Conservation of Angular Momentum AP Physics 1 FRQ – Exam Style Questions etc.
Conservation of Angular Momentum AP Physics 1 FRQ
Unit 6: Energy and Momentum of Rotating Systems
Weightage : 10-15%
Exam Style Practice Questions, Conservation of Angular Momentum AP Physics 1 FRQ
Question
Some physics students build a catapult, as shown above. The supporting platform is fixed firmly to the ground. The projectile, of mass 10 kg, is placed in cup A at one end of the rotating arm. A counterweight
bucket B that is to be loaded with various masses greater than 10 kg is located at the other end of the arm. The arm is released from the horizontal position, shown in Figure 1, and begins rotating. There is a mechanism (not shown) that stops the arm in the vertical position, allowing the projectile to be launched with a horizontal velocity as shown in Figure 2.
a. The students load five different masses in the counterweight bucket, release the catapult, and measure the resulting distance x traveled by the 10 kg projectile, recording the following data.
| Mass (kg) | 100 | 300 | 500 | 700 | 900 |
| x (m) | 18 | 37 | 45 | 48 | 51 |
i. The data are plotted on the axes below. Sketch a best-fit curve for these data points.
ii. Using your best-fit curve, determine the distance x traveled by the projectile if 250 kg is placed in the counterweight bucket.
b. The students assume that the mass of the rotating arm, the cup, and the counterweight bucket can be neglected. With this assumption, they develop a theoretical model for x as a function of the counterweight mass using the relationship x = vxt, where v, is the horizontal velocity of the projectile as it leaves the cup and t is the time after launch.
i. How many seconds after leaving the cup will the projectile strike the ground?
ii. Derive the equation that describes the gravitational potential energy of the system relative to the ground when in the position shown in Figure 1, assuming the mass in the counterweight bucket is M. iii. Derive the equation for the velocity of the projectile as it leaves the cup, as shown in Figure 2.
c. i. Complete the theoretical model by writing the relationship for x as a function of the counterweight mass using the results from b. i and b. iii.
ii. Compare the experimental and theoretical values of x for a counterweight bucket mass of 300 kg. Offer a reason for any difference.
Answer/Explanation
Ans:
a. i. 
ii. x = 33 m
b. i. y = ½ gt2; t = (2y/g)1/2 = 1.75 s
ii. Uinitial = Ubucket + Uprojectile = M(9.8 m/s2)(3 m) + (10 kg)(9.8 m/s2)(3 m) = 29.4M + 294
iii. Uinitial = Ufinal + K where Ufinal = Mg(1 m) + (10 kg)g(15 m) = 9.8M + 1470
Kprojectile = ½ 10vx2 and Kbucket = ½ Mvb2 where vb = vx/6
putting it all together gives 29.4M + 294 = 9.8M + 1470 + 5vx2 + (M/72)vx2
vx = \(|\frac{\overline{19.6M – 1176}}{5 + M/72}\)
c. i. x = vxt
x = 1.75 \(|\frac{\overline{19.6M – 1176}}{5 + M/72}\)
d. x(300 kg) = 39.7 m (greater than the experimental value)
possible reasons include friction at the pivot, air resistance, neglected masses not negligible