Home / AP® Exam / AP® Chemistry / AP Chemistry 8.5 Acid-Base Titrations Study Notes

AP Chemistry 8.5 Acid-Base Titrations Study Notes

AP Chemistry 8.5 Acid-Base Titrations Study Notes - New Syllabus Effective fall 2024

AP Chemistry 8.5 Acid-Base Titrations Study Notes- New syllabus

AP Chemistry 8.5 Acid-Base Titrations Study Notes – AP Chemistry –  per latest AP Chemistry Syllabus.

LEARNING OBJECTIVE

Explain results from the titration of a mono- or polyprotic acid or base solution, in relation to the properties of the solution and its components.

Key Concepts: 

  • Titration Curves & Equivalence Points
  • Titration Curves & Half-Equivalence Points
  • Titration Curves of Polyprotic Acids

AP Chemistry-Concise Summary Notes- All Topics

8.5.A.1  Titration Curve:

1. Acids and Bases:

i. Strong Acids and Bases:

These fully dissociate in water, i.e., 100% of the acid or base molecules disintegrate into ions.

  • Strong Acids (examples):

* HCl → H⁺ + Cl⁻
* HNO₃ → H⁺ + NO₃⁻
* H₂SO₄ (first proton only) → H⁺ + HSO₄⁻

 In water:

* All acid molecules give up protons (H⁺).
* No original acid molecules are left.
* The solution is highly conductive (lots of free ions).
* pH is extremely low (for acids) or extremely high (for bases).

  • Strong Bases (examples):

* NaOH → Na⁺ + OH⁻
* KOH → K⁺ + OH⁻
* Ba(OH)₂ → Ba²⁺ + 2OH⁻

 In water:

* Fully release OH⁻ ions.
* High hydroxide ion concentration.

ii. Weak Acids and Bases:

These only partially dissociate in water. Most of the molecules stay intact.

  • Weak Acids (examples):

* CH₃COOH (acetic acid) ⇌ H⁺ + CH₃COO⁻
* HF (hydrofluoric acid) ⇌ H⁺ + F⁻

 In water:

* Only a small percentage releases H⁺ ions.
* Forms an equilibrium (⇌).
* pH is higher (less acidic) than strong acids of the same concentration.

  • Weak Bases (examples):

* NH₃ (ammonia) + H₂O ⇌ NH₄⁺ + OH⁻
* CH₃NH₂ + H₂O ⇌ CH₃NH₃⁺ + OH⁻

 In water:

* Few molecules only accept protons to become OH⁻.
* Also establishes equilibrium.

2. Titration Process:

i. Titration: What It Is:

Titration is a laboratory method of finding the concentration of an unknown solution (the analyte) by reacting it with a solution of known concentration (the titrant).

Key Terms:

TermDefinition
TitrantThe known solution added from a burette (usually an acid or base).
AnalyteThe unknown solution being analyzed.
Equivalence PointThe point where moles of titrant = moles of analyte (neutralization).
End PointThe point where the indicator changes color, signaling the equivalence point (ideally very close).
IndicatorA dye (e.g., phenolphthalein) that changes color at or near the equivalence point.

ii. How Titration Works – Step-by-Step:

 1. Prepare your solutions

* Titrant (known concentration) into the burette.
* Analyte (concentration is unknown) goes into a flask, usually a couple of drops of indicator.

 2. Slowly add titrant:

* Apply the burette to add titrant to the analyte slowly.
* Stir the flask repeatedly so that solutions become mixed.

3. Look out for the end point

* While you slowly add the titrant, the indicator will change color.
* Stop adding when a permanent color change is achieved — this is the end point.

 4. Determine the unknown concentration

* Apply the volume of titrant added and a balanced chemical equation to determine the moles of analyte, then compute its concentration.

iii.  Titration Equation:

M₁V₁ = M₂V₂ (for monoprotic acid/base reactions)

Where:

* M₁, V₁ = molarity and volume of the acid
* M₂, V₂ = molarity and volume of the base

For polyprotic acids or more complicated reactions, apply stoichiometry using a balanced equation.

3.  Titration Curve Interpretation:

i. A titration curve is a plot of pH (y-axis) against volume of titrant added (x-axis).

