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Rotational Equilibrium and Newton’s First Law in Rotational Form AP  Physics 1 FRQ

Rotational Equilibrium and Newton’s First Law in Rotational Form AP  Physics 1 FRQ – Exam Style Questions etc.

Rotational Equilibrium and Newton’s First Law in Rotational Form AP  Physics 1 FRQ

Unit 5: Torque and Rotational Dynamics

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AP Physics 1 Exam Style Questions – All Topics

Exam Style Practice Questions, Rotational Equilibrium and Newton's First Law in Rotational Form AP  Physics 1 FRQ

Question

A l.0-kilogram object is moving horizontally with a velocity of 10 meters per second, as shown above, when it makes a glancing collision with the lower end of a bar that was hanging vertically at rest before the
collision. For the system consisting of the object and bar, linear momentum is not conserved in this collision, but kinetic energy is conserved. The bar, which has a length l of 1.2 meters and a mass m of 3.0 kilograms, is pivoted about the upper end. Immediately after the collision the object moves with speed v at an angle θ relative to its original direction. The bar swings freely, and after the collision reaches a maximum angle of 90° with respect to the vertical. The moment of inertia of the bar about the pivot is Ibar = ml²/3 Ignore all friction.
a. Determine the angular velocity of the bar immediately after the collision.
b. Determine the speed v of the l-kilogram object immediately after the collision.
c. Determine the magnitude of the angular momentum of the object about the pivot just before the collision.
d. Determine the angle θ.

Answer/Explanation

Ans:

a. K = U
    ½ Iω2 = mghcm
    ½ (ml2/3)ω2 = mg(l/2) which gives ω = 5 rad/s
b. Ki = Kf
    ½ m0v02 = ½ m0v2 + ½ Iω2
    v = 8 m/s
c. L = mvr = (1 kg)(10 m/s)(1.2 m) = 12 kg-m2/s
d. Li = Lf
     12 kg-m2/s = m0(v⊥)l + Iω = m0(v cos θ)l + I ω
    θ = 60º

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