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Simple Circuits AP Physics 2 MCQ

Simple Circuits  AP  Physics 2 MCQ – Exam Style Questions etc.

Simple Circuits  AP  Physics 2 MCQ

Unit 11: Electric Circuits

Weightage : 15–18%

AP Physics 2 Exam Style Questions – All Topics

Exam Style Practice Questions , Simple Circuits AP  Physics 2 MCQ

QUESTIONS (A)–(C) ARE BASED ON THE FOLLOWING CIRCUIT:

Question(A)

 What is the equivalent resistance of the circuit?
         (A) 6 Ω
         (B) 8 Ω
         (C) 11 Ω
         (D) 5 Ω

▶️Answer/Explanation

Ans:(D)

The two 2 Ω resistors are in series with each other: 2 Ω + 2 Ω = 4 Ω. This 4 Ω equivalent resistance is in parallel with the existing 4 Ω resistor:  ¼ Ω + ¼ Ω = ½ Ω. So the equivalent resistance for that section of the circuit is 2 Ω. This 2 Ω equivalent resistance is in series with the 3 Ω resistor:  2 Ω + 3 Ω = 5 Ω.

Question(B)

What is the reading of the voltmeter across the 4-ohm resistor?
        (A) 3 V
        (B) 9 V
        (C) 12 V
        (D) 6 V

▶️Answer/Explanation

Ans:(D) The 15 volts must be split between the 3-ohm resistor and the 2-ohm equivalent resistance of the right-hand side (see answer 23). Voltage for the 4-ohm              resistor is the same as the voltage across the 2-ohm equivalent resistance of the right-hand side:
                                                                                                                       V = (2/5)(15 V) = 6 V

Question(C)

What is the current through the leftmost 2-ohm resistor?
        (A) 3 A
        (B) 1.5 A
        (C) 0.75 A
        (D) 1 A

▶️Answer/Explanation

Ans:(B) The 15-volt battery will supply 3 amps of current for the 5-ohm circuit:
                                                                               V = IR
                                                                        15 V = (3A)(5 ohm)
         This 3-amp current will split as it comes to the branching point before the 4-ohm resistor. Since both pathways have equal resistance (4 ohms),   the current will split evenly: 1.5 amps.

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