The form of the curve will be determined by the strength of the acid and base used.

ii. Key Parts of the Curve:

 1. Initial pH (Starting Point):

* This is the pH prior to any addition of titrant.
* Varies with the strength of the analyte:

* Strong acid (e.g., HCl): extremely low pH (~1).
* Weak acid (e.g., CH₃COOH): higher pH (~3–4).
* Strong base: extremely high pH (~13–14).
* Weak base: lower (~9–10).

2. Gradual Rise or Fall:

* When you add titrant, the pH begins to change slowly.
* This area indicates the buffering capacity, particularly in weak acid/base titrations.

3. Steep Rise (or Fall):

* Abrupt, sharp pH change over a small volume.
* This is where the base and acid are quickly neutralizing one another.
* Happens close to the equivalence point.

 4. Equivalence Point:

* Moles of titrant = moles of analyte.
* The solution is neutralized.
* The pH at equivalence varies depending on the type of titration:

Titration TypepH at Equivalence
Strong acid + strong base~7 (neutral)
Weak acid + strong base>7 (slightly basic)
Strong acid + weak base<7 (slightly acidic)

 5. Beyond the Equivalence Point:

* Introducing more titrant overwhelms the analyte.
* pH reaches a plateau and indicates the type of the excess titrant:

* If titrant is a base → pH jumps high and becomes level.
* If titrant is an acid → pH drops low and becomes level.

8.5.A.2  Equivalence Point and Analyte Concentration:

1. Acid-Base Neutralization and Mole Concept:

i. Acid-Base Neutralization Reaction:

Neutralization is the reaction between an acid and a base to produce water and a salt:

ii. General Reaction (Monoprotic Case):Acid (H⁺ donor)+Base (OH⁻ donor)Salt+Water\text{Acid (H⁺ donor)} + \text{Base (OH⁻ donor)} → \text{Salt} + \text{Water}

Example:HCl+NaOHNaCl+H₂O\text{HCl} + \text{NaOH} → \text{NaCl} + \text{H₂O}

ii. Mole Concept in 1:1 Neutralization:

For monoprotic acids (donate one H⁺) and monobasic bases (donate one OH⁻), neutralization is a 1:1 mole ratio.

That is:

* 1 mole of H⁺ from the acid combines with 1 mole of OH⁻ from the base.
* Neutralization is complete when:moles of acid (H⁺)=moles of base (OH⁻)\text{moles of acid (H⁺)} = \text{moles of base (OH⁻)}

2. Titration Calculations:

Apply the formula:

M1 V1 = M2 V2

Where:

* M1 = molarity of acid
* V1 = volume of acid
* M2 = molarity of base
* V2 = volume of base

> Applies to 1:1 mole ratio titrations (e.g., monoprotic acids and monobasic bases)

8.5.A.3  Half-Equivalence Point and pKa Determination:

1. Conjugate Acid-Base Pair:

During an acid-base reaction, when a weak acid (such as HA) loses a proton (H⁺), it becomes its conjugate base (A⁻). This is because acids are proton donors.

Example:
HA ⇌ H⁺ + A⁻

Here:

* HA is the weak acid.
* A⁻ is the conjugate base, which is formed after HA loses a proton.

In reverse, A⁻ may take up a proton to form HA once again, thus a base in the conjugate pair.

This acid-base conjugate pair (HA and A⁻) are connected as they only vary by one proton (H⁺). This is fundamental when interpreting buffer systems and titration curves, particularly at the half-equivalence point, where [HA] = [A⁻].

2. Henderson-Hasselbalch Equation:pH=pKa+log([A][HA])

* pH: Solution pH
* pKa: Acid dissociation constant
* [A⁻]: Concentration of the conjugate base
* [HA]: Concentration of weak acid

Key Point:

At the half-equivalence point (where

[A]=[HA][A^-] = [HA]

), pH = pKa, allowing you to determine the pKa of a weak acid.

3. Half-Equivalence Point:

At the half-equivalence point, half of the weak acid (HA) has been transformed into its conjugate base (A⁻), so:

[HA]=[A]

This reduces the Henderson-Hasselbalch equation to:pH=pKa

So, at this point, the pH is equal to the pKa of the acid, and the pKa can be directly calculated from the measured pH.

4. Why It Matters:

By measuring the pH at the half-equivalence point in a titration, you can determine the pKa (and therefore Ka) of a weak acid. This is because, at this point, pH = pKa, providing a direct method for experimentally determining the acid’s dissociation constant.

