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AP Physics 1- 2.3 Newton’s Third Law- Study Notes- New Syllabus

AP Physics 1-2.3 Newton’s Third Law – Study Notes

AP Physics 1-2.3 Newton’s Third Law – Study Notes -AP Physics 1 – per latest Syllabus.

Key Concepts:

  • Interaction of Two Objects – Newton’s Third Law

AP Physics 1-Concise Summary Notes- All Topics

Interaction of Two Objects – Newton’s Third Law

Newton’s Third Law states: For every action, there is an equal and opposite reaction. When two objects interact, they exert forces on each other that are:

  • Equal in magnitude
  • Opposite in direction
  • Act on different objects

Representation of Paired Forces:

  • If Object A exerts a force \( F_{AB} \) on Object B, then Object B exerts a force \( F_{BA} \) on Object A.
  • These forces form an action–reaction pair:

     

\( F_{AB} = -F_{BA} \)

Important Note:

The action and reaction forces do not cancel each other because they act on different objects.

Example 1: Pushing a Wall

A person pushes a wall with force 100 N. The wall pushes back on the person with 100 N in the opposite direction. Even though the wall doesn’t move, the reaction force exists and balances the push on the person.

Example 2: Book on a Table

The book exerts a downward force (weight) on the table: \( F_{bt} = mg \).

The table exerts an upward normal force on the book: \( F_{tb} = -mg \).

These two forces are an action–reaction pair.

Example 3: Rocket Propulsion

The rocket expels gas backward with a force \( F_{rg} \). The gas pushes the rocket forward with equal and opposite force \( F_{gr} \).

This reaction is what propels rockets in space.

Example :

A 2 kg block rests on a horizontal table. The block exerts a force on the table due to its weight. Find:

  1. The force exerted by the block on the table.
  2. The force exerted by the table on the block.
▶️ Answer/Explanation

1. Weight of block (force on table): \( F_{bt} = m g = 2 \times 9.8 = 19.6 \, \text{N} \) (downward).

2. By Newton’s Third Law, the table exerts an equal and opposite normal force on the block: \( F_{tb} = 19.6 \, \text{N} \) (upward).

Answer: – Block on table: 19.6 N downward – Table on block: 19.6 N upward These two forces are an action–reaction pair.

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