AP Physics 1- 5.2 Connecting Linear and Rotational Motion- Study Notes- New Syllabus
AP Physics 1-5.2 Connecting Linear and Rotational Motion – Study Notes
AP Physics 1-5.2 Connecting Linear and Rotational Motion – Study Notes -AP Physics 1 – per latest Syllabus.
Key Concepts:
- Connecting Linear and Rotational Motion
Connecting Linear and Rotational Motion
Linear and rotational motions are closely related. For a point on the rim of a rotating body (radius \( r \)), linear quantities can be expressed in terms of angular quantities.
Angular Quantities for a Rigid System
For a rigid system, all points have the same angular displacement, angular velocity, and angular acceleration, regardless of their distance from the axis of rotation.
However, their linear velocities and linear accelerations depend on their distance \( r \) from the axis.
Displacement
The arc length \( s \) traveled by a point on the rim of a rotating object is related to angular displacement \( \theta \) by:
\( s = r \theta \)
Units: meters (m).
Velocity
The linear velocity \( v \) of a point on the rim is proportional to angular velocity \( \omega \):
\( v = r \omega \)
Direction of \( v \): Tangent to the circular path (perpendicular to the radius).
Acceleration
There are two components of linear acceleration for a rotating body:
- Tangential acceleration: \( a_t = r \alpha \) (due to angular acceleration).
- Centripetal acceleration: \( a_c = \dfrac{v^2}{r} = r \omega^2 \) (directed toward the center of rotation).
Kinematic Analogies
The equations of rotational motion mirror those of linear motion:
- Linear: \( v = v_0 + a t \) ↔ Rotational: \( \omega = \omega_0 + \alpha t \)
- Linear: \( s = v_0 t + \dfrac{1}{2} a t^2 \) ↔ Rotational: \( \theta = \omega_0 t + \dfrac{1}{2} \alpha t^2 \)
- Linear: \( v^2 = v_0^2 + 2 a s \) ↔ Rotational: \( \omega^2 = \omega_0^2 + 2 \alpha \theta \)
Example:
A wheel of radius \( r = 0.5 \, \text{m} \) rotates at \( \omega = 8 \, \text{rad/s} \).
Find (i) the linear speed of a point on the rim, and (ii) its centripetal acceleration.
▶️Answer/Explanation
(i) Linear speed:
\( v = r \omega = 0.5 \times 8 = 4 \, \text{m/s} \)
(ii) Centripetal acceleration:
\( a_c = r \omega^2 = 0.5 \times (8^2) = 32 \, \text{m/s}^2 \)
Answer: \( v = 4 \, \text{m/s}, \, a_c = 32 \, \text{m/s}^2 \)
Example :
A wheel of radius \( 0.4 \, \text{m} \) rotates with angular velocity \( \omega = 10 \, \text{rad/s} \). Find the linear speed of a point on its rim.
▶️Answer/Explanation
\( v = r \omega = 0.4 \times 10 = 4 \, \text{m/s} \)
Answer: \( v = 4 \, \text{m/s} \)
Example :
A grinding wheel accelerates from rest with angular acceleration \( \alpha = 5 \, \text{rad/s}^2 \). If its radius is \( 0.2 \, \text{m} \), find the linear acceleration of a point on the rim.
▶️Answer/Explanation
\( a = r \alpha = 0.2 \times 5 = 1 \, \text{m/s}^2 \)
Answer: \( a = 1 \, \text{m/s}^2 \)