between the solubility of ionic and molecular compounds in aqueous and nonaqueous solvents, and the intermolecular interactions between particles.
Key Concepts:
- Solubility and Intermolecular Interactions
Solubility and Intermolecular Interactions
The solubility of a substance in a given solvent depends on the similarity and relative strength of the intermolecular interactions between the solute and solvent particles. The general rule governing solubility is expressed as: “Like dissolves like.” This means that substances with similar types of intermolecular forces tend to be soluble or miscible in each other.
1. Types of Intermolecular Interactions Affecting Solubility:
Ionic–Dipole Interactions: Occur when ionic compounds (such as salts) dissolve in polar solvents like water.
- The cations (\(\mathrm{Na^+}\), \(\mathrm{K^+}\)) are attracted to the partially negative oxygen end (δ⁻) of water molecules.
- The anions (\(\mathrm{Cl^-}\), \(\mathrm{SO_4^{2-}}\)) are attracted to the partially positive hydrogen ends (δ⁺) of water molecules.
- These ion–dipole attractions overcome the ionic lattice forces, leading to dissociation and solvation (hydration).
Dipole–Dipole and Hydrogen Bonding Interactions: Occur among polar molecular compounds.
- Polar molecules dissolve best in polar solvents because both experience dipole–dipole attractions or hydrogen bonding.
- For example, ethanol (\(\mathrm{C_2H_5OH}\)) dissolves readily in water because both can form hydrogen bonds.
London Dispersion Forces: Dominant in nonpolar substances.
- Nonpolar molecules (e.g., hexane, benzene, iodine) dissolve in nonpolar solvents because both interact through temporary induced dipoles.
- Since there are no strong dipole or ion–dipole interactions to disrupt, solubility depends mainly on molecular size and polarizability.
2. Solubility Patterns and Examples:
Ionic Compounds in Polar Solvents:
- Ionic solids such as \(\mathrm{NaCl}\) dissolve in water because the strong ion–dipole attractions between ions and water molecules compensate for the lattice energy of the salt. Conversely, \(\mathrm{NaCl}\) is insoluble in hexane (a nonpolar solvent) because there are no strong attractive forces between ions and hexane molecules.
Molecular Compounds in Polar Solvents:
- Polar molecular solutes (like \(\mathrm{NH_3}\), \(\mathrm{CH_3OH}\)) dissolve readily in water via hydrogen bonding or dipole–dipole attractions.
Nonpolar Compounds in Nonpolar Solvents:
- Nonpolar solutes such as \(\mathrm{I_2}\) or \(\mathrm{CCl_4}\) dissolve in nonpolar solvents (like benzene or hexane) due to similar dispersion forces.
Immiscibility of Polar and Nonpolar Substances:
- Polar and nonpolar liquids (e.g., water and oil) do not mix because the strong hydrogen bonding network in water cannot be disrupted by weak London forces from oil molecules.
3. Microscopic Explanation of Solubility:
When a solute dissolves, three types of interactions are considered:
- Solute–solute attractions (e.g., ionic lattice or hydrogen bonds within solute)
- Solvent–solvent attractions (e.g., hydrogen bonds between water molecules)
- Solute–solvent attractions (new interactions formed during dissolution)
For dissolution to occur:
- The energy released by forming solute–solvent interactions must be comparable to or greater than the energy required to break solute–solute and solvent–solvent interactions.
- If solute–solvent forces are weaker, the solute will not dissolve appreciably.
Example :
Explain why sodium chloride (\(\mathrm{NaCl}\)) dissolves in water but not in hexane (\(\mathrm{C_6H_{14}}\)).
▶️ Answer/Explanation
Step 1: \(\mathrm{NaCl}\) is ionic, composed of positive and negative ions held together by strong electrostatic attractions.
Step 2: Water is polar and forms strong ion–dipole interactions with both \(\mathrm{Na^+}\) and \(\mathrm{Cl^-}\).
Step 3: These interactions compensate for the energy required to break the ionic lattice, allowing \(\mathrm{NaCl}\) to dissolve.
Step 4: Hexane is nonpolar and lacks permanent dipoles, so it cannot stabilize ions via ion–dipole forces.
Final Answer: \(\mathrm{NaCl}\) dissolves in water due to strong ion–dipole attractions but remains insoluble in hexane because there are no comparable attractive forces between the ions and the solvent.
Example :
Explain why ethanol (\(\mathrm{C_2H_5OH}\)) is miscible with water, while hexane (\(\mathrm{C_6H_{14}}\)) is not.
▶️ Answer/Explanation
Step 1: Both ethanol and water are polar molecules capable of hydrogen bonding.
Step 2: When mixed, hydrogen bonds form between the –OH group of ethanol and water molecules, creating a uniform mixture (miscible).
Step 3: Hexane, however, is nonpolar and cannot form hydrogen bonds with water molecules.
Step 4: The strong hydrogen bonding network among water molecules excludes nonpolar hexane, causing phase separation.
Final Answer: Ethanol dissolves in water because both exhibit hydrogen bonding, while hexane does not because its nonpolar London forces cannot compete with water’s hydrogen bonding.