AP Physics 1- 5.2 Connecting Linear and Rotational Motion- Study Notes- New Syllabus
AP Physics 1-5.2 Connecting Linear and Rotational Motion – Study Notes
AP Physics 1-5.2 Connecting Linear and Rotational Motion – Study Notes -AP Physics 1 – per latest Syllabus.
Key Concepts:
- Connecting Linear and Rotational Motion
Connecting Linear and Rotational Motion
Linear and rotational motions are closely related. For a point on the rim of a rotating body (radius \( r \)), linear quantities can be expressed in terms of angular quantities.
Angular Quantities for a Rigid System
For a rigid system, all points have the same angular displacement, angular velocity, and angular acceleration, regardless of their distance from the axis of rotation.![]()
However, their linear velocities and linear accelerations depend on their distance \( r \) from the axis.
Displacement
The arc length \( s \) traveled by a point on the rim of a rotating object is related to angular displacement \( \theta \) by:
\( s = r \theta \)
Units: meters (m).
Velocity
The linear velocity \( v \) of a point on the rim is proportional to angular velocity \( \omega \):
\( v = r \omega \)
Direction of \( v \): Tangent to the circular path (perpendicular to the radius).
Acceleration
There are two components of linear acceleration for a rotating body:![]()
- Tangential acceleration: \( a_t = r \alpha \) (due to angular acceleration).
- Centripetal acceleration: \( a_c = \dfrac{v^2}{r} = r \omega^2 \) (directed toward the center of rotation).
Kinematic Analogies
The equations of rotational motion mirror those of linear motion:
![]()
- Linear: \( v = v_0 + a t \) ↔ Rotational: \( \omega = \omega_0 + \alpha t \)
- Linear: \( s = v_0 t + \dfrac{1}{2} a t^2 \) ↔ Rotational: \( \theta = \omega_0 t + \dfrac{1}{2} \alpha t^2 \)
- Linear: \( v^2 = v_0^2 + 2 a s \) ↔ Rotational: \( \omega^2 = \omega_0^2 + 2 \alpha \theta \)
Example:
A wheel of radius \( r = 0.5 \, \text{m} \) rotates at \( \omega = 8 \, \text{rad/s} \).
Find (i) the linear speed of a point on the rim, and (ii) its centripetal acceleration.
▶️Answer/Explanation
(i) Linear speed:
\( v = r \omega = 0.5 \times 8 = 4 \, \text{m/s} \)
(ii) Centripetal acceleration:
\( a_c = r \omega^2 = 0.5 \times (8^2) = 32 \, \text{m/s}^2 \)
Answer: \( v = 4 \, \text{m/s}, \, a_c = 32 \, \text{m/s}^2 \)
Example :
A wheel of radius \( 0.4 \, \text{m} \) rotates with angular velocity \( \omega = 10 \, \text{rad/s} \). Find the linear speed of a point on its rim.
▶️Answer/Explanation
\( v = r \omega = 0.4 \times 10 = 4 \, \text{m/s} \)
Answer: \( v = 4 \, \text{m/s} \)
Example :
A grinding wheel accelerates from rest with angular acceleration \( \alpha = 5 \, \text{rad/s}^2 \). If its radius is \( 0.2 \, \text{m} \), find the linear acceleration of a point on the rim.
▶️Answer/Explanation
\( a = r \alpha = 0.2 \times 5 = 1 \, \text{m/s}^2 \)
Answer: \( a = 1 \, \text{m/s}^2 \)