8.5.A.5  Titration of Polyprotic Acids and pKa Determination:

1. Polyprotic Acids and Their Protons:

Polyprotic acids are able to donate multiple protons and experience sequential ionization steps, each with its own dissociation constant Ka.

i. Ionization Steps:

a. First ionization is stronger, with a larger Ka1

Example:

H2SO4H++HSO4\text{H}_2\text{SO}_4 \to \text{H}^+ + \text{HSO}_4^-

(complete dissociation)

b. Second ionization is weaker, with a smaller Ka2.

Example:

HSO4H++SO42\text{HSO}_4^- \to \text{H}^+ + \text{SO}_4^{2-}

(partial dissociation)

ii. Ka and pKa:

  • pKa1<pKa2<pKa3

2. Species at Different Points:

i. Before Equivalence (Initial Point):

* Weak acid titrated with strong base:

* Mostly acid (HA): Weak acid in excess.
* Conjugate base (A⁻): Being formed in minute quantities.
* H⁺ ions: In lower concentration as the acid is dissociating.
* Strong acid titrated with strong base:

* Predominantly H⁺ (from acid).
* OH⁻ ions: Added as the base is being titrated.

ii. At Half-Equivalence Point (Buffer Region)

* Weak acid titrated with strong base:

* [HA] = [A⁻]: Equivalents concentrations of the acid and its conjugate base.
* pH = pKa at this point.

* Strong acid titrated with strong base:

* Near neutral: Most of the acid has reacted and approximately equal volumes of acid and base remain.

iii. At Equivalence Point:

* Weak acid titrated with strong base:

* Conjugate base (A⁻) is in excess (because it arises from acid neutralization).
* Water and salt: The resultant salt (e.g., NaA) might hydrolyze, so the solution becomes somewhat basic (pH > 7).

* Strong acid titrated with strong base:

* Water and salt: The solution is neutral (pH = 7), since acid and base completely neutralize.

iv. Beyond Equivalence (Excess Titrant):

* Weak acid titrated with strong base:

* Excess base (OH⁻) is in excess, raising the pH.
* Strong acid titrated with strong base:

* Excess OH⁻: Adding more base drives the pH up.

8.5.A.4  Equivalence Point and pH in Titrations:

1. Strong vs. Weak Acid/Base Titrations:

Titration TypepH at EquivalenceWhy
Strong Acid + Strong BasepH = 7Neutral solution due to complete dissociation.
Weak Acid + Strong BasepH > 7 (basic)Conjugate base of weak acid hydrolyzes to form OH⁻.
Strong Acid + Weak BasepH < 7 (acidic)Conjugate acid of weak base hydrolyzes to form H⁺.

2. Conjugate Base/Acid Behavior:

i. Conjugate Base/Acid Behavior – Hydrolysis:

When an acid or base dissociates, it produces a conjugate species, which can react with water (hydrolyze) to either release H⁺ ions (creating an acidic solution) or accept H⁺ ions (creating a basic solution). This comes into play when thinking about the pH at the equivalence point in a titration.

ii. Conjugate Base (from Weak Acid):

* When a weak acid (e.g., acetic acid, CH₃COOH) is titrated with a strong base, the formed conjugate base (A⁻) will react with water:

A+H2OHA+OH\text{A}⁻ + \text{H}_2\text{O} \rightleftharpoons \text{HA} + \text{OH}⁻

* Conjugate base (A⁻) accepts H⁺ ions from water, forming OH⁻ ions, thereby making the solution basic.
* Result: pH at equivalence is greater than 7.

Example:
In the titration of acetic acid (CH₃COOH) with sodium hydroxide (NaOH), the acetate ion (CH₃COO⁻) is the conjugate base and will increase the pH.

iii. Conjugate Acid (from Weak Base)

* When a weak base (e.g., ammonia, NH₃) is titrated with a strong acid, the conjugate acid (e.g., NH₄⁺) produced can react with water:

NH4++H2ONH3+H3O+\text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+

* The conjugate acid (NH₄⁺) donates H⁺ ions to water, hence the solution acidic.
* Result: pH at equivalence is less than 7.

Example:
In ammonia (NH₃) titration with hydrochloric acid (HCl), the ammonium ion (NH₄⁺) is the conjugate acid and will decrease the pH.

Scroll to Top